Question
A PARTICLE OF MASS m IS MADE TO MOVE WITH UNIFORM SPEEDv ALONG PERIMETER OF A REGULAR HEXAGON
. MAGNITUDE OF IMPULSE APPLIED AT EACH CORNER OF HEXAGON IS
A)mv
b)mv31/2
c)mv/2
d)zero
Read 1 Solution.
as in regular hexagon angle between two sides is 120. now resolve mv in mv cos60 and mv sin60
change in momentum =2mv cos60 =mv
as mv sin60 is in same direction so there will be no change in momentum for mvsin60 but mv cos60 are in opposite direction.
so impulse= mvcos60- (-mvcos60)=2mvcos60.
not possible to make digram .so plese make by urself to understand it nicely.
Best SolutionNIKHIL VARSHNEY 12 year ago
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