Question
A simple pendulum of mass and length L is held in horizontal position. If it is released from this position, then find the angular momentum of the bob about the point of suspension when it is vertically below the point of suspension.
Joshi sir comment
by energy conservation v = √(2gL) below the point of suspension
so angular momentum = mvL about the point of suspension
Read 2 Solution.
L= iω where i is ml^2 / ( 3 ) where l= lenght/2 becoz measure from c.o.m
SARIKA SHARMA 10 year ago
is this solution helpfull: 3 4
The answer is mL√2gL
how???
SWATI KAPOOR 10 year ago
is this solution helpfull: 4 4