iit jee physics

the eqn of an shm with amplitude A and ang freq w in which all the distances are measured from one extreme position and time is taken zero at other extreme position is

1)  x = A- Acos wt

0r  2) x = A+Acos w t

i want to know which one is the correct formula

Asked By: SARIKA 1 Day ago

A 50 kg gymnast falls freely from a height of 4 m on to a trampoline. The trampoline then bounces her back upward with a speed equal to the speed at which she first struck the trampoline. What is the average force the trampoline applies on the gymnast ?

A) 50 N  B) 200 N C) 500 N  D) 2000 N  E)  more information is required

Asked By: VAIBHAV GUPTA 12 Day ago
Calculate rate of change of momentum

rain is falling down vertically 2m/s. a person is walking with velocity 2m/s on horizantal road. the angle made by the umbrella with vertical to protect from rain is

Asked By: VISHISTA 17 Day ago
Tan inverse 2/2 = 45 degree

a block of mass m is pushed up a movable incline of mass nm and height h.All surfaces are smooth without friction.what must be the minimum value of u so that the block just reaches the top of the movable incline.

let velocity of m at start is u along horizontal

at the top horizontal velocity of system = u/(n+1)  and vertical velocity = 0

by energy conservation 1/2 mu2 = 1/2 (nm+m) {u/(n+1)}2 + mgh

solve

Physics >> Mechanics Part 2 >> Elasticity Medical Exam

A solid sphere is subjected to uniform pressure from all direction. The ratio of volumetric strain to lateral strain produced in it, is

Asked By: SWATI KAPOOR 22 Day ago

V = 4/3 πr3

so dV = 4πr2

now calculate dV/V

Physics >> Mechanics Part 2 >> Elasticity Medical Exam

What is the length of a wire whose density is 8 g/cm3, which suspended vertically, would break due to its own weight? [Breaking stress of wire is 2.4 x 108 N/m2]

Asked By: SWATI KAPOOR 22 Day ago

use stress = force/area

Physics >> Mechanics Part 2 >> Elasticity Medical Exam

When a load of 8 kg is hung on a wire, then extension of 3 cm takes place, the work done by internal forces of wire is

Asked By: SWATI KAPOOR 22 Day ago
Calculate work done by weight of body hung
Physics >> Mechanics Part 2 >> Elasticity Medical Exam

The work done per unit volume to stretch the length of area of cross-section 2 mm2 by 2% will be [ Y = 8 x 1010 N/m2 ]

Asked By: SWATI KAPOOR 22 Day ago
W =1/2 Y (dl/l)2 V V represents volume Now solve
Physics >> Mechanics Part 2 >> Elasticity Medical Exam

To break a wire a stress of 9 x 105 N/m2 is required. If density of the material of wire is 3 g/cc, then the minimum length of wire which will break by its own weight will be

Asked By: SWATI KAPOOR 22 Day ago

use stress = force /area

Physics >> Mechanics Part 2 >> Elasticity Medical Exam

A steel wire is 1m long and 1mm2 in area of cross-section. If it takes 200 N to stretch this wire by 1mm, how much force will be required to stretch a wire of the same material as well as diameter from its normal length of 10m to a length of 1002 cm?

Asked By: SWATI KAPOOR 22 Day ago

by first set of data calculate Y then by using this Y solve the question

Physics >> Mechanics Part 2 >> Elasticity Medical Exam

The length of wire, when M1 is hung from it, is l1 and is l2 with both M1 and M2 hanging. The natural length of wire is [ M2 is on M1 ]

Asked By: SWATI KAPOOR 22 Day ago

Y = M1gL/A(l1-L) = (M1+M2)gL/(l2-L)

solve for L

Physics >> Mechanics Part 2 >> Elasticity Medical Exam

A nylon rope 3 cm in diameter has a breaking strength of 1.5 x 105 N. The breaking strength for a similar rope 1.5cm in diameter is

Asked By: SWATI KAPOOR 22 Day ago

breaking stress will remain same

Physics >> Mechanics Part 2 >> Elasticity Medical Exam

Two metallic cylinder made of same material and radii r and 2r are joined ( cylinder with smaller radius is on the cylinder with largest radius). If cylinder B is twisted t angle , then angle of twist for cylinder A is

Asked By: SWATI KAPOOR 22 Day ago
Physics >> Mechanics Part 2 >> Elasticity Medical Exam

A cubical block of a metal having shear modulus η is fixed from one face as shown in figure and constant force F is applied on it. Find the shear strain produced in it.

Asked By: SWATI KAPOOR 22 Day ago
Shear elasticity = F/A/shear strain Now solve
Physics >> Mechanics Part 2 >> Elasticity Medical Exam

Breaking stress for a material is 2 x 108 N/m2. What maximum length of the wire of this material can be taken so that the wire does not break by own weight? (Density of material = 5 x 103 kg/m3)

Asked By: SWATI KAPOOR 22 Day ago
Physics >> Mechanics Part 2 >> Elasticity Medical Exam

A uniform wire of mass 400g hangs from the ceiling. A block of mass 600g is attached to its lower end. Find the ratio of stress at points 3L/4 from the top and bottom end of wire.

Asked By: SWATI KAPOOR 22 Day ago

Methane goes through combustion by consuming Oxygen through the formula CH4 + 2O2 -----> CO2 + 2H2O, If inputs are CH4 = 1Kg and N2 = 13.2 Kg then prove law of conservation if CO2 2.75 Kg, H2O = 2.25 Kg

Asked By: MOAVIA HASSAN 26 Day ago

The time period of a pendulum is given by T=2π√l/g, find T when l=20 cm and g is acceleration due to gravity (9.8 m/sec2)

Asked By: MOAVIA HASSAN 26 Day ago
An Object is displaced from a point A(0,0,0) to B(1,1,1) under a force F vector=(yi+xj)N. Find the work done by this force in this process.
Asked By: ANUPAM CHAKRABORTY 29 Day ago
An Object is displaced from a point A(0,0,0) to B(1,1,1) under a force F vector=(yi+xj)N. Find the work done by this force in this process.
Asked By: ANUPAM CHAKRABORTY 29 Day ago
An Object is displaced from a point A(0,0,0) to B(1,1,1) under a force F vector=(yi+xj)N. Find the work done by this force in this process.
Asked By: ANUPAM CHAKRABORTY 29 Day ago

a mass attached to a spring oscillates every 2 sec.if the mass is increased by 2 kg and the time period increases by 1 sec .what was the initial mass?

.a mass attached to a spring oscillates every 2 sec.if the mass is increased by 2 kg and the time period increases by 1 sec .what was the initial mass?

a package of mass 10kg is released from rest on a rough slope inclined at 25 degrees to the horizontal. after 2 seconds the package has moved 4m down the slope. find the coefficient of friction between the package and the slope.

a box of mass 2kg is pushed up a rough plane by a horizontal force of magnitude 25N. the plane is inclined to the horizontal at an angle of 10 degree. given that the coefficient of friction between the box and the plane is 0.3, find the acceleration of the box.

Asked By: AMAR KHAN 1 Month ago

first part is correctly explained by Sarika

for second part make components of forces as 25 N and weight along and perpendicular to the incline, friction μN will be along downward incline and N will be the resultant of components of weight and 25 N perpendicular to the plane.

a projectile is thrown upward with initial velocity of 20 m/s  making an angle 30 degrees with horizontal .find its velocity at highest point.Also find its velocity just before hitting the ground.

Asked By: ALI UMAIR 1 Month agoSolved By: SARIKA

A chain of mass m=0.8 kg and length i=1.5m rests on a rough surfaced table so that one of its ends hangs over the edge.The chain starts sliding all by itself provided that the length of the hanging part is n=1/3 of chain length.What will be the total work done by the friction forces acting on the chain by the moment it slides completely off the table?

Asked By: SUSHOVAN HALDAR 1 Month ago
Physics >> Mechanics part 1 >> Kinematics Engineering Exam

The velocity  body A is X m/s at all instants with respect to another body B which follows a parabolic path. The parabola intersects the elliptical path of another body C whose velocity with respect to B at the instant of inersection (when B and C do not collide) is Y m/s. Find the absolute velocity of A at the instant of intersection.

In order to raise a mass of 100 kg, a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbes the rope with an acceleration 5g/4 relative to the rope. The tension of the rope is:

(a) 1432 N

(b) 928 N

(c) 1218 N

(d) 642 N

Asked By: RAJIV 1 Month ago

eq. for upward motion of 100 Kg is T-100g = 100a  (1)

for man eq. is T-60g = 60[(5g/4)-a]             from ground frame

solve?

A gas expands against a variable external pressure given by p = 10/V atm, where V is the volume at each stage of expansion. in expanding from 10 L to 100 L, the gas undergoes a change in internal energy ΔU = 418 J. How much heat has been absorbed?

process is isothermal because pV = 10 = nRT

so work done W = 2.303nRTlog(V2/V1)

so Q = Δ+ W

if an area of isoscale right angle triangle(made of uniform wire of unit resistivity) is 8 unit. a battery of emf 10 unit is connected with across the longest branch then the current drawn from battery is approx                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                     ans is  3A

Asked By: AKANKSHA SINHA 1 Month ago

area = l2/2 = 8 so l = 4

ρ = 1

so  resistance of the 3 legs of the triangle = 4/A, 4/A, 4√2/A

battery is connected across the longest branch so eq. resistance = 4/A+4/A+4√2/A = 13.6/A

i think area of cross section will be given then calculate current

When An external resistance R is connected with the battery of emf E and internal resistane r, what is the maximum power?

Asked By: 1 Month agoSolved By: SARIKA
Physics >> Mechanics part 1 >> Kinematics Medical Exam

A particle starts wth initial speed u and retardation a and takes time t to cme to rest. The tine raken by particle to cover first half of the total path travelled is?

Asked By: RITIKA 1 Month ago

sir

there is a statement ie

FRICTION IS SELF ADJUSTABLE   , is it right or not ??  The problem is only static frictn is self adjustable , so wat shld be the ans for only frictn ??

Asked By: SARIKA 1 Month ago

in a general way the statement is correct

There is a spring balance whose one end is attached to a cage , in which of the following case weight measured by spring balaced will not be equal to  real one ,optn r

1)  a   bird is  sitting in an air tight cage

2)   a   bird is sitting in a cage whose gate is open

3)   a bird is flying in an air tight cage

4)      a bird is flying in a cage whose gate is open

annex explnatn also

Asked By: SARIKA 1 Month ago

Can You explain some easy way to find potential difference between A & B and B & C.

Asked By: BONEY HAVELIWALA 1 Month ago
Solution by manish sir

3 μF || 3 μF = 6 μF and 1 μF || 1 μF = 2 μF

so divide voltage between 6 and 2

voltage on 6 will be 2*100/8 = 25

similarly for other

Can You explain some easy way to find potential between A and B?

Asked By: BONEY HAVELIWALA 1 Month ago

use kirchhoff laws

4-10i+1-30x = 0

1-30x+20(i-x) = 0

solve it for i and x

potential across A and B = 4-10i+1 = 30x

Physics >> Mechanics part 1 >> Kinematics Medical Exam

Two cars are moving in the same direction with the same speed 30 kmph . They are separated by a distance 5km. What is the speed of the car moving in the opposite direction if it meets these two cars at an interval of 4 minutes ?

Asked By: PRACHI PATEL 1 Month agoSolved By: PRACHI PATEL

Two Magnets of M magnetic dipole moment are placed shown in figure. What will be the intensity of magnetism at the point P shown in figure.

Asked By: BONEY HAVELIWALA 1 Month ago

the resultant dipole moment is √2M  thus  the resultant magnetic  field is  μ2√2M/4πd3   (ans)

Asked By: BONEY HAVELIWALA 1 Month ago

since the circuit is symmetrical with respect to the line given so V, the potentials at the given points will be same

now calculate the eq. for the half circuit and double it for getting the eq. of the whole circuit

Solution by manish sir

since the circuit is symmetrical with respect to the line given so V, the potentials at the given points will be same

now calculate the eq. for the half circuit and double it for getting the eq. of the whole circuit

for one side eq. of 2 and 4 = 4/3

and then 4 in series of it so 4/3 + 4 = 16/3

finally 16/3||4/3

eq = 16/15

final answer = 16/15 * 2 = 32/15

A Volt-meter of 20000 Ohm resistance is connected with R ohm resistance in series. if we apply 110 V of pd to the mechanism, the Volt meter shows 5 V reading.. so find the R...

Asked By: BONEY HAVELIWALA 1 Month ago

current on both the resistances will be same

so V1/R1 = V2/R2

5/20000 = 105/R

solve

Physics >> Mechanics part 1 >> Kinematics Medical Exam

the min no. of non coplanar and non zero vectors of unequal magnitude which can give zero resultant is _________??

Asked By: SARIKA 1 Month ago

four

let three are i, j, k then fourth will be -(i+j+k)

Physics >> Mechanics part 1 >> Kinematics Medical Exam

if y= 50 / [(x-5)2 +5]2  then maximum value of y will be??

Asked By: SARIKA 1 Month ago

let z = [(x-5)2 +5]

then dz/dx = 2(x-5)

compare it to 0 we get x = 5

so for x = 5, z will be minimum and so y will be max for that x

put x= 5 and get answer

CALCULATE  THE MAGNETIC FIELD  AT THE CENTRE OF SQUARE WIRE OF SIDE (2)1/2cm  AND CARRYING A CURRENT OF 10A.?

Asked By: GAUTAM SAGAR 1 Month ago

method given by BONEY is correct but formula is not correct

it should be B = 4×{ (μ0I) / 4πR } × [sinθ1+ Sinθ2]

Two voltameters one of copper and another of silver, are joined in parallel. When a
total charge q flows through the voltameters, equal amount of metals are deposited.
If the electrochemical equivalents of copper and silver are z1 and z2 respectively the
charge
which flows through the silver voltameter is

m = z1q1 = z2q2 (1)

and q = q1 + q2

now solve

can you explain the magnetic meridian, geometric meridian and angle of deep? with diagram if possible

Asked By: BONEY HAVELIWALA 2 Month agoSolved By: SARIKA

two short magnets of equal dipole momet M are fastened perpedicularat their centre.the magnitude of  magnetic feild at adistance d from the centre on the bisector of right angles is?

Asked By: AKANKSHA 2 Month agoSolved By: SARIKA

the resultant dipole moment is √2M  thus  the resultant magnetic  field is  μ2√2M/4πd3   (ans)

Can You Please Explain the Cartesian method for mirror and Lens?

Asked By: BONEY HAVELIWALA 2 Month ago

Cartesian method is the method of sign convention

Sign Convention for Spherical Mirrors and Thin Lenses

Spherical Mirrors                   Lenses
Focal Length            - for concave mirrors            + for a converging lens
+ for convex mirrors               - for a diverging lens
Object Distance           - real object                     - real object
+ virtual object                 + virtual object

Image Distance           - real image                          + real image
+ virtual image                   - virtual image
Magnification            + for erect image                 + for erect image
- for inverted image            - for inverted image

Can you please explain me to find potential difference between two plates of capacitor like this shown in figure. Can you Give anymore examples if possible? Thank You! (Please omit time)

Asked By: BONEY HAVELIWALA 2 Month ago

after time t charge on plates of capacitor q = CE(1-e-t/RC)

then potential difference between the plates of capacitor = q/C

after a long time this potential difference = E      [this can be obtained by putting t = ∞]

A particle has initial velocity of y = 3i+ 4j and a constant force F = 4i -3j acts on it. Then what will be the path followed by the particle?

Asked By: VIKRAM 2 Month ago

acceleration is constant and initial velocity is perpendicular to it because dot product of two given vectors is 0 so this is the case equivalent to a particle thriwn from the top of a building horizontally under gravity so path will be parabolic

if you want the equation of path then reply

A block of mass 100 g is moved with a speed of 5 m/s at the highest point in a closed circular tube of radius 10 cm kept in vrtical plane.The cross section of the tube is such that the block just fits in it.The block makes several oscillations inside the tube and finally stops at the lowest point. Find the work done by the tube on the block.

Asked By: SUBHASH 2 Month ago

Total energy is lost so K E will be the work done

A particle is moving with a velocity of 10m/s due east. In One second its velocity changes to 10m/s due west. If the particle is uniformly accelerated, the change in velocity will be directed as

 A.  20m/s, east B. 10m/s, east C. 10m/s, west D. 20m/s west

Asked By: GAUTAM SAGAR 2 Month agoSolved By: SARIKA SHARMA

A particle moving with constant acceleration covers a distance of 30m in the 3rd second. it covers a distance of 50m in the 5th  second. What is the acceleration of the particle?

