Question
a car travelling at 20m/s due north along the highway makes a right turn on to a side road that heads due east.It takes 50seconds for the car to complete the turn.At the end of 50 sec car has a speed of 15m/s along the side road.Determine the magnitude of average acceleration over the 50s intervalRead 1 Solution.
The car initially travls at 20 j (m/s).
At the end of 50 seconds the velocity becomes 15 i.
Therefore acceleration along x = 15-0/time = 15/50 = 0.3 i
Acceleration along y = 0-20/time = -20/50= -0.4j
Thus th total acceleration is 0.3i +0.4j.
thus the magnitude is 0.5
SHARAN VENKATESH 8 year ago
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