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Question

a particle starts with a constant tengential acceleration on a circle. the instant when it complete half circle what is the angle between its velocity vector and acceleration vector...???

Joshi sir comment

let tangential acc is a

then velocity after covering half circle

v² = 2a(πr)

so centripetal acc = v²/r = 2aπr/r = 2aπ

so angle = tan^-1[2aπ/a] = tan^-12π

here notice that velocity will be in the direction of tangential acc.

Read 3 Solution.

90 degree

SARIKA 10 year ago is this solution helpfull: 2 1

for speeding up tangential acc will be along velocity vector thus for acc net find by resultant of centripetal and tangential acc for speeding down particle acc tangential will opposite to velocity vector

ignore the first soln as it is for centripetal

SARIKA 10 year ago is this solution helpfull: 2 1

sarika wt u mean .....please tell me right angle.....i can't understand ur explanation....

IMRAN AHMED 10 year ago is this solution helpfull: 0 1

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