Question
A particle is executing SHM and its velocity v is related to its position (x) as v2 + ax2 = b, where a and b are positive constants. The frequency of oscillation of particle is
Read 2 Solution.
v2 = b - ax2
v = (b - ax2)1/2
differentiatin both sides w.r.t. t,
accn. = -ax/(b-ax2)1/2
-w2x = -ax/(b-ax2)1/2
w = [ a/(b-ax2)1/2 ]1/2
SANKALP SINGH DEV 10 year ago
is this solution helpfull: 15 117
V2 + ax2 = b
differentiatin both sides w.r.t. x (as this equation is a function of x)
2v dV/dx + 2ax = 0
Vdv/dx = - ax
- w2x = - ax (as vdv/dx = acceleration)
f = √a/2π
PRASENJIT BISWAS 6 year ago
is this solution helpfull: 101 23