Question
Two particles of masses m and 2m with charges q and 2q are placed in a uniform elecric field E and allowed to move for the same time. The ratio of their kinetic energies will be
a) 2 : 1
b) 1 : 2
c) 4 : 1
d) 1 : 4
Read 1 Solution.
Energy1= 1/2 mv2
= 1/2 m (u +at)2
= 1/2 m a2t2
= 1/2 m (q2E2t2/m2)
= (q2E2t2) / 2m --------------------------------------- (A)
Energy2= 1/2 2mv2
= m (u +at)2
= m a2t2
= m (4q2E2t2/4m2)
= (q2E2t2) / m --------------------------------------- (B)
A : B = 1:2 (b)
Best SolutionSHANTANU BARIAR 10 year ago
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