Asked By: GAUTAM SAGAR 2 Month agoSolved By: SARIKA SHARMA

A ball is dropped from the top of the tower of height h. It covers a distance h/2 in the last second of its motion. How long does the ball remain in air?

Asked By: GAUTAM SAGAR 2 Month ago

let total time of flight = t

so h = gt2/2 and

h/2 = gt-(g/2)

so gt2/4 = gt-(g/2)

or t2/4 = t -(1/2)

now solve

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

If L is the angular momentum of a satellite revolving around earth is a circular orbit of radius r with speed v, then (i) L α v

(ii) L α r

(iii) L α √v

(iv) L α √r

Asked By: SWATI KAPOOR 2 Month ago

L = m*v*r

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

If potential energy of a body of mass m on the surface of earth is taken as zero then its potential energy at height h above the surface of earth is [ R is radius of earth and M is mass of earth]

Asked By: SWATI KAPOOR 2 Month ago

[-GMm/(R+h)]-[-GMm/R] = GMm[1/R - 1/(R+h)]

solve ?

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

Two points masses having m and 4m are placed at distance at r. The gravitational potential at a point, where gravitational field intensity zero is

Asked By: SWATI KAPOOR 2 Month ago

field intensity at distance x from m = Gm/x2 - G4m/(r-x)2

compare it to 0 and find x

then calculate gravitational potential at the point

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

During motion of a planet from perihelion to aphelion the work done by gravitational force of sun on it is positive or negative.

Asked By: SWATI KAPOOR 2 Month ago

change in K E = work done by all the forces

and from perihelion to aphelion velocity decreases

so work done will be negative

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

If an object is projected vertically upwards with speed, half the escape speed of earth , then the maximum height attained by it is [R is radius of earth]

Asked By: SWATI KAPOOR 2 Month ago

from ground to that point

1/2 m[√(2gR)/2] + [-GMm/R]  =  0 + [-GMm/(R+h)]

solve for h

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

Two point masses having mass m and 2m are placed at distance d. The point on the line joining point masses, where gravitational field intensity is zero will be at distance

Asked By: SWATI KAPOOR 2 Month ago

let the point will be at a distance of x from m then compare the gravitational field of the two masses at that point

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

If earth suddenly stop rotating, then the weight of an object of mass m at equator will [ ω is angular speed of earth and radius R is its radius]

Asked By: SWATI KAPOOR 2 Month ago

In rotating condition mass at equator is mg-mRω2

if earth stops rotation then it will become mg so increases by mRω2

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

Three particles A,B and C each of mass m are lying at the corners of an equilateral triangle of side L. If the particle A is released keeping the particles B and C fixed, the magnitude of instantaneous acceleration of A is

Asked By: SWATI KAPOOR 2 Month ago

force by the other two on A = Gmm/L2 each but the angle between the two forces is 60 degree so resultant force = √3Gmm/L2

now calculate acceleration?

A large number of identical point masses m are placed along x-axis, at x= 0,1,2,4.........The magnitude of gravitational force on mass at origin (x=0), will be

Asked By: SWATI KAPOOR 2 Month ago

The magnitude of gravitational force on mass at origin (x=0), will be

Gmm/12 + Gmm/22 + Gmm/42 + Gmm/8+ .........................

= [Gmm/12][1+(1/4)+(1/16)+....................]

= Gmm[1/(1-(1/4)]

solve?

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

A satellite of mass 200 kg revolves around a planet of mass 5 x 1030kg in a circular orbit of radius 6.6 x 106 m. Binding energy of the satellite.

Asked By: SWATI KAPOOR 2 Month ago

Binding energy = GMm/2R

What is the minimum coefficient of friction for a solid sphere to roll without slipping on an inclined plane of inclination θ?

Asked By: SWATI KAPOOR 2 Month ago

friction f = mgsinθ/[1+(mr2/I)]

solve for sphere and compare to μmgcosθ

A particle moving with constant acceleration covers a distance of 30m in the 3rd second. it covers a distance of 50m in the 5th  second. What is the acceleration of the particle?

Asked By: GAUTAM SAGAR 2 Month ago

use formula for the distance covered in a particular second

st = u+at-(a/2)

A particle is moving with a velocity of 10m/s due east. In One second its velocity changes to 10m/s due west. If the particle is uniformly accelerated, the change in velocity will be directed as

Asked By: GAUTAM SAGAR 2 Month ago

let east is i

then velocity change = -10i-10i = -20i

A  ball is dropped from a height h reaches the ground in time T. What is its height at time T/2

Asked By: GAUTAM SAGAR 2 Month ago

h = 1/2 gT2

in T/2 time h' = 1/2 gT2/4 = 1/8 gT2

so height from ground = h-h'

solve?

Asked By: GAUTAM SAGAR 2 Month ago

see you tube video of iitbrain by the name I E Irodov problem 1.3

Asked By: GAUTAM SAGAR 2 Month ago

fig 1 and fig 2 are explaining symmetry method.

divide the circuit in two parts by a line symmetry, then calculate eq. resistance between A and O by series parellel rules then for getting eq. resisitance between A and B double the answer between A and O

Delta star is the method to convert the circuit into an equivalent circuit in which series parallel rules can be applied

By this method a set of three resistances R1, R2 and R3 can be converted to 3 new resistances 1, 2 and 3

where 1 = R1R2/(R1+R2+R3), 2 = R1R3/(R1+R2+R3) and 3 = R2R3/(R1+R2+R3)

Two Particles move in a uniform gravitational field  with an acceleration g. At The Initial  moment the particles were located at one point and moved with velocities v1= 3.0ms-1 and v2 = 4.0ms-1 horizontally in opp. Direction.Find The distance between the particles at the moment when their velocity vector become mutually Perpendicular?

Asked By: GAUTAM SAGAR 2 Month ago

see you tube video of iitbrain by the name I E Irodov problem 1.11

A Train Accelerates from rest at a constant rate α for sometime and then it retards to rest at a constant rate β. If te total distance covered by the particle is x, then what is the maximum velocity of the train ?

Asked By: GAUTAM SAGAR 2 Month ago

for first part of motion

v2 = 2αx1   (1)

similarly for second part of motion

v2= 2βx2     (2)

now by given conditions

x = x1 + x2

so x = v2/2α + v2/2β

so x = v2/2[1/α + 1/β]

now solve

Find the moment of inertia of a uniform square plate of mass M and edge a about one of its diagonals.

(1) Ma/ 12

(2) 2/3 x Ma2

Asked By: SWATI KAPOOR 2 Month ago

let the moment of inertia about a diagonal = I

then by perpendicular axis theorem 2I = 1/6 Ma2

now calculate I

Two sphere are rotating about their own axis if axis of rotation of these axis are perpendicular to each other than angular acceleration of one with respect to other
Asked By: MANISH KUMAR SAHU 2 Month ago

let the angular velocities are ω1 ω2

then angular acceleration of one w. r. t. other =  ω1 ω2

A taxi leaves the station X for Station Y every 10 min. Simulataneously, a taxi also leaves the station Y for station X Every 10min. The Taxis move at the same constant speed and go from X to Y or Viceversa in 2Hours. How Many taxis coming from the other side meet each taxi enroute from Y To X?

Asked By: GAUTAM SAGAR 2 Month ago

the answer depends on the condition that where taxi meets with the first taxi coming from opposite side.

If we consider that at the starting point taxi meets with the first taxi coming from other side, then after every 5 min it will meet with a taxi from opposite side. This will be due to the double relative speed of two taxi moving opposite. Total time length of the path = 2 hrs = 120 min

so no. of taxi = 120/5 + 1 = 25

if first taxi meet at the point a little ahead the starting point then no of taxi = 120/5 = 24

similarly other cases

A train accelerates from rest at a constant rate α for distance x1 and time t1.After that it retards to rest at constant rate β for distamce x2 and time t2.Which of the following relation is correct?

 A. x1/x2=α/β=t2/t1 B.   x1/x2=β/α=t2/t1 C. x1/x2=α/β=t1/t2 D.  x1/x2=β/α=t1/t2

Asked By: GAUTAM SAGAR 2 Month ago

for first part x1 = αt12/2 and v = αt1

similarly for second part x2 = βt22/2 and v = βt2

on comparing v we get  αt= βt2

so β/α = t1/t2   (1)

and x1/x2αt12/βt2= β/α   (2)        by using (1)

A ball of mass 1 kg is projected with a velocity of 20√2 m/s from the origin of an xy coordinates axis system at an angle 45° with x-axis (horizontal). The angular momentum of the ball about the point of projection after 2s of projection is [take g=10 m/s2] (y-axis is taken as vertical)

Asked By: SWATI KAPOOR 2 Month ago

initial vertical and horizontal velocities are 20 m/s and 20 m/s

after 2 sec. vertical and horizontal velocities are 0 m/s and 20 m/s

and y and x displacements are 20 m and 40 m

so about point of projection angular momentum after 2 sec.

= mvxy - mvyx = 1*20*20 - 1*0*40 = 400

A disc of mass 3kg rolls down an inclined plane of height 5 m. The translational kinetic energy of the disc on reaching the bottom of the inclined plane is

Asked By: SWATI KAPOOR 2 Month ago

mgh = 1/2 mv2 + 1/2 Iω2

I for the disc about centre = 1/2 MR

and for pure rolling v = Rω

calculate v then 1/2 mv2

A heavy solid sphere is thrown on a horizontal rough surface with initial velocity u without rolling. What will be its speed, when it starts pure rolling motion

Asked By: SWATI KAPOOR 2 Month ago

for translational motion

0-μMg = Ma so a = -μg

so after time t velocity v = u-μgt  (1)

for rotational motion

about centre, μMgr = Iα = 2Mr2α/5

so α = 5μg/2r

so ω = 0 + αt

so ω = 5μgt/2r  (2)

for pure rolling

v = rω implies that u-μgt = r5μgt/2r

implies that u = 7μgt/2

so t = 2u/7μg

now put t in (1) for getting v

Two rings of same mass and radius R are placed with their planes perpendicular to each other and centres  at a common point. The radius of gyration of the system about an axis passing through the centre and perpendicular to the plane of one ring is

Asked By: SWATI KAPOOR 2 Month ago

The axis passing through the centre of one ring and perpendicular to the plane will be diametric axis of the other ring

so moment of inertia about that axis = MR2 + 1/2 MR2 = 3/2 MR2

now compare it to Mk2 and get k, it is radius of gyration

A man of mass 60 kg is standing on a boat of mass 140 kg , which is at rest in still water. The man is initially at 20 m from the shore. He starts walking on the boat for 4s with constant speed 1.5 m/s towards the shore. The final distance of the man from the shore is

Asked By: SWATI KAPOOR 2 Month ago

distance covered in boat = 1.5*4 = 6 m

and for making the position of centre of mass undistubed displacement of boat in opposite direction = x (let)

by law of conservation of momentum (140+60)*v = 60*1.5

so v = 90/200 = 0.45 m/s

so displacement of boat = 0.45*4 = 1.8 m

so final distance of the man from the shore = 20-6+1.8 = 15.8 m

A horizontal disc rotating freely about a vertical axis through its centre makes 90 revolutions per minute. A small piece of wax of mass m falls vertically on the disc and sticks to it at a distance r from the axis. If the number of revolutions per minute reduce to 60, then  the moment of inertia of the disc is

Asked By: SWATI KAPOOR 2 Month ago

use I1ω1 = I2ω2

let moment of inertia of disc about given axis is I

then I2π90/60 = [I+mr2]2π60/60

solve it

A uniform rod of mass m and length l is suspended by two strings at its ends. When one of the strings is cut, the rod starts falling with an initial angular acceleration

Asked By: SWATI KAPOOR 2 Month ago

after cutting one string eq. of motion will be

mg-T = ma

mg*l/2 = Iα

put I = ml2/3 and get the answer

A particle of mass 5 kg is moving with a uniform speed 3√2 in XOY plane along Y = X + 4. The magnitude of its angular momentum about the origin is

Asked By: SWATI KAPOOR 2 Month ago
Solution by manish sir

perpendicular distance of the line x-y+4 = 0 from origin

= (0-0+4)/√2

so angular momentum = mvr = 5*(3√2)*4/√2 = 60

A wheel having moment of inertia 4 kg m2 about its symmetrical axis, rotates at rate of 240 rpm about it. The torque which can stop the rotation of the wheel in one minute is

Asked By: SWATI KAPOOR 2 Month ago

angular retardation = 2π[240/60]/60             this is by the formula ω = ω0+αt  where ω= 0

now use τ = Iα

Two equal and opposite forces are applied tangentially to a uniform disc of mass M and radius R as shown in the figure. If the disc is pivoted at its centre and free to rotate in its plane, the angular acceleration of the disc is

Asked By: SWATI KAPOOR 2 Month ago

by using τ = Iα

2FR = MR2α/2

solve?

A disc of mass M kg and radius R metre is rotating at an angular speed of ω rad/s when the motor is switched off. Neglecting the friction at the axle, the force that must be applied tangentially to the wheel to bring it to rest in time t is

Asked By: SWATI KAPOOR 2 Month ago

let force is F

then retarding torque about axis = FR

so by τ = Iα  calculate α

then use first eq. of motion in rotation

ωfω- αt

A hollow sphere of mass 1 kg and radius 10 cm is free to rotate about its diameter. If a force of 30 N is applied tangentially to it, its angular acceleration is (in rad/s2)

Asked By: SWATI KAPOOR 2 Month agoSolved By: SARIKA SHARMA

An angular impulse of 20 Nms is applied to a hollow cylinder of mass 2 kg and radius 20 cm.The change in its angular speed is

Asked By: SWATI KAPOOR 2 Month agoSolved By: SARIKA SHARMA

Four thin uniform rods each of length l and mass m are joined to form a square. The moment of inertia of square about an axis along its one diagonal is

Asked By: SWATI KAPOOR 2 Month ago

moment of inertia of 1 rod about diameter = m(lsin45)2/3

now multiply it to 4 for getting the net inertia about diameter

A disc of mass 1 kg and radius 0.1m is rotating with angular velocity 20 rad/s. What is angular velocity (in rad/s) if a mass of 0.5 kg is put on the circumference of the disc?

Asked By: SWATI KAPOOR 2 Month ago

by angular momentum conservation

I1ω1 = I2ω2

so [1(0.1)2/2]20 = [1(0.1)2/2+0.5(0.1)2]ω2

solve and get ω2

Which of the following have maximum percentage of total K.E. in rotational form while pure rolling – Disc, Sphere, Ring or Hollow sphere. PLZ  EXPLAIN  ALSO.

Asked By: SWATI KAPOOR 2 Month ago

total kinetic energy of a rolling body = mv2/2 + Iω2/2 = mv2/2 + Iv2​/2r2 = (mv2/2)[1+I/mr2

rotational kinetic energy of a rolling body =  Iω2/2 = Iv2​/2r2 = (mv2/2)[I/mr2

so ratio R. K. E. / T. K. E. =  (mv2/2)[I/mr2] /  (mv2/2)[1+I/mr2] = [I/mr2] / [1+I/mr2]

= [I/I+mr2

= 1/[1+(mr2/I)]

I is max. for a ring so ratio will be max. for a ring

To a billiard ball  of mass M and radius r a horizontal impulse is given passing through its centre of mass and it provides velocity u to its centre of mass. If coefficient of friction between the ball and the horizontal surface is μ, then after how much time ball starts pure rolling?

Asked By: SWATI KAPOOR 2 Month ago

for translational motion

0-μMg = Ma so a = -μg

so after time t velocity v = u--μgt

for rotational motion

about centre, μMgr = Iα = 2Mr2α/5

so α = 5μg/2r

so ω = 0 + αt

so ω = 5μgt/2r

for pure rolling

v = rω implies that u-μgt = r5μgt/2r

implies that u = 7μgt/2

so t = 2u/7μg

The thin circular ring shown below has mass M and length L. A force F acts at one end at an angle 30° with the horizontal and the rod is free to rotate about the other end in the plane of force. Initial angular acceleration of the rod is

Asked By: SWATI KAPOOR 2 Month ago

ring or rod, first clear it

A thin circular ring slips down a smooth incline then rolls down a rough incline of identical geometry from same height. Ratio of time taken in the two motion is

Asked By: SWATI KAPOOR 2 Month ago

in first slipping takes place whereas in second rolling takes place

for first accleration = g sinθ

and for second acceleration = g sinθ/[1+(I/mr2)]

now use s = ut + at2/2

If μ is the coefficient of friction, K is the radius of gyration, R is the radius and θ is the inclination. Then find the relation between them???

