Question

a bullet is fired from gun .the force on the bullet is given by F=600-2*105 t, where F is in newton and t is in sec. the force on the bullet becomes zero as soon as it leaves the barrel.what impulse imparted to the bullet

ans-0.9Ns

Read 1 Solution.

impulse = dp= ∫fdt

f= 600-2x105t

4 getting impulse integrate force

i= ∫Fdt=  600t-  2x105t2/2 = 600t- 105t2  (a)

now find t=??  by putting force=zero  u vyl get t= 3x10-3( 600-2x105t=o => t=3x10-3)

now 4 impulse put  d value of time in eqn (a)  u will get impulse = 0.9Ns

SARIKA SHARMA 11 year ago is this solution helpfull: 67 21

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