Question
A uniform electric field is established by connecting the plates of a parallel plate capacitor to a 12v battery. A charge particle of +6.24x10 to the power -6c moves from rest from the positive plate to the negative plate. when the charge reaches the negative plate,it acquires a speed of 3.4m/s.what is{a} the mass of the charge particle and{b} its final kinectic energy?
Joshi sir comment
energy gained by the particle between the plates of the capacitor = qV
this will provide K.E. to the particle so qV = 1/2 mv2
solve for mass
then for K.E.
Read 1 Solution.
7.5 e
ke = 5
GIRISH 1 year ago
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