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Question

when 20 g of caco3 were put into 10 litre flask and heated to 800 degree cesius, 30% of caco3 remained unreacted at equilibrium. kp for decomposition of caco3 will be 1.231 ATM HOWWWW............PLS SOLVE THIS ....PLS PLS..........

Joshi sir comment

CaCO₃ ----------> CaO + CO₂(g)

0.2 mole 0 0

0.06 0.14 0.14

so K_p= p only CO₂ is gas so its pressure is considered

now p = 0.14*0.0821*1073/10

now solve

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