Asked By: SWATI KAPOOR 2 Month agoSolved By: SARIKA SHARMA

A simple pendulum of mass and length L is held in horizontal position. If it is released from this position, then find the angular momentum of the bob about the point of suspension when it is vertically below the point of suspension.

Asked By: SWATI KAPOOR 2 Month ago

by energy conservation v = √(2gL) below the point of suspension

so angular momentum = mvL about the point of suspension

A rod of length L and mass m is free to rotate about its one end in vertical plane. If it is released from horizontal position, then find torque on rod about end of rotation , when it makes an angle θ with vertical line

Asked By: SWATI KAPOOR 2 Month ago

force is mg and perpendicular distance from axis l/2 sinθ

now calculate

Four solid rigid balls each of mass m and radius r are fixed on a rigid ring of radius 2r and mass 2m.The system is whirled about ‘O’. The radius of gyration of the system is 128 mr2/30. How???

Asked By: SWATI KAPOOR 2 Month ago

M. I. of ring = 2m(2r)2

M. I. of one ball = 2mr2/5 + m(2r)2 = 22mr2/5

so total = 8mr2 + 4*22mr2/5

solve

One other thing is that the question is wrong, in the place of radius of gyration, you should write moment of inertia

H = W =  V2t/R .  [ H inversely proportional to R ]

therefore my question is how can heat be both directly and inversely proportional to the resistance in the circuit??

Asked By: AAYUSH TANEJA 2 Month ago

you should take the formula in which one variable is constant and for a circuit current will be constant

In an electrical circuit...

H = W = (i x i) x R x t   [ H directly proportional to R ]

H = W =  (V x V) x t /R .  [ H inversely proportional to R ]

So is Heat Generated directly proportional or inversely proportional to the resistance in the circuit ??

Asked By: AAYUSH TANEJA 2 Month ago

H = W = (i x i) x R x t   [ H directly proportional to R ]

this one is correct for the heat generated

The rate of doing work by force acting on a particle moving along x-axis depends on position x of particle and is equal to 2x. The velocity of particle is given by

Asked By: SWATI KAPOOR 2 Month ago

Rate of doing work is power so according to the given condition

P = 2x

so Fv = 2x

or m(dv/dt)v = 2x

or m(vdv/dx)v = 2x

or mv2dv = 2xdx

now integrate.

A shell at rest on a smooth horizontal surface explodes into two fragments of masses m1 and m2. If just after explosion m1 moves with speed u, then work done by internal forces during explosion is

Asked By: SWATI KAPOOR 2 Month ago

By momentum conservation velocity of m2 = m1u/m2

now sum of kinetic energies = Net work done by internal forces

A body of mass m falls from height h on ground. If 'e' be the coefficient of restitution of collision between the body and ground, then the distance travelled by body before it comes to rest is

Asked By: SWATI KAPOOR 2 Month ago

if a body falls from height h then height attained after rebound will be e2h

by using this fact

total distance covered before stop = h+2e2h+2e2e2h+2e2e2e2h+..................................................

so d = h+2e2h[1+e2+e4+e6+.........................]

now solve

A particle is moving in a circular path of radius r under the action of a force F. If at an instant velocity of particle is v, and speed of particle is increasing, then

(i) F.v=0    (ii) F.v > 0   (iii) F.v < 0

Asked By: SWATI KAPOOR 2 Month ago

centripetal acc. is the need for circular motion but speed is increasing so tangential acc will also be present so angle between velocity and acc will be acute so F.v > 0

A ball of mass m moving with speed v collides with a smooth horizontal surface at angle θ with it as shown in figure. The magnitude of impulse imparted to surface by ball is

Asked By: SWATI KAPOOR 2 Month ago

From where θ is measured, horizontal or vertical ?

A particle of mass m moving from origin along x-axis and its velocity varies with position x as v= k√x. The work done by force acting on it during first 't' seconds is

Asked By: SWATI KAPOOR 2 Month ago

v = k√x

so a = dv/dt = [k/2√x]*dx/dt  = [k/2√x]*v = [k/2√x]*[k√x] = k2/2 = constant

and dx/dt = k√x

so dx/√x = kdt

integrate within o to t

finally work = Fx  because F is constant

A particle of mass m is projected with speed u at angle θ with horizontal from ground. The work done by gravity on it during its upward motion is

Asked By: SWATI KAPOOR 2 Month ago

H = u2sin2θ/2g

so work done by gravity = mgH

A body of mass m is projected from ground with speed u at an angle θ with the horizontal. The power delivered by gravity to it at half of maximum height from the ground is

Asked By: SWATI KAPOOR 2 Month ago

at half height, vertical velocity v2 = u2sin2θ - 2gH/2, from this equation calculate v

then P = F.v = -mg* vertical component of velocity

this will be instataneous power

A ball of mass m moving with speed v collides perfectly inelastically with another ball of mass m at rest. The magnitude of impulse imparted to the first ball is

Asked By: SWATI KAPOOR 2 Month ago

inelastic collision means velocity of both ball will be same after collision

so by momentum conservation mv = 2mv' so v' = v/2

now initial momentum + impulse imparted = final momentum

mv + I = mv/2

so I = -mv/2

Two balls of equal mass undergo head on collision while each was moving with speed 6 m/s. If the coefficient of restitution is 1/3 , the speed of each ball after impact will be

Asked By: SWATI KAPOOR 2 Month ago

according to the given condition u1 = 6, u2 = -6

let after collision velocities are v1, v2

then by momentum conservation m1u1 + m2u2 = m1v1 + m2v2

and v2 - v1 = e(u2 - u1)

now solve

A small ball hits obliquely a smooth and horizontal surface with speed u whose x and y components are 2 amd 4 m/s. If the coefficient of restitution is 1/2, then its x and y components vx and vy just after collision are respectively.

Asked By: 2 Month agoSolved By: SARIKA

The position x of a particle moving along x-axis at time t is given by the equation t = √x + 2 , where x is in metres and t in seconds. Find the work done by the force in first four seconds.

Asked By: SWATI KAPOOR 2 Month ago

t = √x + 2

implies x = (t-2)2

so dx/dt = v = 2(t-2)

and dv/dt = a = 2

so F = ma = 2m

and x(initial) = 4 m

x (final) = 4 m

so displacement = 0 m

so work = 0 J

A bullet of mass m passes through a pendulum bob of mass M with velocity v and comes out of it with a velocity v/2. The minimum value of v so that tha bob mass complete one resolution in the vertical circle. (l= length of pendulum)

Asked By: SWATI KAPOOR 2 Month ago

for completing revolution velocity of the bob at lowest point should be √5gl

so by momentum conservation mv = M√5gl + mv/2

now solve

A ball moving with speed v collides with a horizontal smooth surface at an angle ϴ with normal to surface. If coefficient of restitution is ‘e’ , then find velocity after rebounce making same angle theta with the normal.

Asked By: SWATI KAPOOR 2 Month ago

let angle before collision is φ and after collision is θ with vertical then

for vertical direction velocity after rebound = evcosφ

for horizontal direction velocity after rebound = vsinφ

now use pythagorus theorem

A ball falls from a height such that it strikes the floor of lift at 10 m/s. If lift is moving in the upward direction with a velocity 1m/s, then velocity with which the ball rebounds after elastic collision will be

Asked By: SWATI KAPOOR 2 Month ago

A ball of mass m is released from the top of an inclined plane of inclination θ as shown. It strikes a rigid surface at a distances 3l/4 from the top elastically. Impulse imparted to ball by the rigid surface is

Asked By: SWATI KAPOOR 2 Month ago

The potential energy of a particle of mass 1 kg moving along x-axis given by U(x)= [x2/2 - x] . If total mechanical energy of particle is 2J, then find its maximum speed.

Asked By: SWATI KAPOOR 2 Month ago

If a particle is moving on a circular path with constant speed, then the angle between the direction of acceleration and its position vector wrt centre of circle will be

Asked By: SWATI KAPOOR 2 Month ago

it should be 180 degree

Two blocks of masses 2 kg and 4 kg are hanging with the help of massless string passing over an ideal pulley inside an elevator. The elevator is moving upward with an acceleration g/2. The tension in the string connected between the blocks will be

Asked By: SWATI KAPOOR 2 Month ago

equation 1

4g+4g/2-T = 4a

equation 2

T-2g-2g/2 = 2a

now solve

A block of mass 10 kg is released on rough incline plane of inclination 30°. Block start descending with acceleration 2 m/s2. Kinetic friction force acting on block is

Asked By: SWATI KAPOOR 2 Month agoSolved By: SARIKA
a particle starts with a constant tengential acceleration on a circle. the instant when it complete half circle what is the angle between its velocity vector and acceleration vector...???
Asked By: IMRAN AHMED 2 Month ago

let tangential acc is a

then velocity after covering half circle

v2 = 2a(πr)

so centripetal acc = v2/r = 2aπr/r = 2aπ

so angle = tan-1[2aπ/a] = tan-1

here notice that velocity will be in the direction of tangential acc.

is impedence as same as resistanace in a circuit // and // are capacitive reactance and inductive reactance constant values(i.e. independant of value of current in ac circuit at any time)  ??

Asked By: AAYUSH TANEJA 2 Month ago

Write the question with correct symbols

yes it is equivalent to resistance for that circuit

For what angle should a body be projected with velocity 24m/s just to pass over the obstacle 16 m high at horizontal distance of 32 m? Take g=10 m/s^2

Asked By: RESHU SINGH 2 Month ago

use the eq.

y = xtanθ-(gx2/2u2cos2θ)

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A rocket is fired vertically from the ground. It moves upward with a constant acceleration 10 m/s2 for 30s after which the fuel is consumed. After what time from the instant of firing the rocket will attain the maximum height?

Asked By: SWATI KAPOOR 3 Month ago

total height covered in upward journey = at2/2 = 10*30*30/2 = 4500 = 4.5 km

after consuming all the fuel, it will fall with gravity and g = 10 m/sso it will move the same distance again upto stop

so max H = 9 km.

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a bullet is fired vertically upwards with an initial velocity of 50 m/s. It covers a distance h1 during the first second and a distance h2 during the last 3 seconds of its upward motion. If g = 10 m/s2, h1 and h2 will be related as

Asked By: SWATI KAPOOR 3 Month ago

remember that gravity reduces velocity by 10 m/s on upward journey.

Also understand the diagram given

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a car is going eastwards with a velocity of 8m/s. To the passengers in the car , a train appears to be moving northwards with a velocity 15m/s. What is the actual velocity of the train?

Asked By: SWATI KAPOOR 3 Month ago

vobserver = 8i

vtrain,observer = 15j

so by formula

vtrain,observer = vtrain - vobserver

Physics >> Mechanics part 1 >> Kinematics Medical Exam

The displacement x of a particle varies with time t as x2= 1+t2 . What is its acceleration?

Asked By: SWATI KAPOOR 3 Month ago

on diffrentiation we will get

2xdx/dt = 2t

so xv = t    (1)

on differentiating again

xdv/dt + vdx/dt = 1

or xa + v= 1  (2)

now put v from (1) to (2) we will get answer

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a particle moving with constant acceleration on a straight line ultimately comes to rest. What is the angle between its initial velocity and acceleration

Asked By: SWATI KAPOOR 3 Month ago

180 degree because it is retarded particle

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a particle moves along a straight line. Its position (x) at any instant is given by x= 32t - 8t3/3, where x is in metre and t in second. Find the acceleration of the particle at the instant particle comes to rest

Asked By: SWATI KAPOOR 3 Month ago

differentiate the given function and find v, again differentiate find a

compare v to 0 for rest, get t and put in a

a particle initially at rest moves along x-axis. Its acceleration is given as a = (2t+2) m/s2. If it starts from origin , find distance covered in 2 second.

Asked By: SWATI KAPOOR 3 Month ago

dv/dt = 2t+2

so dv = 2tdt+2dt

on integrating the given eq.

v = t2 + 2t + C

at start v = 0 at t = 0

so on puting these initial values we get C = 0

so v = t2 + 2t

so dx/dt = t2 + 2t

so dx = t2dt + 2tdt

on integrating x = t3/3 + t2+ C

on putting initial values x=0 at t=0

we get C = 0

so x =  t3/3 + t

now put t = 2

Angle between a and b is θ. What is the value of a.(bxa) ?

Asked By: SWATI KAPOOR 3 Month ago

If two vectors are some in scalar triple product then it will be 0 always

Physics >> Mechanics part 1 >> Kinematics Medical Exam

the velocity v of a particle moving in the positive direction of x - axis as v = 5√x, assuming that at t=0, particle was at x=0. What is the acceleration of the particle?

Asked By: SWATI KAPOOR 3 Month ago

v = 5√x

differetiate this we get

dv/dt = 5*1/(2√x)*dx/dt

so a = 5*1/(2√x)*v

so a = 5*1/(2√x)*5√x

so a = 12.5

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a man wants to cross a river of width 500m in minimum distance. The rowing a speed of man relative to water is 3 km/h and river flows with speed 2km/h. The time taken by man to cross the river is

Asked By: SWATI KAPOOR 3 Month ago

for minimum drift he should swim in a direction such that 3sinA = 2

so sinA = 2/3

now calculate cosA

then time = 500/3cosA

a particle is moving along a straight line such that its position varies with time t as x=6α [ t+ αsin (t/α)

where x is its position in metre, t is time in s and α is a positive constant

The particle comes to rest at time t = (in terms of α and π)

Asked By: SWATI KAPOOR 3 Month ago

differentiating given x w. r. t. t

dx/dt will be v

for rest v = 0

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a vector a which has magnitude 8 is added to a vector B which lies on x-axis. The sum of these two vectors, lies on y-axis and has a magnitude twice of the magnitude of B. The magnitude of vector B is

Asked By: SWATI KAPOOR 3 Month ago

let a = 8cosAi+8sinAj and B = bi

sum of the two =  8cosAi+8sinAj+bi

it is given as 2bj

so   8cosAi+8sinAj+bi = 2bj

so   (8cosA+b)i+8sinAj = 2bj

now on comparing coefficient of i and j we get

cosA = -b/8 and sinA = 2b/8

now use sin2A +cos2A = 1

Physics >> Mechanics part 1 >> Kinematics Medical Exam

the forces F1 and F2 are acting perpendicular to each other at a point and have resultant R. If force F2 is replaced by R2 - F12/F2 acting in the direction opposite to that of F2, the magnitude of resultant

Asked By: SWATI KAPOOR 3 Month ago

F1+ F22 = R2  (1)

now for second condition

F1+ [(R2 - F12)/F2]2  = R12          R1 is new resultant

on putting the value of Rfrom first eq. we get

F1+ [ F22/F2]2 = R12

so R = R1

A sleeping cat and a sleeping dog are initially at a distance 'l' metres. As soon as the dog wakes up, the cat runs in the horizontal direction with constant velocity of u m/s. Immediately the dog chases the cat with constant speed of v m/s. Initially the dog was facing the north direction towards cat. The cat starts running in the east direction. Assuming the dog aims at the cat with constant speed v m/s, find the time after which the dog chases the cat.

see video for this solution in you tube by the name iitbrain.com

video:  i e irodov 1.13

Sir, can third law of Newton  be derived from second law??

actually as we all know that second law is real law so first  & second law can be derived,  but on the other side it is written that they are THE LAWS ARE INDEPENDENT THUS CAN'T BE DERIVED FROM ANY OTHER LAW (acc to HC Verma)

sir sometime ans is yes while sometime no , in different books different ans , i consulted this query to many  other teachers also but some favours while some teachers not , so what you suggest?

is this depends upon questn setting person

Asked By: SARIKA 3 Month ago

THE LAWS ARE INDEPENDENT

a particle moving in a straight line with an initial velocity u is subjected to a constant acceleration,a. Show that the distance traveled by the particle in the nth second is; Sn=u+a(n-0.5)
Asked By: KAGGWA BEN 3 Month ago

distance covered in n sec. = un+an2/2   (1)

distance covered in n-1 sec. = u(n-1)+a(n-1)2/2    (2)

so sn = (1) - (2)

put equation (1) and (2) and get the answer

The temperature of a perfect black body

is 1000k and its area

is 0.1m2 . the heat radiated by it in 1 minute in joule is

Asked By: HASITHA.KOTTA 3 Month ago

Q/At = σT4

now solve

Physics >> Mechanics part 1 >> Kinematics Medical Exam

Time of flight of a projectile thrown from ground is 8√5 s. It will rise up to a height of.........

T = 2usinθ/g

by formula calculate usinθ

then put in H formula

A resistor of 10kΩ having tolerance 10 % is connected in series with another resistor of 20 kΩ having tolerance 20 %. The tolerance of the combination will be approximately.

