Question
A particle has an initial velocity of 9m/s due east and a constant acceleration of 2m/s2 due west. What isthe distance covered by the particle in the 5 th second of its motion ?
Read 1 Solution.
use Snth = u- [a(2n-1)/2] -ve becoz opposite they are moving u=9, a=2, n=5
SARIKA 11 year ago
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