Question

Two rings of same mass and radius R are placed with their planes perpendicular to each other and centres  at a common point. The radius of gyration of the system about an axis passing through the centre and perpendicular to the plane of one ring is

Joshi sir comment

The axis passing through the centre of one ring and perpendicular to the plane will be diametric axis of the other ring 

so moment of inertia about that axis = MR2 + 1/2 MR2 = 3/2 MR2

now compare it to Mk2 and get k, it is radius of gyration

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