Question
0.2 mole of N2 and 0.6 mole of H2 react to give NH3 and 40 % of reactant mixture is decreased , according to the equation,
N2 (g) + 3H2 (g) = 2NH3 (g) at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases is
Joshi sir comment
N2 (g) + 3H2 (g) = 2NH3 (g)
0.2 0.6 0
0.2-x 0.6-3x 2x
according to the given condition 4x = 0.8*40/100 = 0.32
so x = 0.08
now solve