Question
a bullet is fired from gun .the force on the bullet is given by F=600-2*105 t, where F is in newton and t is in sec. the force on the bullet becomes zero as soon as it leaves the barrel.what impulse imparted to the bullet
ans-0.9Ns
Read 1 Solution.
impulse = dp= ∫fdt
f= 600-2x105t
4 getting impulse integrate force
i= ∫Fdt= 600t- 2x105t2/2 = 600t- 105t2 (a)
now find t=?? by putting force=zero u vyl get t= 3x10-3( 600-2x105t=o => t=3x10-3)
now 4 impulse put d value of time in eqn (a) u will get impulse = 0.9Ns
SARIKA SHARMA 11 year ago
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