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Chemistry >> General Chemistry >> Mole Concept and Stoicheometry Medical Exam

the normality of 10% (w/v) acetic acid is ?

1.7N

Asked By: SARIKA SHARMA
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Joshi sir comment

10 % w/v acetic acid means 10 gm. in 100 ml. soln.

so 1000 ml soln. contains 100 gm acetic acid

so 1 litre contains 100/60 moles of acetic acid

so M = 100/60 = 1.67

so N = M * basicity = 1.67*1 = 1.67 

Chemistry >> General Chemistry >> Atoms and molecules Medical Exam

the ques which i have already submitted i.e. d ques in which we have to find min transitional energy in terms ofRH , IS THE ANS IS RH. PLS AGAIN TELL THAT SOLn so that i can understand more easily

Asked By: SARIKA SHARMA
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Joshi sir comment

for max transitional energy we will use 

E = hcRH {1/12  - 1/∞2}

so E will be proportional to RH

Chemistry >> General Chemistry >> Redox Reactions and n factor Medical Exam

oxide of E react with KOH & give compd like KMnO4 WHAT IS THE FORMULA OF OXIDE OF E

EO

E2O3

E2O7      OR ANY OTHER ANS (& IF ANY OTHER ONE THEN GIVE THAT ANS WITH SOLn)

 

Asked By: SARIKA SHARMA
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Joshi sir comment

 

2 EO2 + 4 KOH + O2 → 2 K2EO4 + 2 H2O
and
3 K2EO4 + 2 CO2 → 2 KEO4 + 2 K2CO3 + EO2
 
so oxide will be EO2
 
 
 
Chemistry >> General Chemistry >> Mole Concept and Stoicheometry Medical Exam

Q ONE LITRE MIXTURE OF CO &CO2 IS PASSED THRU RED HOT CHARCOAL IN A TUBE THE NEW VOL . BECOMES 1.2L WHAT % OF CO IN MIXTURE INITIALLY?

Q AN Aq SOLn CONTAINING 100 g OF DISSOLVED MgSO4 IS FED TO A CRYSTALLIZER WHERE 80% SALT CRY. OUT AS MgSO4.6H2O CRYSTAL HOW MANY gm OF HEXAHYDRATE SALT CRY. ARE OBTAINED FROM CRYSTALLIZER=?

ELECTROCHEM

Fe3+  +  e- -----> Fe2+ = 0.77V

Fe --------.>  Fe3+  + 3e-     E = +0.04V

WHAT IS VALUE OF E* for Fe2+  +2e--------> Fe ? 

Asked By: SARIKA
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Joshi sir comment

CO2 + C (charcoal) ------->  2CO

let us consider that initially volume of CO2 is x litre and that of  CO is (1-x) litre

so after the above written process net CO in final = 2x+1-x = 1.2      given 

on solving x = 0.2 and 1-x = 0.8   now calculate %

 

MgSO4  -------------->   MgSO4 .6H2O

it means 120 gm (mw of compound) gives 228 gm MgSO4 . 6H2O 

so 80 gm will give 228*80/120     solve it

here 80 is used for 80% of 100 gm.

 

 

Fe+++  +  e-  ----->  Fe++                  E=  +0.77 V

Fe                ----->  Fe+++  + 3e-       E = +0.04 V

 

on adding we get

Fe                ----->  Fe++  + 2e-         

so E for the new reaction = [1F(0.77) + 3F(0.04)]/2F = 0.89/2 = 0.445

Chemistry >> General Chemistry >> Mole Concept and Stoicheometry IIT JEE

A decapeptide (Mol.wt 796) on complete hydrolysis gives glycine(Mol.wt 75) , alanine and phenylalanine.  Glycine contributes 47 % to the total weight  of the hydrolysed products . The number of glycine units present in the decapeptide is

Asked By: NITIN RAO
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Joshi sir comment

47 % of (796+162) = 958*47/100 = 450 approx

so no of glycene units = 450/75 = 6 approx

here 162 is taken for the weight of 9 water molecules required for breaking the decapeptides.

Chemistry >> General Chemistry >> Mole Concept and Stoicheometry IIT JEE

A compound contains 3.2% of oxygen . the minimum molecular weight of the compound is ?

Asked By: AMIT DAS
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Joshi sir comment

atomic wt. of oxygen = 16

so m.w./100 = 16/3.2 or m.w. = 500

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