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Question

A body of mass m is projected from ground with speed u at an angle θ with the horizontal. The power delivered by gravity to it at half of maximum height from the ground is

Joshi sir comment

at half height, vertical velocity v² = u²sin²θ - 2gH/2, from this equation calculate v

then P = F.v = -mg* vertical component of velocity

this will be instataneous power

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