Asked By: SWATI KAPOOR 3 Month ago

resultant = (10±1)+(20±4) = 30±5

so tolerance = 5*100/30 = 50/3 = 16.67 %

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A body is projected at some angle with a velocity of 100m/s and it takes 5 second to reach the ground. The change in its velocity for the whole motion is ........ [g=10 m/s2]

Asked By: SWATI KAPOOR 3 Month agoSolved By: AVENA
Physics >> Mechanics part 1 >> Kinematics Medical Exam

A projectile is projected with velocity u= ai+bj from ground if acceleration due ti gravity is g, then the change in velocity of the projectile in second of projection is

Asked By: SWATI KAPOOR 3 Month ago

for t sec of projection v = u + at so v = ai+bj-gtj

now calculate v-u then mod

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A particle moves in the x-y plane according to the relation x= Kt and y= Kt(1-dt), where K and d are positive constants and t is time. What is the equation of the trajectory of the particle?

Asked By: SWATI KAPOOR 3 Month agoSolved By: AVENA
Physics >> Mechanics part 1 >> Kinematics Medical Exam

A shell at rest at large height explodes into two parts which move horizontally with speeds v1 and v2. After what time their instantaneous velocities are perpendicular?

Asked By: SWATI KAPOOR 3 Month ago

iitbrain.com in you tube

video name i e irodov problem 1.11

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A particle moving in uniform circular motion undergoes an angular displacement α (less then 360°) from point P and Q. Then angle between average velocity from P to Q and velocity at Q is........

Asked By: SWATI KAPOOR 3 Month ago

as clear from the figure that angle is a/2

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A particle moves in the plane xy with velocity v = ai + bxj, where i and j are the unit vectors of the x and y axes, and a and b are constants. At the initial moment of time the particle was located at the point x = y = 0. Find:
(a) the equation of the particle's trajectory y(x);
(b) the curvature radius of trajectory as a function of x.

Asked By: SWATI KAPOOR 3 Month ago

see the video in you tube by the name iitbrain.com

video i e irodov 1.35

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A ball is thrown up with some velocity after time t second it is at height h from the ground which is given by h = at -1/2 bt2. The dh/dt is zero at t equal to

Asked By: SWATI KAPOOR 3 Month ago

dh/dt = a - bt

so for dh/dt = 0

t = a/b

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A ball is thrown up with velocity 20m/s relative to ground in open lift moving up with speed 10m/s at time of throwing and has an acceleration of 2 m/s upward, ball meets lift after

Asked By: SWATI KAPOOR 3 Month ago

relative to lift

u of the ball = 20-10 = 10

a = 10-(-2) = 12 downward

and s = 0 because ball returns to initial point

now use s = ut + 1/2 a t2

Physics >> Mechanics part 1 >> Kinematics Medical Exam

Velocity of a particle is given by v= 3-t m/s. The distance travelled by particle in 1st four second is

Asked By: SWATI KAPOOR 3 Month ago

04 |v|dt  = 0(3-t)dt + 34(t-3)dt

now solve

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A bus is begins to move with an acceleration of 1 m/s2. A boy who is 48 m behind the bus starts running  at 10 m/s towards the bus. After what time bus will cross the boy?

Asked By: SWATI KAPOOR 3 Month ago

according to the given condition

1/2 t2+ 48 = 10t

solutions of this eq. = 12, 8

so boy will cross the bus after 8 sec and then bus will cross the boy after 12 sec from start.

Physics >> Mechanics part 1 >> Kinematics Medical Exam

The acceleration of a particle, varies with time according to the relation                     a=-mw2sinwt.The displacement of this particle at a time t will be

1) m sin(wt)

2) mwcos(wt)

3) mwsin(wt)

4) -1/2(mw2sinwt)t2

Asked By: SWATI KAPOOR 3 Month ago

a = dv/dt = -mw2sinwt

so   ∫dv = -mw2sinwtdt

so v = mwcoswt + C

at t=0, v=0 so 0 = mw+C or C = -mw

so v = -mw(1-coswt)

similarly put v = ds/dt and integrate again

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A motor boat going down stream ,overtakes a floating object in water .One hour later ,the motor boat turned back .If speed of motor boat in still water is constant and flow velocity is also assumed constant,motor boat will again pass the floating object after time 't ' given by

1)Greater than 2 hrs

2)Equal to 2 hrs

3)less than 2 hrs

4)less than 1 hr

Asked By: SWATI KAPOOR 3 Month ago

see video in you tube under the name iitbrain

video i e irodov 1.1

time will be 1 hour

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A paper weight is dropped from the roof of a 35 storey building each storey being 3m high. It passes the ceiling of the 20th storey at x m/s [g=10 m/s2]. Find x.

Asked By: SWATI KAPOOR 3 Month ago

total height = (35-20+1)*3 = 48 m

now solve

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A lift with open top is moving up with acceleration f. A body is thrown up with speed u relative to lift and it comes back to lift in time t. Then speed u is ...

{g = acceleration due to gravity}

Asked By: SWATI KAPOOR 3 Month ago

relative acc. = g+f

and relative velocity = u

now solve

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A projectile is thrown with speed 40 ms-1 at angle θ from horizontal. It is found that projectile as at same height at 1s and 3s. What is the angle of projection?

Asked By: SWATI KAPOOR 3 Month ago

It is found that projectile as at same height at 1s and 3s, so half time of flight = 2 sec

now solve

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A particle is thrown with a velocity of u m/s. It passes A and B at time t1 = 1s  and t2 = 3s. The value of u is (g=10 m/s2).

Asked By: SWATI KAPOOR 3 Month ago

question is not complete

Physics >> Mechanics part 1 >> Kinematics Medical Exam

When a force F acts on a particle of mass m, the acceleration of particle becomes a. Now if two forces of magnitude 3F and 4F acts on the particle (both are at an angle of 90° from mass m) simultaneously , then the acceleration of the particle is ..............

Asked By: SWATI KAPOOR 3 Month ago

resultant force = 5F

so acceleration = 5a

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A man moves in an open field such that after moving 10m on a straight line, he makes a

sharp turn of 60° to his left. Find the displacement after 8 such turns

Asked By: SWATI KAPOOR 3 Month ago

draw a hexagon

just after 8 such turn displacement = 10√3

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a particle is moving eastwards with a speed of 6m/s. After 6s, the particle is found to be moving with same speed in a direction 60° north of east. The magnitude of average acceleration in this interval of time is ..............

Asked By: SWATI KAPOOR 3 Month ago

initial velocity = 6i

final velocity = 6cos60i+6sin60j

now solve

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a body is dropped from a certain height h (h is very large) and second body is thrown downward with velocity of 5 m/s simultaneously. What will be difference in heights of the two bodies after 3s.

Asked By: SWATI KAPOOR 3 Month ago

g is acting on both bodies so difference = 5*3 = 15 m

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a stone thrown upward with a speed u from the top of a tower reaches the ground with a velocity 4u. The height of the tower is .........

Asked By: SWATI KAPOOR 3 Month ago

(4u)2 = (-u)2+ 2gh

solve

Physics >> Mechanics part 1 >> Kinematics Medical Exam

The velocity of a body depends on time according to the equation v = (t2/10) + 20 . The body is undergoing -

1. Uniform acceleration

2. Uniform retardation

3. Non-uniform acceleration

Asked By: SWATI KAPOOR 3 Month ago

dv/dt = 2t/10

so a depends on t

option (3)

Physics >> Mechanics part 1 >> Kinematics Medical Exam

When a particle is thrown vertically upwards, its velocity at one third of its maximum height is 10√2 m/s. The maximum height attained by it is......

Asked By: SWATI KAPOOR 3 Month ago

remaining height = 2h/3

so 0= (10√2)- 2g(2h/3)

solve

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A body falling from a vertical height of 10m pierces through a distance of 1m in sand. It faces an average

retardation in sand equal to?

[Answer is in terms of 'g' i.e acceleration due to gravity ]

Asked By: SWATI KAPOOR 3 Month ago

velocity at the time of impact

v2 = 02 + 2g10

now in sand this velocity becomes 0 in 1 m

so 02 = 20g - 2a(1)

so a = 10g

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a body thrown vertically up with initial velocity 52 m/s from the ground passes twice a point at h height above at an interval of 10s. The height h is...........

(g=10m/s2)

Asked By: SWATI KAPOOR 3 Month ago

from that point to topmost point, time taken = 10/2 = 5 sec

so velocity at that point = 50 m/s

now use

522 = 502- 2gh

solve

A bus starts moving with an acceleration of 2m/s2. A cyclist 96m behind the bus starts simultaneously towards the bus at 20 m/s . After what time cyclist will be able to overtake the bus?

Asked By: NISHANT JAIN 3 Month ago

let after time t

then distance covered by cyclist in this time = 20t

and by bus = 2t2 / 2 = t2

so according to the given condition

20t = 96+t2

so t = 8,12

after 8 sec cyclist overtakes bus and after 12 sec bus overtakes cyclist

when two plane mirror inclined to each other at an angle 60degree , the number of image =?

please explain with ray diagram .

Asked By: ASHOK SOLANKI 3 Month ago

angle is 60

if object is placed symmetrical then images = 360/60 - 1 = 5

if unsymmetrical then 360/60 = 6

a boat is moved uniformily by pulling with force p=240n,q=200n .what must be the inclination of the resultent force with p and q to have resultent r=400.

Asked By: RAJITH 3 Month agoSolved By: ARICA

In this problem r is the resultant of p and q, let the angle between r and p is α and r and q is β then

p = r sin β/sin(α+β)       (1)          and                         q = r sinα/sin(α+β)           (2)

so p/q = sinβ/sinα

and according to given condition p/q = 6/5 so sinβ = 6k and sinα = 5k

now obtain cos function and solve it.

What is chock coil?
Asked By: ROHITGARG 3 Month agoSolved By: ARICA

a cyclist is moving due east with a velocity of 10 km/h there is no wind air and rain appear to fall at degree vertival calculate the speed of rain.

Asked By: ARVIND 3 Month ago

Question is not submitted properly, angle is not given

let the angle is θ degree

then v(man) = 10i

and v(rain) = -vj                          i and -j are the directions for man and rain

so v(rain w.r.t. man) = -vj-10i

so tanθ = 10/v so v = 10 cotθ

θ is measured from vertical

A body is moving on a circle of radius 80m with a speed 20m/s which is decreasing at the rate of 5m/s2 at an istant. What is the angle made by its acceleration with its velocity?

Asked By: SWATI KAPOOR 3 Month ago

You should write that calculate

What is the angle made by its acceleration with its velocity at the instant for which conditions are given.

solution

centripetal acceleration = 20*20/80 = 5 m/s2

tangential acceleration = 5 m/s2

so angle = tan-1(5/5) = 450

A body is projected with a velocity of 20m/s and at an angle of 30° with the ground. The change in the direction of its velocity cannot be (during its motion).

Asked By: SWATI KAPOOR 3 Month ago

I think options are necessary for this problem.

but if we analyse we can say that the angle will be between 0 and 120 degree

Q.On a spring balance,

(i)10N force is applied on both the ends

(ii)10N force is applied on one end & no force on the other end.

(iii)10N is applied on one end and 20N is applied at the other.

Calculate the reading of the spring balance in each case.

Asked By: ASUTOSH SAHOO 3 Month ago

i) 10 N

ii) 0 N, and it will be accelerated

iii) 10 N, and it will be accelerated

Sir,

please explain in detail how friction helps in walking?Please involve all the action and reaction forces involved in the process..Also what is the reason that we can't walk on a frictionless surface?

Asked By: ASUTOSH SAHOO 3 Month ago

in accelerated motion friction will be forward and due to the same reason we take small steps when we walk in ice due to reduce friction. Without friction you can not accelerate  or retard on the surface.

Can this question be answered quick ? a man runs at a speed of 4m/s to overtake a standing bus. when he is 6m behind the door the bus moves forward and continues with constant acceleration of 1.2m/s^2. how long does it take for the man to go to the door ? if he was initially 10m behind the door, can he catch the bus?

Asked By: BRENDA JENNIFER 4 Month ago
Physics >> Mechanics part 1 >> Kinematics Medical Exam

a train starts from a station with acceleration 0.2 m/s2 on a straight track and then comes to rest after attaining maximum speed on another station due to retardation 0.4m/s2. if total time spent is half an hour, then distance between two stations is {neglect length of train}

1. 216 km

2. 512 km

3. 728 km

4. 1296 km

Asked By: SWATI KAPOOR 4 Month ago
Physics >> Mechanics part 1 >> Kinematics Medical Exam

a bullet after entering a wooden block at rest covers 30 cm inside it and loses half of its velocity after how much further distance will it come to rest?

Asked By: SWATI KAPOOR 4 Month ago
Physics >> Mechanics part 1 >> Kinematics Medical Exam

The velocity of a BODY MOVING ALONG x axis is given by v=( 36+2x)1/2 where v is in m/s and x is in metre. Find distance travell by it 2nd second.

Asked By: SWATI KAPOOR 4 Month ago

a body travels 2 m in 2nd second and 6 m in the next four seconds . what will be the distance travelled in the 9th second.

Asked By: AMAN KUMAR MISHRA 4 Month agoSolved By: SWATI KAPOOR

Two particles of masses m and 2m with charges q and 2q are placed in a uniform elecric field E and allowed to move for the same time. The ratio of their kinetic energies will be

a) 2 : 1
b) 1 : 2
c) 4 : 1
d) 1 : 4

Asked By: JINCY JACOB 4 Month ago

Two particles of masses m and 2m with charges q and 2q are placed in a uniform elecric field E and allowed to move for the same time. The ratio of their kinetic energies will be

a) 2 : 1
b) 1 : 2
c) 4 : 1
d) 1 : 4

Asked By: JINCY JACOB 4 Month agoSolved By: SHANTANU BARIAR

In equation y = x2 cos2 2π (βγ/α) , the units of x, α , β are m , s-1 ans (ms-1)-1 respectively. The units of y and γ are ....?

Asked By: SWATI KAPOOR 4 Month agoSolved By: AKSHAY TIWARY

A particle is projected with an initial velocity of 200 m/s in a direction making an angle of 30 with the vertical . The horizontal distance covered by the particle in 3 seconds is ?

Asked By: RASHMITHA VARMA 4 Month agoSolved By: AMINTA CAMPESTARIS

why does a paper ball does not go more distance with comparison with a cosco ball.

Asked By: AMANVERMA 4 Month agoSolved By: INNOCENT STUDENT

when we throw a shotput ball it covers a very less distance and when we throw a rubber ball it covers a larger distance.

the reason behind this well known to everyone that the shotput ball has more mass as compared to the rubber ball.

But when throw a paper ball it covers the least diatance  why?

Asked By: SANTANU VERMA 4 Month ago

for this motion 0-R = ma

so retardation = R/m

for less mass retardation will be more

in the case of shotput

mu + impulse given = mv

so v = u + {impulsegiven/m}

so more mass will gain less velocity in comparison to less mass on applying same impulse.

A particle moves with velocity v along a parabolic path y=ax2 ,where a is a positive constant. Find the acceleration w of the particle at pint x=0.

(Plz Explain in detail, Fundamental_Laws_of_Mechanics IRODOV Problem 1.8)

Asked By: ABHAY 4 Month ago

two particles A and B are projected from ground towards each other with speeds 10 m/s and 52 m/s at angle 30° and 45° with horizontal from two points separated by a distance of 15 m. will they collide or not?

Asked By: RISHAV MORIA 4 Month ago

two particles A and B are projected from ground towards each other with speeds 10 m/s and 7.071 m/s at angle 30 and 45 with horizontal from two points separated by a distance of 15 m. will they collide or not?

Asked By: RISHAV MORIA 4 Month ago

two particles A and B are projected from ground towards each other with speeds 10 m/s and 7.071 m/s at angle 30 and 45 with horizontal from two points separated by a distance of 15 m. will they collide or not?

