Question
Three forces F1 = ( 2i+ 4j ) N ; F2 = ( 2j-k ) N and F3 = (k - 4i - 2j ) N are applied on an object of mass 1 kg at rest at origin. The position of the object at t=2s will be
1. (-2m, -6m) 2. (-4m , 8m)
Read 1 Solution.
Find resultant of F u will be left with -2i +4j then +divide it by mass to get acceleration
now on integrating wrt dt u will get velocity = -2t , 4t
again integrate wrt dt to get position & WE WILL get = -2t2/2 ,4t2/2 = -4, 8 m (ANS) ( on putting t=2sec)
Best SolutionSARIKA SHARMA 11 year ago
is this solution helpfull: 81 58