Question

A chain of mass m=0.8 kg and length i=1.5m rests on a rough surfaced table so that one of its ends hangs over the edge.The chain starts sliding all by itself provided that the length of the hanging part is n=1/3 of chain length.What will be the total work done by the friction forces acting on the chain by the moment it slides completely off the table?

Read 1 Solution.

 w.d. = mgl / (2n2)    put the value to get ans

SARIKA 10 year ago is this solution helpfull: 6 9

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