Asked By: RISHAV MORIA 4 Month ago

how to solve equivelent resistance in the cube

Asked By: JITENDRA PANWAR 4 Month ago
Asked By: AARSHI 4 Month ago
Force F is applied on upper pulley. If F=30t N where t is time in second. Find the time when 4kg loses contact with floor
Asked By: AARSHI 4 Month ago
an elevator with out a ceiling is ascending up with an acceleration of 5m/s^2 .a boy on the elevator shoots a ball in vertically upward direction from a height of 2m above the floor of elevator at this instant the elevator is moving up with a velocity of 10m/s and the floor of elevator is at the height of 50m from ground the initial speed of the ball is 15m/s w.r.t the elevator then the time in which the ball strikes the floor of the elevator?
Asked By: RAKESH PARIDA 4 Month ago
an elevator with out a ceiling is ascending up with an acceleration of 5m/s^2 .a boy on the elevator shoots a ball in vertically upward direction from a height of 2m above the floor of elevator at this instant the elevator is moving up with a velocity of 10m/s and the floor of elevator is at the height of 50m from ground the initial speed of the ball is 15m/s w.r.t the elevator then the time in which the ball strikes the floor of the elevator?
Asked By: RAKESH PARIDA 4 Month ago
an elevator with out a ceiling is ascending up with an acceleration of 5m/s^2 .a boy on the elevator shoots a ball in vertically upward direction from a height of 2m above the floor of elevator at this instant the elevator is moving up with a velocity of 10m/s and the floor of elevator is at the height of 50m from ground the initial speed of the ball is 15m/s w.r.t the elevator then the time in which the ball strikes the floor of the elevator?
Asked By: RAKESH PARIDA 4 Month ago

pls tell me hc verma Qu. 33 and 35

Asked By: MAYANK GOYAL 4 Month ago
Physics >> Mechanics part 1 >> Kinematics Engineering Exam

A small block of weight W rests on a smooth plane of inclination θ to the horizontal. Find the value of θ if:

a force of W/2 parallel to the plane is required to keep the block in equilibrium?
Asked By: NARDOS DEMERE MELAKU 4 Month ago

a partical of mass m and carrying charge q starts moving around a fixed charge q2 along a circular path of radius r find period of revolution

Asked By: NISHANT KUMAR 5 Month ago

QUE. A charge "q1" is placed at the centre of a spherical conducting shell of radius 'R" .Conducting shell has a total charge of "q2" .Electrostatic potential energy of the system is???

Asked By: SANKET DAS 5 Month ago

why all teachers  behave so strangely when a student needs their guindance highly, are all people are so selfish that they do not solve queries when the doubts and exam , entrance are on head , i think doubts bubbling in students are never ending process so teacher should also understand this thing and should not left student lonely at the time of tests , if they leave institute then it does not mean that the bonding between teacher and student is broken , just because of a teacher who didnt solve query of a student wen required urgently , a student was not able to solve that question in exam that leads to a wide difference in rank of that student just because of one question , DO U THINK IT IS WRONG FOR A TEACHER TO DO SO ,  SO PLZ DELETE THIS COMMENT AND NEVER DO THIS WITH UR STUDENTS WHO ARE WITH U ON THIS SITE if u do this then it can bring the great satisfaction to the site followers of iitbrain, i think u r also a teacher and can understand the feelings of all  sitefollowers

Asked By: CAPIT OLERACEA ONCI 5 Month ago

QUE. A planet of mass "m" has an elliptical orbit of semimajor axis and semiminor axis "a" & "b" respectively. If the time period of the planet around the sun is "c', then what wl b its angular momentum about sun???

Asked By: SANKET DAS 5 Month ago

the initial velocity of a body moving along a straight line is 7m/s.it has a uniform acceleration of 4m/s2.what is the distance covered by in the 5th second of motion?.. solve

Asked By: SUKHWINDER SINGH 5 Month ago

can the linear speed of two objects be different if they have the same angular speed?

Asked By: VIBHU GOEL 5 Month ago

angular speed depends on the distance from pivot also so v may be same or different

formula affilated is v = r ω

A body is projected with a velocity 'u' making an angle α with the horizontal. Its velocity when it is perpendicular to the initial velocity vector is:

A. ucotα B. utanα C. usinα D. ucosα

Asked By: GAUTHAM GANESH 5 Month ago

component of gravity perpendicular to the final direction is gsinθ so by equation

v=u+at

0 = u -gsinθt

so t = u/gsinθ

now along final direction v = 0+gcosθt             on putting the value of t we get v = gcosθu/gsinθ = ucotθ

A particle when thrown,moves such that it passes from same height at 2sec. And 4 sec, then what is the height?
Asked By: ASHISH SHUKLA 5 Month ago

Due to gravity a freely falling body covers the distances in the ratio 1:3:5:7:9..............................so

if a particle passes at the same point twice (2nd and 4th sec),  then it will be at heightest pont in 3rd sec. so height = 5+15+25 = 45 meter

pl give me solution of problem of I E Irodovw question no 1.91

two identical balls of same charge hanged with athread suspended at an angle theta of same charge.find the mass of identical ball

Asked By: SAI KRISHNA 9 Month ago

Find the location of the center of mass of a three particle system. Given that all the three particles have identical mass and are located at (0,0,0) , (a,0,0) and (2a,0,0).

Asked By: SUKHIN VINAYAK 10 Month ago

2 tuning forks when sounded together produces 3 beats per second, on loading one of them with little wax 20 beats are heard in 4 second. find its frequency if that of other is 386 hz?

Asked By: KANISHK AGGARWAL 10 Month ago

what is projectile motion?

Asked By: FAITH MWONGELI 10 Month ago

A particle thrown in such a way that velocity and acceleration makes variable angle with each other.

In some cases angle can be fixed

what is defination of polarization

Polarisation is the phenomenon to turn light in a particular direction by any means

Asked By: VIRAT 10 Month ago

A bar magnet of magnetic moment 'm' and moment of inerta 'I' (about an axis passing through centre of mass and perpendicular to the magnet) is turned through 900 about the axis of suspension, to be at right angle to a uniform magnetic field B and then released. What is the angular velocity of the magnetwhile passing through the direction of the field ??

Asked By: VIRAT 10 Month ago
Asked By: NIKUNJ BAJPAI 10 Month ago

Derive an expression for the gravitational field due to a uniform rod of length L and mass M at a point on its perpendicular bisector at a distance d from the centre.

Asked By: TANAY NARSHANA 10 Month ago

Acceleration of point x=2m of a transverse wave is 5ĵ m/s^2 (5 m/s^2 in +ve y direction) and slope of waveform is given by dy/dx = 5sin[(pi/12)x] {where pi=22/7}. What is the speed of the particle at x=2?

Asked By: LETTERTOKNOW 10 Month ago

Acceleration of point x=2m of a transverse wave is 5ĵ m/s^2 (5 m/s^2 in +ve y direction) and slope of waveform is given by dy/dx = 5sin[(pi/12)x] {where pi=22/7}.

Asked By: LETTERTOKNOW 10 Month ago

Acceleration of point x=2m of a transverse wave is 5ĵ m/s^2 (5 m/s^2 in +ve y direction) and slope of waveform is given by dy/dx = 5sin[(pi/12)x] {where pi=22/7}.

Asked By: LETTERTOKNOW 10 Month ago

a 150 kg car engine developes 500 w for each kg .what force it exerts in moving car at speed of 20 m/sec

Asked By: ANGELLA NICHOLSON 10 Month ago

a body starts with a velocity of 9kmh and 2 seconds later has a velocity 45 km h .find the acceleration and the distance travelled

Asked By: JUMA AL GHUEFEILI 10 Month ago

a body starts with a velocity of 9kmh and 2 seconds later has a velocity 45 km h .find the acceleration and the distance travelled

Asked By: JUMA AL GHUEFEILI 10 Month ago

a body starts with a velocity of 9kmh and 2 seconds later has a velocity 45 km h .find the acceleration and the distance travelled

Asked By: JUMA AL GHUEFEILI 10 Month ago

a body starts with a velocity of 9kmh and 2 seconds later has a velocity 45 km h .find the acceleration and the distance travelled

Asked By: JUMA AL GHUEFEILI 10 Month ago
Asked By: SAHBIR.PATEL@GMAIL.COM 10 Month ago
Asked By: SAHBIR.PATEL@GMAIL.COM 10 Month ago

bulb of thermometer made up of mercury is cylinderical in shape , it is not spherical  why/?? ie why cylinderical shaped bulb is more senstive 2 temperature how??

Asked By: SARIKA SHARMA 10 Month ago

is its force dat depends on acceleratn or its acceleratn that depends upon force??

Asked By: SARIKA 10 Month ago

both are proportional to each other

1>What is the distance covered by a point object projected with velocity  "U" making an angle theta with the horizental?

Asked By: MANOJ KUMAR 10 Month ago

formula for calculating distance of a curve is ∫ds

where ds2 = dx2 + dy2

and equation of projectile is

y = xtanθ-(1/2)(gx2/u2cos2θ)

try to solve

if not solved give qurey i will give the complete solution

for an aperture of size a illuminated by a parallel beam of light having wavelength λ the fresnel distance is

ans a^2/λ       what is fresnel dist.??

Asked By: SARIKA SHARMA 11 Month ago

fringe width β = λD/d

for β = d , D is called fresnel distance

so d2 = λD

so D = d2/ λ

now change d by a

Physics >> Optics >> Refraction Medical Exam

if fv and fr are d focal lenth of concave lens than which one vyl be gr8ter

ans given is fv> fr  why, as  wavelength is directly proptional to f isn't it shld be fr>fv

Asked By: SARIKA SHARMA 11 Month ago

a 4kg box slide down 37dgree under the action of gravity. If the box is slides down in the plane .Find the coefient of static friction

Asked By: MELAKU ABEBAW KASSIE 11 Month agoSolved By: SARIKA SHARMA
What is Potential Energy?
Asked By: SOURAV MAHAPTRA 11 Month agoSolved By: SARIKA SHARMA

A ball falls vertically on to a floor, with momemtum p and then bounces repeatedly, the coefficient of restitution is e. What is the total momemtum imparted by the ball to the floor.

.....Thank you

Asked By: PRITOM SHARMA 11 Month ago

The kinetic energy of a particle moving along a cirle of radius 'r' depends on the distance  covered "s" as T=as2 ,where a is a constant. Find the force acting  on the particle as a function of s.

---- sir, hope you will  reply the anrwer soon.

Asked By: PRITOM SHARMA 11 Month ago

a wire of desity 900 kg/m3 is strechded between two clamps 1m apart while subjected to an extention of 0.05 cm.what is the lowest frequency of the transverse vibration in the wire.assuming young's modulus y=9×10 dyne/m2.

Asked By: DAWIT SOLOMON 11 Month ago

a wire of desity 900 kg/m3 is strechded between two clamps 1m apart while subjected to an extention of 0.05 cm.what is the lowest frequency of the transverse vibration in the wire.assuming young's modulus y=9×10 dyne/m2

Asked By: DAWIT SOLOMON 11 Month ago

is law of conservation of charge voilated in space power generator

Asked By: SYED ILYAS 11 Month agoSolved By: SARIKA
Physics >> Mechanics Part 2 >> Gravitation Medical Exam

Q- The speed of a planet is v when it is at minimum distance r from sun. Find it's speed when it will be at maximum distance R from sun?

Ans: vr/R        how?

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

Q-1:- A point mass m is located at a distance r from a uniform rod of infinite length and linear mass density λ. Find the gravitational force of attraction between point mass and rod?                                                                                                                                                                  Ans- 2Gλm/r    How?

Asked By: TAMAL SINHABABU 1 year ago

A 5000kg rocket is for vertical firing.The exhaust speed is 800m/s.To give an upward acceleration of 20m/s2 , the amount of gas ejected per second to supply the needed thrust is(g=10m/s2)

Asked By: HARISH 1 year ago

A 5000kg rocket is for vertical firing.The exhaust speed is 800m/s.To give an upward acceleration of 20m/s2 , the amount of gas ejected per second to supply the needed thrust is(g=10m/s2)

Asked By: HARISH 1 year ago
A ball falls on an incline plane of inclination theta from a height h above the point of impact and makes an elastic collision.where will it hit the plane again if coefficient of restitution is e.
Asked By: ABHISHEK RAAZ 1 year ago
Asked By: PREM NATH TIWARI 1 year ago

In the figure shown man is balanced by counter weight of same mass. He starts to climb the rope
with an accelerator of 2 m/s2 w.r.t. rope. What is the time after which he reaches the pulley.

Asked By: PREM NATH TIWARI 1 year ago
Asked By: PREM NATH TIWARI 1 year ago

PLEASE TELL ME ABOUT FREE BODY DIAGRAM AND HOW TO DO IT

Asked By: KRRISH 1 year ago

Irodov problem 2.2
Two identical vessels are connected by a tube with a valve letting the gas pass from one vessel into the other if the pressure difference >= 1.1 atm. Initially there was a vacuum in one vessel while the other contained ideal gas at a temperature t1= 27 degree celsius and pressure p1= 1 atm. Then both vessels were heated to a temperature t2=107 degree celsius. Up to what value will the pressure in the first vessel( which had vacuum initially) increase?

Asked By: PILLAI IYAPPAN 1 year ago

A pendulum bob of mass m is suspended at rest. A constant horizontal force F = 10N starts acting on it. The maximum angular deflection of stringis what ?

Asked By: H. SHASHANK KUMAR 1 year ago

1-the mean free path of electrons in a metal is 4*10^-8.the elecric field which can give can give on an average 2 eV energy to an elecron in a metal will be ?           ans ---5*10^7

Asked By: SHWETA BHARDWAJ 1 year ago
A moving body of mass m and velocity 3km/hr collides a rest body of mass 2m and sticks to it.now the combine mass starts to move.what will be the combine velocity?plz explain it briefly.
Asked By: PREMJIT KHWAIRAKPAM 1 year ago

I am confused with boat and river problem. When we say relative velocity of point particle A wrt particle B it is easy to visualize, but here we have point particle A as boat and river is not point particle. And velocity of boat A is actually governed by velocity of river unlike other relative velocity problems. So it means that some force is acting on boat. Also VBW means water is stagnant and only boat is moving, so boat should move perpendicular to river to reach opposite bank. Now assuming river is flowing towards right with velocity nu, and boat is sailing with velocity u, then VBW should point straight to other side that is perpendicular to river velocity.

Asked By: ANJUM S KHAN 1 year ago

a solid sphere of mass 'm' and radius 'r' is placed on a plank of equal mass, which lies on a smooth horizontal surface .the sphere is given a sharp impulse in the horizontal direction so that it strats sliding with a speed of 'v' find the time taken by the sphere to start pure rolling on the plank

Asked By: ROHIT 1 year ago

1-the electric field between two parallel plates of an oscilloscope is 1.2*10^5V/m.if an electron of energy 2keV enters at right angle to the field ,what will be its deflection if the plates are 1.5 cm long?(3.375mm)

Asked By: SHWETA BHARDWAJ 1 year ago

An object is moving along the x axis with position as a function of timegiven by x=x(t).
Point O is at x=0. The object is definetely moving towards O when..

a) dx/dt < 0
b) dx/dt > 0
c)d(x2)/dt < 0
d)d(x2)/dt > 0

Asked By: MOHIT SAINI 1 year ago
What is mean by a system
Asked By: JASEEM A RAHMAN P 1 year ago
Physics >> Mechanics part 1 >> Kinematics Medical Exam

Physics >> Mechanics part 1 >> KinematicsMedical Exam

min no. of unequal vectors which can give zero resultant is_________?? ans 3

where as option four is also in ques so,Sir the query is that here ques is for coplanar or for non coplanar as .it is not mention in the ques itself.

Asked By: SARIKA SHARMA 7 Day ago

A . B=0 & A.C=0 , then how it will be proved that A is parallel to B x C ?? (here A,B,C are vectors, Ok)

Asked By: SARIKA SHARMA 7 Day ago

resultant of two forces ,one double the other in magnitude ,is perpendicular to smaller of the two forces .then < b/w 2 forces??

ans 120o

Asked By: SARIKA SHARMA 7 Day ago

Q the resultant of two forces 3P & 2P is R, if first force is double then resultant is also doubled. then the < b/w two forces=??

ans 1200

Asked By: SARIKA SHARMA 7 Day ago

Asked By: SARIKA 1 year ago

what is the principle couse of gravity

Asked By: SSANKULP CLASSES 1 year agoSolved By: SARIKA

a child is sitting on a swing.its minimum and maximum heights from the ground are 0.75m and 2m respectively, its maximum speed will be

Asked By: SHIVANI MALIK 1 year ago

a car moving with a speed of 40km/h can be stopped by applying breakes after atleast 2m . if the same car is moving with speed of 80km/h, what is the minimum stopping distance?

ans=8m

Asked By: SHIVANI MALIK 1 year ago

A  rubber ball is dropped from a hieght of 5m on a plane, where the acceleration due to gravity is not known . on bouncing, it rises to1.8m . the ball loses its vel. on bouncing by a factor of

ans=2/5

Asked By: SHIVANI MALIK 1 year ago

a metal ball of mass 2kg moving with speed of 36km/h has a head on collision with a stationary ball of mass 3kg. if after collision both the ball move together, then loss in K.E due to collision is

ans=60J

Asked By: SHIVANI MALIK 1 year ago

a moving body of mass m and vel. 3m/s collids with a rest body of mass 2m and sticks to it.now combined mass start to move . what will be the combined velocity

ans=1m/s

Asked By: SHIVANI MALIK 1 year ago

a man of 50kg is standing in agravity free space at a height of 10m above the floor. he throws a stone of mass 0.5kg downwards with a speed of 2m/s. when the stone reaches the floor, the distance of the man sbove the floor will be

ans=10.1m

Asked By: SHIVANI MALIK 1 year ago

a block of mass M is attached to the lower end of a virtical spring. the spring is hung from a ceiling and a force constant value K. the mass is released from rest with a spring initially unstrrtched. the maximum extention produced in the length of the spring will be

ans=2 Mg/k

Asked By: SHIVANI MALIK 1 year ago

a roller coaster is designed such that riders experence weightlessness as they go round the top of hill whose radius of curvature is 20m. the speed of the car at the top of the hill is between

ans=14m/s and 15m/s

Asked By: SHIVANI MALIK 1 year ago
why can't we use scilencer in air plane to reduce its noise ?

