Question
what is the ph of the solution formed by mixing 20 ml of 0.05 M H2SO4 with 5 ml of 0.45 M NaOH at 298 k ?
Joshi sir comment
mili eq of acid = VN = 20*0.1 = 2
mili eq of base = VN = 5*0.45 = 2.25
total milieq = 2.25-2 = 0.25 of base in 25 ml
so N = 0.25/25 = 10-2
so pOH = 2 so pH = 12