Question
a body is projected with a velocity 3i +4j m/s . what is maximum height attained by the ball.
Read 1 Solution.
Suppose particle makes angle a with d hrizntal.... So vcosa= 3, say eq. 1 vsina= 4, say eq 2 squaring nd adding both the equations...... We get v²= 25..... V=5m/s.
Putting value of v in eq1 nd eq2 we get... Sina= 4/5 nd cosa= 3/5..... Nw max. Height attained
= v²sin²a/ 2g.... All value r knw.... Put nd get ur answer.........
AMAN JAISWAL 8 year ago
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