A long plank of mass M rests upon  a smooth horizontal surface. A thin circular ring (m,R) slips ( without rotation ) upon plank. The coefficient of friction between the wheel and plank is k. At  t = t s , the ring's slipping ceases and pure rolling starts upon the plank, then what is the  value of t = ?

Asked By: H. SHASHANK KUMAR 1 year ago

the mean free path of a molecule of He gas is α. Its mean free path along any arbitrary coordinate axis will be

Asked By: AVANTIKA PURI 1 year ago

The internal energy of 10 g of nitrogen at NTP is about

Asked By: AVANTIKA PURI 1 year ago

If α moles of a monoatomic gas are mixed with β moles of a polyatomic gas and mixture behaves like diatomic gas, then [ neglect the vibrational mode of freedom ]

Asked By: AVANTIKA PURI 1 year ago

An ideal gas undergoes a polytropic given by equation PVn = constant . If molar heat capacity of gas during this process is arithmetic mean of its molar heat capacity at constant pressure and constant volume then value of n is

Asked By: AVANTIKA PURI 1 year ago

nitrogen gas is filled in an insulated container. If α  fraction of moles dissociates without exchange of any energy , then the fractional change in its temperature is

Asked By: AVANTIKA PURI 1 year ago

If hydrogen gas is heated to a very high temperature, then the fraction of energy possessed by gas molecules correspond to rotational motion

Asked By: AVANTIKA PURI 1 year ago

the energy ( in eV ) possessed by a neon atom at 27 oC is

Asked By: AVANTIKA PURI 1 year ago

A box of negligible mass containing 2 moles of an ideal gas pf molar mass M and adiabatic exponent  γ moves with constant speed v on a smooth horizontal surface. If the box suddenly stops, then change in temperature of gas will be

Asked By: AVANTIKA PURI 1 year ago

The ratio of no of collisions per second at the walls of container by He and O2 gas molecules kept at same volume and temperature is ?

Asked By: AVANTIKA PURI 1 year ago

The ratio of no of collisions per second at the walls of container by He and O2 gas molecules kept at same volume and temperature is ?

Asked By: AVANTIKA PURI 1 year ago

for an ideal gas the fractional change in its volume per degree rise in temperature at constant pressure is equal to [ T is absolute temperature of gas ]

Asked By: AVANTIKA PURI 1 year ago

a vessel contains a non linear triatomic gas. If 50 % of gas dissociate into individual atom, then find new value of degree of freedom of freedom by ignoring the vibrational mode and any further dissociation.

Asked By: AVANTIKA PURI 1 year ago

a container is filled with a sample of gas having n molecules with speed a, 2a, 3a .......na. Find the ratio of average speed to root mean square speed.

Asked By: AVANTIKA PURI 1 year ago

Neon gas of a given  mass expands isothermally to double volume. What should be the further fractional decrease in pressure, so that the gas when adiabatically compressed from that state, reaches the original state?

answer is 1 - 2 ‾ 2/3

Asked By: AVANTIKA PURI 1 year ago

A container is filled with 20 moles of an ideal diatomic gas at absolute temperature T. When heat is supplied to gas temperature remains constant but 8 moles dissociate into atoms. Heat energy given to gas is

4 RT          6 RT             3 RT                5 RT

Asked By: AVANTIKA PURI 1 year ago

an ideal gas of volume v and pressure p expands isothermally to volume 16 V and then compressed adiabatically to volume V. The final pressure of gas is { γ = 1.5 }

Asked By: AVANTIKA PURI 1 year ago

which of the following can be coefficient of performance of refrigerator -

1       0.5          9                all of these

Asked By: AVANTIKA PURI 1 year ago

during the thermodynamic process for an ideal gas in which pressure is directly proportional to Volume

Δ T = 0     ΔQ=0      W<0      ΔU >0

which one is true?

Asked By: AVANTIKA PURI 1 year ago

A mixture of gases at NTP for which γ = 1.5  is suddenly compressed to 1/9 th of its original volume. The final temperature of mixture is

Asked By: AVANTIKA PURI 1 year ago

Two cylinders contain ideal monatomic gas. Same amount of heat is given to two cylinders. If temperature rise in cylinder A is T then temperature rise in cylinder B will be

Asked By: AVANTIKA PURI 1 year ago

An ideal gas with adiabatic exponent γ is heated at constant pressure. It absorbs Q amount of heat. Fraction of heat absorbed in increasing the temperature is

Asked By: AVANTIKA PURI 1 year ago

Morning breakfast gives 5000 cal to a 60 kg person. The efficiency of person is 30% . The height upto which the person can climb up by using energy obtained from breakfast is

Asked By: AVANTIKA PURI 1 year ago
Physics >> Mechanics part 1 >> Kinematics Medical Exam

min no. of unequal vectors which can give zero resultant is_________?? ans 3

where as option four is also in ques so,Sir the query is that here ques is for coplanar or for non coplanar as  .it  is not mention in the ques itself.

Asked By: SARIKA SHARMA 1 year ago
Physics >> Mechanics part 1 >> Kinematics Medical Exam

A . B=0 & A.C=0  , then how it will be proved that A is parallel to B x C ?? (here A,B,C  are vectors, Ok)

Asked By: SARIKA SHARMA 1 year ago

resultant of two forces ,one double the other in magnitude ,is perpendicular to smaller of the two forces .then < b/w 2 forces??

ans 120o

Asked By: SARIKA SHARMA 1 year ago

Q the resultant of two forces 3P & 2P is R, if first force is double then resultant is also doubled. then the < b/w two forces=??

ans  1200

Asked By: SARIKA SHARMA 1 year ago
Physics >> Mechanics part 1 >> Kinematics Medical Exam

A car travels at a speed of 60 km/hr due north and the other at a speed of 60 km/hr due east  . are the velocities equal? if no which one is greater

Asked By: KANISHK AGGARWAL 1 year ago

which physical quantity has its unit as LUX??

Asked By: SARIKA SHARMA 1 year ago

its illuminance

A person can throw a stone to a max distance of 100m.The greatest height to which he can throw the stone is
Asked By: GULSHAN BAJPAI 1 year agoSolved By: SARIKA SHARMA

a shell of mass 200 gm is ejected from a gun of mass 4kg by an explosion that generates 1.05kj of energy. the initial velocity of the shell is

ans-100m/s

Asked By: SHIVANI MALIK 1 year ago

a monkey of mass 20 kg is holding a vertical rope.the rope will not break when a mass of 25kg is suspended from it but will break if the mass exceeds 25kg. what is the maximum acceleration with which the monkey can climb up along the rope?

ans-2.5m/s2

Asked By: SHIVANI MALIK 1 year ago

a bullet is fired from gun .the force on the bullet is given by F=600-2*105 t, where F is in newton and t is in sec. the force on the bullet becomes zero as soon as it leaves the barrel.what impulse imparted to the bullet

ans-0.9Ns

Asked By: SHIVANI MALIK 1 year ago

a 5000 kg rocket is set for verticle firing. the exhaust speed is 800ms.to  give an initial upward acceleration of 20ms2, the amount of gas ejected per sec to supply the needed thrust will be

ans-187.5kg/s

Asked By: SHIVANI MALIK 1 year ago

a small particle of mass m=2kg moving with constant horizontal velocity u=10m/s strikesa wedge shaped block of mass M=4kg horizontally on its inclined surface.after collisoin particle starts moving up the inclined plane. calculate the velocity of wedge immediately after collision.

Asked By: SAHIL MUDGAL 1 year ago
Physics >> Optics >> Refraction Medical Exam

the diameter of aperture of planoconvex lens is 6 cm & its maxm thickness is 3mm . If the velocity of light in the material of lens is 2X 108m/s , then what will be its focal length?/

ans 30cm

Asked By: SARIKA 1 year ago
Physics >> Optics >> Refraction Medical Exam

2 thin similar convex glass pieces are joined together front to front with its rear portn silvered such that a sharp image is formed 20cm from the mirror . When the air b/w glass pieces is replaced by H2O (u=4/3) then image formed from the mirror is at a distance ______________??

ans 12cm

Asked By: SARIKA 1 year ago
Physics >> Mechanics part 1 >> Kinematics Medical Exam

a stone is dropped from a hieght h. it hits the ground with a certain momentum P. if the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by

ans-41%

Asked By: SHIVANI MALIK 1 year ago

A motorboat going downstream, passes a raft at point 'A'.t = 60 min later it turned back and after some time it passes the same raft at a distance of 6 k.m. from point 'A' . find the flow velocity assuming the duty of the engine to be constant.

Asked By: KANISHK AGGARWAL 1 year ago
Solution by manish sir

you can see video in you tube for this irodov problem 1.1

a body is projected at 40m/s from the horizontal ground at an angle 60 degree with the vertical. time at which it is moving perpendicular to its direction of motion is

Asked By: PRATIBHA 1 year ago

when particle will move perpendicular to its initial direction its velocity in its ititial direction will become 0. and component of gravity in that direction = gsin30

30 degree will be the angle of motion of particle from horizontal.

now use v = u + at,

a particle is projected at an angle of 60 degree with the horizontal at a speed of 30m/s. the time after which the speed of the particle remain half of the initial speed is

Asked By: PRATIBHA 1 year ago

intial speed = 30 m/s

at top point speed = 30 cos60 = 15

so answer will bo half time of flight

Solution by manish sir

intial speed = 30 m/s

at top point horizontal speed = 30 cos60 = 15

vertical component will be 0

so speed = 15 m/s

so answer will bo half time of flight

= usinθ/g

A SIMPLE ELECTRIC MOTOR HAS AN ARMATURE RESISTANCE OF 1 ohm & RUNS FROM A D.C SOURCE OF 12V . IT DRAWS A CURRENT OF 2A WHEN UNLOADED . WHEN A CERTAIN LOAD IS CONNECTED TO IT ,IT SPEED REDUCES BY 10% OF ITS INITIAL VALUE ,THE CURRENT DRAWN BY THE UNLOADED MOTOR IS??

ANS 3A

Asked By: SARIKA SHARMA 15 Day ago

SIR , ISTHE FOLLOWG METH. IS CORRECT

R=1ohm , E=12V , I=2A

I=(E-e)/R => e=10 ON PUTTING D VALUES

NOW AS IT IS REDUCES BY 10% MEANS NOW e' = 9V ( 10/100 X 10 = 1 CHANGE , THUS FINAL = 10-1=9)

I= E-e'/R = ( 12-9)/ 1 = 3A (RESISTANCE IS KEPT CONST.) RESISTANCE WILL CHANGE OR NOT??

SARIKA SHARMA 15 Day ago

Asked By: SARIKA 1 year ago

yes this method is correct.

is megnatic & electric feild depend on the frame give proper illustration please?

Asked By: RISHABH GOUR 1 year agoSolved By: SARIKA
Physics >> Mechanics Part 2 >> Elasticity Medical Exam

1-a uniform wire of mass of 400g hangs from a ceiling .a block of mass 600g is attached to its lower end.find the ratio of stress at the point 3/4L from the top and bottom end of wire?

2-a rubber ball is taken to depth 1 km inside water so that its volume reduces to 0.05%.what is the bulk modulus for rubber?

Asked By: SHWETA BHARDWAJ 1 year ago

if a particle is moving on a circular path with constant speed then the angle between the direction of acceleration and its position vector with respect to centre of circle will be?

Asked By: SHWETA BHARDWAJ 1 year ago

since speed is constant so only centripetal acc. will be present and it will be parallel to position vector starting from centre of the circle.

the reduced mass of two particle having masses m and 2m is  2m/m.how????.....

Asked By: SHIVANI MALIK 1 year ago

formula for finding reduced mass will be [m1m2/m1+m2]

consider a system of two particles having masses m1 and m2. if the particle of mass m1 is pushed towards m2 through a distance d, by what distance should be particle of mass m2 be moved so as to keep the centre of mass of the system of particle at the original position?

ans-m1d/m1+m2

Asked By: SHIVANI MALIK 1 year ago

two bodies have their moment of inertia L and 2L resp. about their axis of rotation.if their kinetic energies of rotation are equal, their respective angular momentum will be in ratio

Asked By: SHIVANI MALIK 1 year ago

the angular momentum of a particle performing uniform circular motion is L. if the kinetic energy of particle is doubled and frequency is halved, then angular momentum becomes-

ans-4L

Asked By: SHIVANI MALIK 1 year ago

a wheel having moment of inertia 4kgm2 about its symmetrical axis,rotates at rate of 240 rpm about it.the torque which can stop the rotation of the wheel in one minute is-

ans-8n/15

Asked By: SHIVANI MALIK 1 year ago

two point masses m and 3m are placed at distance r.The moment of inertia of the system about an axis passing through the centre of mass of system and perpendicular to the line joining the point masses is

ans-34mr2

Asked By: SHIVANI MALIK 1 year ago

two circular loops A and B of radii R and 2R resp. are made of the similar wires.there moments of inertia about the axis passing through the centre and perpendicular to their plane La and Lb resp.the ratio of LaLb is

Asked By: SHIVANI MALIK 1 year ago

what is the moment of inertia of a disc of mass M and radius R about an axis parallel to its diameter and at a distance R2 from the center?

Asked By: SHIVANI MALIK 1 year ago

4 identical balls of radius R and mass m are lying in a gravity free space. The balls are in contact and their centers are forming vertices of a square of side 2R in a horizontal plane.One identical ball travelling vertically with speed v hits the 4 balls symmetrically and elastically.The centers of 4 balls are at (R,R,0),(R,-R,0),(-R,R,0) and (-R,-R,0). What is the speed of ball 1 after collision.What is speed of projectile ball just after collision.

Asked By: EAKAM 1 year ago
Asked By: EAKAM 1 year ago

A block of mass M is pulled along a horizontal surface by applying a fore at an angle Teta with the horizontal.If the block travels with a uniform velocity and has a displacement d and the coefficient of friction is nu , then find the work done by applied force ?

Asked By: BALA KAILASH 1 year ago

Q A SIMPLE ELECTRIC MOTOR HAS AN ARMATURE RESISTANCE OF 1 ohm  & RUNS FROM A D.C SOURCE OF 12V . IT DRAWS A CURRENT OF 2A WHEN UNLOADED . WHEN A CERTAIN LOAD IS CONNECTED TO IT ,IT SPEED REDUCES BY 10% OF ITS INITIAL VALUE ,THE CURRENT DRAWN BY THE UNLOADED MOTOR IS??

ANS 3A

Asked By: SARIKA SHARMA 1 year ago

4 identical blocks of length l are arranged one over the other. the maximum distance of the uppermost block from the edge of teh lowermost block is x such that no block tumbles then x is?

Asked By: HARISH KORIBILLI 1 year ago

the moment of inertia of a thin uniform rod about an axis through its end and perpendicular to its length is ML²/3 . The moment of inertia of the rod about an axis parallel to given axis and at a distance L from the center of the rod is

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

for an axis parellel to the axis of rod and at distance l, rod will act as a set of equidistance particles. so answer will be Ml2

answer given by sarika is not completely correct

velocity of e- in hydrogen atom is 2X106 m/s . the radius of orbit is 5X10-11 m . the mag induction at centre of orbit in T will be??

Asked By: SARIKA 1 Month ago

Asked By: SARIKA SHARMA 1 year ago

B = μ0/2 * i/r

and i = e/T

and T = 2πr/v

solve

potential diff b/w dees of cyclotron is V , if charge q comes out of it after completing n revolution then gain in KE of charge is 2nqV HOW?

