Question

 
Six particles situated at the corners of a regular hexagon of side 'a' move at a constant speed 'v'. Each particle maintains a direction towards the particle at the next corner. Calculate the time the particles will take to meet each other ?
 
 
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A regular hexagon is composed of 6 equilateral triangles.  One side of each triangle forms a chord of the circumscribed circle, while the other two sides are radii of the circle.  Each chord therefore intersects the circle at a 30° angle. 

The radial component of the speed is given by the sine of the angle times the speed.  The sine of 30° is 0.5, so the radial speed is v/2. 

The time for the particles to meet is thus 2r/v.

KASHAF AHMED 9 year ago is this solution helpfull: 2 0

2a/v

MD.YASIR FEROZ KHAN 9 year ago is this solution helpfull: 1 1

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