Question
The acceleration of a particle, varies with time according to the relation a=-mw2sinwt.The displacement of this particle at a time t will be
1) m sin(wt)
2) mwcos(wt)
3) mwsin(wt)
4) -1/2(mw2sinwt)t2
Joshi sir comment
a = dv/dt = -mw2sinwt
so ∫dv = ∫-mw2sinwtdt
so v = mwcoswt + C
at t=0, v=0 so 0 = mw+C or C = -mw
so v = -mw(1-coswt)
similarly put v = ds/dt and integrate again