Asked By: SARIKA 1 Month ago
Asked By: SARIKA SHARMA 1 year ago

when charge will move from first dee to second dee it will gain qV and on returning to first dee it will gain qV again so in one revolution it will gain 2qV so in n revolutions it will gain 2qVn

Physics >> Electricity >> Capacitors Medical Exam

distance b/w plate of capacitor C &q charge is increased to double . work done=??

as distance d is double thus C= Ae/2d  thus capacitance will be halved so wd shld be (1/2 )q2/(C/2)   ie 1/4 q2/C

BUT Sir the ans given is=( 1/2)q2/C Plzz do me a little favour by solving this query

Asked By: SARIKA SHARMA 1 year ago

(1/2 )q2/(C/2) = q2/C not 1/4 q2/C

so work done = new energy - previous energy

An isolated conducting sphere of radius r has given charge q then PE??

ans is q2/8πe0r

But Sir ,why the ans q2/2πe0r is incorrect??

Asked By: SARIKA SHARMA 1 year ago

let we have given x charge and want to give dx also to the sphere

so dE = [1/4πε0]xdx/r

now integrate and take limits of x as 0 to q

2 Equal -ve charges -q r placed at pt(0,a) and (o,-a) on y axis , one +ve charge +q at rest is left from pt(2a,0). this charge will not execute SHM . WHY?? even when  F α -x condition is satisfying as force is due to both charges is acting & motion is also opposing during oscillating

Asked By: SARIKA SHARMA 1 year ago

Solve the question for force, you will get a condition according to which yours statement  "even when  F α -x condition is satisfying"

is incorrect

A wheel starting from rest is uniformly accelerated at 2 radsec^2 for 20s.It is allowed to rotate uniformly for next 10s and finaly brought to rest in next 20s.Find total angle rotated by wheel ( in radian).

Asked By: AVANTIKA PURI 1 year ago

ω = 0 + 2(20) = 40               (according to rotational equation ω = ω0 + αt)

and θ = 0 + 1/2(2)(20)2 = 400 radian

in middle uniform part angle rotated = 40*10 = 400 radian

and since acceleration in first part and retardation in last part are equal so angle rotated in last part = 400 radian

A body rotating with uniform angular acceleration covers 100 π (radian) in the first 5 s after the start. Its angular speed at the end of 5 s ( in radian/s) is

Asked By: AVANTIKA PURI 1 year ago

initial angular velocity = 0

so use θ = 1/2 αt2

and ω = αt

If the angle between the vectors C and D is θ  then the value of the product (C x D).D  is equal to

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

if A + B + C = 0 then A x B is

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

It is not given that in which terms we have to get answer so many answers are possible

A possible solution

A + B + C = 0

A+B = -C

B X (A+B) = - B X C

BXA + 0 = - B X C

AXB = BXC   ( ANS)

a vector A points towards north and vector B point upwards then A x B point towards

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

a small block slides down a smooth inclined plane , starting from rest at time t = 0 .let Sn be the distance  travelled by the block in time interval t = n - 1 to t = n. then the ratio Sn / Sn + 1 is ??

Asked By: SUVREEN VERMA 1 year ago

distance travelled in n seconds = 1/2 an2                          (a is the acceleration in the direction of incline)

distance travelled in n-1 second = 1/2 a(n-1)2

distance travelled in n+1 second = 1/2 a(n+1)2

so according to given condition Sn / Sn+1 =   [1/2 an-  1/2 an2] /  [1/2 a(n+1)2 -  1/2 an2]

now solve

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

NAME  THE OUTERMOST LAYER OF SUN ????

Asked By: SARIKA SHARMA 1 year ago

i think its corona

Two identical particles each of mass M & charge Q are placed some distance apart . If they are in equilm under mutual gravitational & electric force then calculate the order of signature of charge Q/M in SI system.

ANS = 10-10 C/kg

Asked By: SARIKA SHARMA 1 year ago

on comparing gravitational force and electrical force,

we get 9*109 * q2/r2 = 6.67*10-11* m2/r2

so q/m = 10-10 approx

What is the impulse momentum principle..??
Asked By: PUNEET KUMAR 1 year agoSolved By: PRIYANKA DAHIYA

1. A mass "m" moving with a velocity "u" hits a surface at an angle "Q" with the normal at the point of hitting . How much force does  it exerts, if no energy is lost ?

2. A thin cicular loop of radius "R" rotates about its vertical diameter with angular frequency "W" . show that a small bead on the wire loop remains at its lowermost  point for     W ≤ (root of g/R) . what is the angle made by the radius vector joining the center to the bead with the vertical downwards direction for   W= ( roots of 2g/R) . neglect  friction .

3. A rear side of a truck is open and a box of 40 kg is placed 5m away from the open end . the coefficient of friction b/w  box and surface in 0.15 on a straight road , the truck starts from rest and acclerates with 2m/s2. at what distance from the starting point  does the box fall off the truck .

4. Straight  from rest , a mass "m" slides down on inclined plane "Q" in a time "n times " the time to slide down the same lenght in absence of friction . Find the coefficient of friction .

Asked By: PRIYANKA DAHIYA 1 year ago

1) angle is measured from vertical so vertical component of velocity = ucosθ

and since no energy is lost so returning velocity in vertical direction will be same

so impulse = (mucosθ) - (-mucosθ)

force cant be calculated without time of impact.

2)

at the position given in diagram mrω2cosθ = mgsinθ for equilibrium

so rω2cosθ = gsinθ  and r = Rsinθ

so Rsinθω2cosθ = gsinθ  so Rω2cosθ = g    or   ω = √[g/Rcosθ]    so  ω ≥  √[g/R]

thus for W ≤ (root of g/R), bead will remain at the lowermost point.

for second part compare W= ( roots of 2g/R) and ω = √[g/Rcosθ]

3)  pseudo in opposite direction = ma

frictional force in the direction of motion of truck = 0.15mg

so equation of motion of box in opposite direction is ma - 0.15mg = ma'

so 2-1.5 = a' or a' = 0.5

distance = 5m

so time taken upto fall of box can be obtained by s = 1/2 a' t2

after calculating t, use again s = 1/2 (2) tfor finding distance travelled by truck.

4)  in first case with friction s = 1/2 (gsinθ-μgcosθ) (nt)2

in second case             s = 1/2 (gsinθ) t2

now solve.

Projectile motions Plzz help!!!!?

Two inclined planes OA and OB intersect in a horizontal plane having their inclinations α and β respectively as shown in the figure in the link given below. A particle is projected from point P with velocity 'u' along a direction perpendicular to plane OA. The particle strikes plane OB perpendicularly at Q.1) If α = 30 degrees and β = 30 degrees find the time of flight from P to Q.
2)If α = 30 degrees and β = 30 degrees and 'a'= 4.9 m, find the initial velocity of projection.
Asked By: AKASH 1 year ago

component of initial velocity along OB = ucos30

component of final velocity along OB = 0

component of g along OB = -gsin30

now use v = u + at

in second part clearly explain "a"

Ek ball viram se chalkar 20second tak eksaman acceleration se chalti hai .ball first 10second me s1 distance tay karti hai and next 10 second me s2 distance chalti hai tab s2=kya hoga

s1 = 0*10+1/2*a*100 = 50a

s1+s= 0*20+1/2*a*400 = 200a

now solve

a fixed uniformly charged ring of radius 3m has a positive linear charge density 50/3µC/m. a point charge 5μC is moving towards the ring along its axis such that its kinetic energy 4m away is 5J. Its kinetic energy at the centre of the ring will be?

Asked By: ROCKANDROLL 1 year ago

compare total energy at the two points and get answer

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a body is projected vertically upward with speed 32 m/s. total time taken in its complete journey is

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA

suppose it travelled h height thus from bottom to top it will covered h height in time t1 & at top its vel will be zero thus from eqn v= u-gt => 0= 32- 10t u can find t1= 3.2s ,  same time particle will take in downward journey so total time = 6.4 sec.

a body is p rojected vertically upwards with speed 20m/s .find the distance travelled by it during the last second of its upward journey(takeg=10m/s2

Asked By: RANDEEPSINGH 1 year ago

last sec. of upward journey means first sec. of free fall from the top so s=0(1) + 1/2(10)(1)2 = 5 meter,  here g is taken 10m/s2

Physics >> Mechanics part 1 >> Kinematics Medical Exam

The velocity of a body moving along x- axis is given by v =√( 36+2x) where v is in m/s and x is in metre. Find the distance travelled by it in 2 nd second.

Asked By: AVANTIKA PURI 1 year ago

dx/dt = √( 36+2x)

so dx/√( 36+2x) = dt

now integrate

limits of x are x1 to x2 and that of time are 1  to 2

A BALLOON WITH ITS CONTENTS WEIGHING 160N IS MOVING DOWN WITH AN ACCELERATION OF g/2 ms-2. THE MASS TO BE REMOVED FROM IT SO THAT THE BALLOOON MOVES UP WITH AN ACCELERATION g/3 ms-2 IS

Asked By: K TEJASAI 1 year ago

according to the given conditions

for downward journey 160-R = (160/g)g/2 = 80 so R = 80

now after removing m kg the new equation

R - [160/g - m]g = [160/g - m]g/3

put the value of R and  get m

A particle has an initial velocity  of 9m/s due east and a constant acceleration of 2m/s2 due west. What isthe distance covered by the particle in the 5 th second of its motion ?

Asked By: ANANT 1 year ago

potential diff b/w dees of cyclotron is V , if charge q comes out of it after completing n revolution then gain in KE of charge is 2nqV HOW?

Asked By: SARIKA 1 year ago

velocity of e- in hydrogen atom is 2X106 m/s . the radius of orbit is 5X10-11 m . the mag induction at centre of orbit in T will be??

Asked By: SARIKA 1 year ago

B = μ0/2 * i/r

i = e/T

and T = 2πr/v

now solve

charge flowing thru a xsection of wire varies with time as q= 2te-kt , where k is const . the voltmeter reads zero at t=??

Asked By: SARIKA 1 year ago

q= 2te-kt

on differentiating with respect to t, we get

dq/dt = 2[t(-k)e-kt e-kt ]

so for V = 0, i will be 0

so t = 1/k

the effective power of 3 lamps A (100W , 200V)  , B(60W,200V) ,C (40W,200V) connected in series is equal to 600/31W . how??

Asked By: SARIKA 1 year agoSolved By: ONLY NAME IS ENOUGH

for series R = R1 + R2 + R3 + R4

and R = V2/P { This is the general case to find the resistence of the device)

now use this and get the result

एक नाव की शांत जल में चाल 5 km /h है ,तथा 1 km  चोडी नदी को न्यूनतम पथ के अनुदिश 15 मिनट में पार करती है  तो नदी के जल प्रवाह का वेग km/h होगा..?

Asked By: VINOD 1 year ago

let boat is moving in a direction making an angle θ with the perpendicular to the flow, then for minimum drift

5sinθ = r

and 5cosθ = 1/.25 = 4

so cosθ = 4/5

and sinθ = 3/5

so r = 3 km/hr

You can see video related to this question in you tube (iit brain) as the name irodov problems

Physics >> Mechanics part 1 >> Kinematics Medical Exam

Velocity of raindrops in still air is 4 m/s vertically downward. If wind starts blowing at the rate 3 m/s horizontally towards north, then find the direction along which a man standing on the ground would  keep his umbrella ti protect himself from rain?

sir, i dont know the figure of this ques, so plz tell me this ques diagramatically.

angel of umbrella with vertical = tan-1[3/4]

एक लिफ्ट में एक सिक्का लिफ्ट के फिर्श से 2m  की उचाई पर छोड़ा जाता है, लिफ्ट की उचाई 10m  है | लिफ्ट 11m/s2के त्वरण से नीचे की ओर गति कर रही है | वह समय जिसके पश्चात सिक्का लिफ्ट से टकराएगा ?

the coin will fall with 10 m/s2 and acc. of lift is given as 11 m/s2. so coin will move upward with acc. 1 m/s2 relative to lift and initial velocity of coin = 0 relative to lift. so it will strike the roof of the lift

use s = ut + 1/2 at2

so 8 = 0 + 1/2 (1) t2

so t = 4

a person stands in contact against the inner wall of a rotor of radius r. The coefficient of friction between the wall and the clothing is μ and the rotor is rotating about vertical axis. The minimum speed of the rotor so that the person does not slip downward is

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA

A block of mass m is at rest on a rough inclined plane of angle of inclination θ . If coefficient of friction between the block and the inclined plane is μ, then the minimum value of force along the plane required to move the block on the plane is mg [sin θ- μ cos θ ] . How?

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA

A monkey of mass 40 kg climbs up a rope, of breaking load 600 N hanging from a ceiling. If it climbs up the rope with the maximum possible acceleration, then the time taken by monkey to climb up is [ Length of rope is 10 m ]

1. 2s      2. 1s      3. 4s

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

A block of mass 10 kg is released on rough incline plane. Block start decending with acceleration 2 m/s² . Kinetic friction force acting on block is ( take g= 10m/s² )

1. 10N      2. 30N

Asked By: AVANTIKA PURI 1 year ago

question is not correct

A bomb of mass M @ rest explodes into 2 fragments of masses m1 &m2 . The total energy released in the explosn is E if E1 &E2 represent the energies carried by m1 &m2. then which of the followg is correct

a) E1=(m2/M)E

B) E1= m1/m2  E

C) E1= m1/M  E

D) E1= m2/m1  E

Asked By: SARIKA SHARMA 1 year ago

(1) is correct

the ratio of energy will be E1/E2 = m2/m1

Three forces F1 = ( 2i+ 4j ) N ; F2 = ( 2j-k ) N and F3 = (k - 4i - 2j ) N are applied on an object of mass 1 kg at rest at origin. The position of the object at t=2s will be

1. (-2m, -6m)         2. (-4m , 8m)

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

a person stands in contact against the inner wall of a rotor of radius r. The coefficient of friction between the wall and the clothing is μ and the rotor is rotating about vertical axis. The minimum speed of the rotor so that the person does not slip downward is

1. √μg/r       2. √g/μr

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

A block of mass m takes t to slide down on a smooth inclined plane of angle of inclination and height h. If same block slids down on a rough inclined plane of same angle of inclination and some height and takes time n times of initial value, then coefficient friction between block and inclined plane is

the answer is [1- 1/n² ] tanθ

Asked By: AVANTIKA PURI 1 year ago

in first case acceleration is gsinθ

and in second case acceleration is gsinθ-μgcosθ

now use s = 1/2 a tin both the case and solve

A block of mass m is at rest on a rough inclined plane of angle of inclination θ . If coefficient of friction between the block and the inclined plane is required to move the block on the plane is

how the answer is   mg[sinθ - μ cosθ]  .

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

i think one line is missing in the question.

A small metallic sphere of mass m is suspended from the ceiling of a car accelerating on a horizontal road with constant acceleration a. The tension in the string attached with metallic sphere is

1. mg        2. m√g² + a²

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

A block of weight 1 N rests on an inclined plane of inclination θ with the horizontal. The coefficient of friction between the block and the inclined plane is μ. The minimum force that has to be applied parallel to the inclined plane to make the body just move up the plane is

1. μ sinθ                  2. μ cosθ + sinθ

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

a point charge q is placed at a distance 2r from the centre O of a conducting charged sphere of radius r. due to induced charges on the sphere , find the elecric potential at point P on the surface of sphere in volt if kq/r =18V.

in the above ques, last time u found out potential at center but according to ques we hav eto find out on the surface and ans. is 3

Asked By: VISHAL PHOGAT 1 year ago

if the answer is 3 V then 2r should be the distance of q from surface not from centre.

first confirm

In the ques previously submitted by someone which was as follow

the electric field vector is given by E= a(x)1/2 i^ . find the φ thru a cube bounded by surface x=l, x=2l, y=0, y=l , z=l, z=0.

Sir , my query is that in the solutn submitted the leaving flux at x=2l is given as( 2l)1/2 X l2 . but as the electric field is itself along x then why 2l will be used as along x axis it will be zero because cosθ used is perpendicular to surface with electric field axis thus cos90 =0??

Asked By: SARIKA SHARMA 1 year ago

θ should be measured between E and perpendicular drawn on the surface

a small body starts sliding from a height h down an inclined groove passing into a half circle of radius h/2. find the speed of the bodywhen it reaches the highest point of its trajectory

Asked By: DANI 1 year ago
Solution by manish sir

since body starts from height h at rest and ends in the same height so it will again be in rest

BLOCK OF WOOD IS KEPT ON THE FLOOR OF A STATIONARY ELEVATOR. D ELEVATOR BEGINS TO DESCEND WITH AN ACCLN 12m/s2 . IF g =10  , THEN DISPLACEMENT OF BLOCK W.R.T. GROUND DURING FIRST 0.2 SEC. AFTER D START WILL BE             ??

