Question

 

 Two particles of masses m and 2m with charges q and 2q are placed in a uniform elecric field E and allowed to move for the same time. The ratio of their kinetic energies will be

a) 2 : 1
b) 1 : 2
c) 4 : 1
d) 1 : 4

Read 1 Solution.

Energy1=  1/2 mv2

              = 1/2 m (u +at)2

              = 1/2 m a2t2

              = 1/2 m (q2E2t2/m2

            = (q2E2t2) / 2m --------------------------------------- (A)

 

Energy2=  1/2 2mv2

              = m (u +at)2

              = m a2t2

              =  m (4q2E2t2/4m2

            = (q2E2t2) / m --------------------------------------- (B)

 

A : B = 1:2 (b)

Best SolutionSHANTANU BARIAR 10 year ago is this solution helpfull: 1 1

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