Question
Six particles situated at the corners of a regular hexagon of side 'a' move at a constant speed 'v'. Each particle maintains a direction towards the particle at the next corner. Calculate the time the particles will take to meet each other ?
Please do answer
Read 2 Solution.
A regular hexagon is composed of 6 equilateral triangles. One side of each triangle forms a chord of the circumscribed circle, while the other two sides are radii of the circle. Each chord therefore intersects the circle at a 30° angle.
The radial component of the speed is given by the sine of the angle times the speed. The sine of 30° is 0.5, so the radial speed is v/2.
The time for the particles to meet is thus 2r/v.
KASHAF AHMED 9 year ago
is this solution helpfull: 2 0
2a/v
MD.YASIR FEROZ KHAN 9 year ago
is this solution helpfull: 1 1