Question

A body is projected with a velocity 'u' making an angle α with the horizontal. Its velocity when it is perpendicular to the initial velocity vector is:

A. ucotα B. utanα C. usinα D. ucosα

 

Joshi sir comment

component of gravity perpendicular to the final direction is gsinθ so by equation

v=u+at 

0 = u -gsinθt 

so t = u/gsinθ

now along final direction v = 0+gcosθt             on putting the value of t we get v = gcosθu/gsinθ = ucotθ

Read 1 Solution.

ans  ucot@  ,

ARECA NUT 10 year ago is this solution helpfull: 1 2

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