Question
A 1000 N block is placed on an inclined plane with angle of 30 degree .find the components of the weight i)parallel (ii)perpendicular to the inclined plane
Read 1 Solution.
Component parallel to inclined plane-mgsin30 = 1000/2=500N
Component perpendicular to inclined plane-mgcos30 =1000√3/2=500√3
NEHA GUPTA 9 year ago
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