Question
A block of mass m is at rest on a rough inclined plane of angle of inclination θ . If coefficient of friction between the block and the inclined plane is μ, then the minimum value of force along the plane required to move the block on the plane is mg [sin θ- μ cos θ ] . How?
Read 2 Solution.
FORCE REQ = F which is acting along the direction of mgsinθ and friction f is acting in opposite direction
F = mgsinθ - f = mgsinθ - µ mgcosθ = mg ( sinθ - µcosθ)
Best SolutionSARIKA 11 year ago
is this solution helpfull: 32 72
required force F will act along Fs (force due to static friction) and in opposite direction will be mgsinθ
"along the plane" means the block is moving upwards
"down the plane" mean the block is moving downwards
so for upwards
F=Fs-mgsinθ = μmgcosθ-mgsinθ=mg(μcosθ-sinθ)
SMART AKASH MISHRA 6 year ago
is this solution helpfull: 67 45