Question
A Train Accelerates from rest at a constant rate α for sometime and then it retards to rest at a constant rate β. If te total distance covered by the particle is x, then what is the maximum velocity of the train ?
Joshi sir comment
for first part of motion
v2 = 2αx1 (1)
similarly for second part of motion
v2= 2βx2 (2)
now by given conditions
x = x1 + x2
so x = v2/2α + v2/2β
so x = v2/2[1/α + 1/β]
now solve
Read 2 Solution.
velocity = αβ/ (α+β) t and x = { 1/2 * αβ/ (α+β ) t2} from this eqn of x find value of t and then put in the eqn of velocity to get the ans
SARIKA 10 year ago
is this solution helpfull: 7 2
v=
RAHUL 9 year ago
is this solution helpfull: 2 4