Question
consider a system of two particles having masses m1 and m2. if the particle of mass m1 is pushed towards m2 through a distance d, by what distance should be particle of mass m2 be moved so as to keep the centre of mass of the system of particle at the original position?
ans-m1d/m1+m2
Read 1 Solution.
let distance of one particle
wrt ground = x
for other wrt ground = -(d-x)
centre of mass = o
m1 x - m2 (d-x) = 0
x (m1 +m2) = m2 d => x = m2d /(m1+m2) this for first particle
similarily for m2 it will be (x) = m1d/ (m1+m2)
SARIKA 11 year ago
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