ANS 0.2m

Asked By: SARIKA SHARMA 1 year ago

s = ut + 1/2 at2

so s = 0 + 1/2 10(0.2)2

so s = 5(0.04) = 0.2

since elevator is moving with an acc. greater than g so we should take it a free fall

The energy required to accelerate a car from rest to 10m/s is E . What energy will be required to accelerate the car from 10m/s to 20m/s??

(ANS 3E)

Asked By: SARIKA SHARMA 1 year agoSolved By: AVANTIKA PURI

4 particles each of mass m and charge q are held at the corners of a square of side a . they are released  at t=0 and move under mutual repulsice force. find the speed of any particle when its distance from the center is double.

Asked By: VISHAL PHOGAT 1 year ago

potential energy in initial condition = 4*k*q*q/a + 2*k*q*q/a√2

potential energy in final condition = 4*k*q*q/2a + 2*k*q*q/2a√2

and kinetic energy in the final condition = 4*mv2/2

now use energy conservation

a point charge q is placed at a distance 2r from the centre O of a conducting charged sphere of radius r. due to induced charges on the sphere , find the elecric potential at point P on the surface of sphere in volt if kq/r =18V.

Asked By: VISHAL PHOGAT 1 year ago

potential at the centre due to q = kq/2r = 9 V

potential at centre due to surface charge = 0 V

total potential = 9 V

now at surface potential due to q = kq/r = 18 V

but it should be 9 V totally so due to surface induction, potential will be -9V

the electric field vector is given by E=a(x)½ iˆ.find the flux through a cube bounded by surfaces x=l ,x=2l, y=0 ,y=l, z=0, z=l

Asked By: VISHAL PHOGAT 1 year ago

entering flux at x=l will be a(l)1/2  *  l2

leaving flux at x=2l will be a(2l)1/2  *  l2

so net flux will be the difference of these 2 flux

A body of mass 32kg is suspended by a spring balance from the roof of a vertically operating lift going downward from rest . At that instant  the lift covered 20m and 50m , the spring balance showed 30 kg & 36 kg respt. the vel. is increasing at 20m & decreasing at 50m. Plzz sir explain this.

Asked By: SARIKA SHARMA 1 year ago

for downward journey

first case

32g-30g = 2g = 32a so a = g/16

second case

32g-36g = -4g = 32a so a = -g/8

so it is acceleration upto 20 m and retardation after that

Physics >> Mechanics part 1 >> Kinematics Medical Exam

d benches of a gallery in a cricket stadium r 1m wide & 1m high . a boy strikes d ball at a level of 1m above d ground & hits a sixer. d ball starts at 35m/s at an < of 530 with d horizontal . d benches r perpendicular to plane of motion & d first bench is 110m from d boy. ON WHICH BENCH WILL THE BALL HIT??

ANS 6TH

Asked By: SARIKA SHARMA 1 year ago

we know that y = xtanθ - gx2/2u2cos2θ

according to the given conditions

x  = 110+n

y = n                              here n is the number of bench in which ball strikes

θ, u and g are given

A 6 kg bomb at rest explodes into three equal pieces P, Q and R. If P flies with speed 30 m/s and Q with speed 40 m/s making an angle 90° with the direction of P. The angle between the direction of motion of P and R is about

1.    143°        2.   127°     3.  120°

Asked By: AVANTIKA PURI 1 year ago

since initially bomb is in rest so initially momentum of the bomb = 0i+0j+0k

after explosion total momentum = 30mi+40mj+mv                    here v is a vector

now by momentum conservation 0 = 30mi+40mj+mv so v = -30i-40j

so vector along P is i and along R is -3i-4j

so by A.B = |A||B|cosθ

we get i.[-3i-4j] = 1*5*cosθ

so -3/5 = cosθ so θ = 127

If n balls hit elastically and normally on a surface per unit time and all the balls of mass m are moving with same velocity u, then force on surface is

2 mun . How ?

Asked By: AVANTIKA PURI 1 year ago

momentum change in elastic collision = mu-(-mu) = 2mu                      here after collision partical will retrace its direction

for n balls it will be  2mun

so force = rate of change of momentum = 2mun/1 = 2mun

A man of mass 50 kg  carries a bag of weight 40 N on his shoulder.  The force with which the floor pushes up his feet will be

1.  882 N         2.   530 N          3.  90 N         4.   600 N

Asked By: AVANTIKA PURI 1 year ago

reaction by ground is due to both bag and man so 50g+40 = 50*9.8+40 = 490+40 = 530 N

When a 4 kg rifle is fired, the 10 g bullet receives an acceleration of 3 x 10^6 cm/s^2 . The magnitude of the force acting on the rifle (in newton) is

1. 300      2.  200     3.  3000

Asked By: AVANTIKA PURI 1 year ago

force on the bullet = [10/1000]*3*10= 300 N

so that will be same for rifle

A body of mass 2 kg is sliding with a constant velocity of 4 m/s on a frictionless horizontal table. The force required to keep the body moving with the same velocity is

1.   8 N      2.   0 N      3. 1/2   N

Asked By: AVANTIKA PURI 1 year ago

no force is required

Two particles each of mass m are moving in horizontal circle with same angular speed. If both string are of same length then the ratio of tension in string T1 / T2 is

1. 3/2          2.  3         3. 2       4. 1/3

Asked By: AVANTIKA PURI 1 year ago

it will be 1:1

A particle is moving on a circular path of radius 1 m with 2 m/s. If speed starts increasing at a rate of 2 m/s² , then acceleration of particle is

Asked By: AVANTIKA PURI 1 year ago

centripetal acceleration = v2/r = 2*2/1 = 4

and tangential acceleration = 2     [given]

so acceleration = [42+22]1/2 = √ 20

A particle is revolving in a circular path of radius 2 m with constant angular speed 4 rad/s. The angular acceleration of particle is

1.  zero    2. 8π²    3. 16π²

Asked By: AVANTIKA PURI 1 year ago

since angular velocity is constant, so zero will be the answer

If a particle is moving on a circular path with constant speed, then the angle between the direction of acceleration and its position vector w.r.t. centre of circle will be

1. zero    2. π   3. π/2     4. 2π

Asked By: AVANTIKA PURI 1 year ago

position will be radically outward and acceleration will be radically inward, so angle = π

If a particle of mass 2 kg is moving in circular path with constant speed 20 m/s. The magnitude of change in velocity when particle travels from A to P will be

1. 20√2 m/s             2.  40 m/s

Asked By: AVANTIKA PURI 1 year ago

in this question you should define A and P first then we will give you an answer.

A block of mass m kg on a weighing machine in an elevator is retarding upward by a m/s^2, the reading of weighing machine is (in kgf)

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA

A book of mass 5 kg is placed on a table and it is pressed by 10 N force then normal force exerted by the table on the book is

My answer is 60 N but the correct answer is 59 N. How?

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

A particle of mass m strikes elastically on a wall with velocity v, at an angle 60° from the wall the magnitude of change in momentum of ball along the wall is

(1) zero       (2) mv

Asked By: AVANTIKA PURI 1 year ago

since momentum of the ball before strike and after strike are same along the wall so change will be 0

sir i had asked a ques and its ans was also replied by you, but still i have a doubt that in 1st part you take g as  -ve because motion is against gravity and it is clear to me but in 2nd why g is taken as -ve? here, the motion is not against gravity, so plz tell me the concept of g? wten it is -ve or +ve.

b) in second part we have to calculate the time of journey from top of 25 m high building to ground.

for this we should use

h = -ut + gt2/2                   [in this case we are using upward direction as - ve and downward as + ve]

so 25 = -20t + 10t2/2

or 5t2 - 20t - 25 = 0

or t2- 4t - 5 = 0

or (t+1)(t-5) = 0

or t = 5 , -1

so t = 5 sec.

This is answer of the same problem but here i am using g +ve, I want to say only that it will always be your opinion to consider the sign of direction. You can consider any of the direction as positive and negative.

A smooth sphere of radius R is made to translate in a straight line with constnt acceralation a . A particle kept on the top of the sphere is released from there at zero velocity with respect to the sphere. find the speed of the particle with respect to the sphere as a function of the angle θ it slide

Solution by manish sir

use energy conservation to solve it

if not possible then send a reply we will give you complete answer.

a ball is thrown vertically upwars with a velocity 20m/s from the top of a multistorey building. the height of the point from where the ball is thrown is 25m from the ground.

a) how high will the ball rise?

b) how long will it be before  the ball hits the ground? take g=10m/s square

a) At heighest poing velocity will be 0

so by formula v2 = u2 - 2gh        (here - is because you are moving against gravity)

so h = 20*20/2*10 = 20 m

so ball will rise upto 25+20 m from the ground.

b) in second part we have to calculate the time of journey from top of 25 m high building to ground.

for this we should use

-h = ut - gt2/2                   [in this case we are using upward direction as + ve and downward as - ve]

so -25 = 20t - 10t2/2

or 5t2 - 20t - 25 = 0

or t2- 4t - 5 = 0

or (t+1)(t-5) = 0

or t = 5 , -1

so t = 5 sec.

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A particle starts from rest and moves with constant acceleration. The magnitude of its displacement is

1) more than its distance traversed

2) less  ''        ''    ''           ''

3)     equal to ''      ''          ''

4)     zero

ans given is (3) but I want to know why it vyl not be less than dist. travelled & why (4) optn is wrong as in case of uniform circular motion displacement is 0 but have const. acc.??

Asked By: SARIKA SHARMA 1 year ago

I think the particle is moving in a straight line

How fast a car can pull 100kg Iron? the energy of car is 10hp

Asked By: PRINCE PAL 1 year ago

E= ∫Fds

=  ∫ma ds

= ∫m( dv / dt) ds

=  ∫m dv (ds/dt)= ∫mvdv

= 1/2 mv2

so v =(2E/m) 1/2    now use mass 100kg & given energy after converting in SI units

This answer is given by SARIKA SHARMA and is correct, we made some modifications only

IF 2sin2220 = p+qcosθ, FIND SMALLEST POSITIVE VALUE OF θ, WHEN p=1 AND q = -1.

Asked By: SARIKA SHARMA 1 year ago

2sin222.5 = 1- cos45 = 1 + (-1)cos45

so θ = 45

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A car moves towards north at a speed of 54 km/h for 1 h. Then it moves eastward with same speed for same duration. The average speed and velocity of car for complete journey is

Asked By: AVANTIKA PURI 1 year ago

avg speed = total distance / total time = 54+54/1+1 = 54

avg velocity = total displacement / total time = 54sqrt(2) / 2 = 27sqrt(2)

Physics >> Mechanics part 1 >> Kinematics Medical Exam

If P  & Q are two vectors such that |P-Q| = |P+Q| , then find angle between P and Q.

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

The acceleration (a) of a body moving along x-axis is given by a=4x3 ,where a is in m/s2 and x is in metre.if at x=0 the velocity of body is 2m/s,then find its velocity at x=4m?

Asked By: AVANTIKA PURI 1 year ago

a = 4x3

so dv/dt = 4x3

or dv/dx * dx/dt = 4x3

or dv/dx * v = 4x3

or vdv = 4x3dx

or ∫vdv = 4∫x3dx

or v2/2 = 4x4/4 + C

at x = 0, v = 2

so 4/2 = 0+C

so C = 2

on putting the value of C

we get v2/2 = x4+ C

now put x = 4 and get v

The position x of a particle moving along x-axis at time t is given by equation t=√x +4 , where x is in meter and t is in seconds. Find the position of particle when its velocity is zero.

Asked By: AVANTIKA PURI 1 year ago

given that x = (t-4)2

so dx/dt = 2(t-4)

or v = 2t-8

now for v=0, t=4

put t=4 and get x

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A body projected upwards is at same height form ground at t=3s and t=7s . Find the maximum height attained by it. ( take g= 10 m/s^2 ).

Asked By: AVANTIKA PURI 1 year ago

A body projected upwards is at same height form ground at t=3s and t=7s. It will gain max. height after 5 second

so maximum height = gt2/2 = 10*5*5/2 = 125

another direct method for finding total distance = 5+15+25+35+45 = 125

these are the distances in 1st, 2nd, 3rd and etc sec.

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A particle starts moving with acceleration 2 m/s^2 . Distance travelled by it in 5 th half second is

(a) 1.25 m    (b) 2.25 m     (c) 6.25 m    (d)30.25 m

Asked By: AVANTIKA PURI 1 year agoSolved By: SARIKA SHARMA

What would be the Potential energy of two points charges q &-q which r separated by a dist d  ( IF POTENTIAL AT MID PT IS TAKEN TO BE ZERO)

Asked By: SARIKA SHARMA 1 year ago

potential energy = -kqq/d

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a particle , with an inital velocity v0 in a plane , is subjected to a constant acceleration in the same plane . then in general ,

the path of the particle would be

1) circle

2) ellipse

3) parabola

4)   hyperbola

Asked By: SARIKA SHARMA 1 year ago

parabola

for understanding this make components of v parallel and perpendicular to a

Physics >> Mechanics part 1 >> Kinematics Medical Exam

a train is moving with a velocity of 30m/s. When brakes are applied , it is found that the velocity  reduces to 10m/s in 240m.

When the velocity of the train becomes zero , the total distance travelled is??

270m

Asked By: SARIKA SHARMA 1 year ago

by v2 = u2-2as

100 = 900-2*a*240

or 800 = 480a

or a = 80/48 = 10/6 = 5/3

so total distance upto rest is u2/2a = 900*3/2*5 = 270m

A CARNOT ENGINE WORKING B/W 270 C & --1230C HAS EFFICIENCY η . IF TEMP OF SINK IS DECREASED BY 50K THE EFFICIENCY BECOMES??

ANS  4η/3

Asked By: SARIKA 1 year ago

according to the given condition η = 1-(150/300) = 0.5

now after decreasing temperature of sink by 50K

we get the new efficiency = 1-(100/300) = 2/3 = 4*0.5/3 = 4η/3

in a thermodynamic process on 2 moles of a monoatomic gas work done on gas is 100J & change in temp is 30 C . The change in internal energy of the gas in this process is??

Asked By: SARIKA 1 year ago

change in internal energy = nCvdT = 2*[R/(γ-1)]*30 = 60*8.31/[(5/3)-1]

while measuring the speed of sound by performing a resonance column expt , a student gets d first resonance conditn at a column length of 18 cm during winter . Repeating d same expt during summer , she measure d column length to be x cm for the second resonance. THEN

1)18>X

2)X>54

3) 54>X>36

4) 36>X>18

ANS (2)

AIEEE 2008

Asked By: SARIKA SHARMA 1 year ago

since l α λ α v/n          n is frequency

on increasing temperature, v increases so λ increases

for first resonance l = λ/4

and for third resonance L = 3λ'/4

and λ> λ so x will be more than 54

Physics >> Mechanics part 1 >> Kinematics Medical Exam

angle b/w vectors (i^+j^)and(j^+k^)  is

1) 60o

2) 90o

3) 300

4) 450

Asked By: SARIKA SHARMA 1 year ago

use the formula A.B = |A||B|cosθ

what is definition of time period?

Asked By: SWARNENDU MANNA 1 year agoSolved By: SARIKA SHARMA

what is the definition of velocity?

Asked By: SWARNENDU MANNA 1 year agoSolved By: SARIKA SHARMA

chock coil is used to

1) increase current

2) increase voltage

3) decrease current

4) decrease voltage

here we know power= IV  & chock coil is used to reduce the power loss , so here what vyl be the answer

Asked By: SARIKA SHARMA 1 year ago

chock coil in ac is the device equivalent to rheostat in dc, so it is used to increase current.

If a particle (strong enough to survive in space) is released in space from earth. Where it will go? What about its motion? Will it revolve around the sun or remain stationary?

Asked By: PRINCE KUMAR 1 year ago

it depends on the speed with which it is thrown

a large open tank has two holes in the wall. one is a square hole of side L at a depth Y from the top and the other is a circular hole of radius R At a depth 4Y  from the top . when the tank is completely filled with H2O , the quantities of H2O flowing / sec from both holes are same . then R IS equal to??

ans L / [√(2π)]

Asked By: SARIKA SHARMA 1 year ago

speed of water from any hole = √2gh

so volume of water per sec. = A√2gh

for square hole volume/sec = L2√2gY

for circular hole volume/sec = πR2√2g4Y

when a tuning fork vibrates with 1.0 m  or  1.05m long wire of a sonometer, 5 beats per second are produced in each case. what will be the frequency of the  tuning fork ??

Asked By: SARIKA SHARMA 1 year ago

for sonometer wire

l = λ/2

or 2l = v/n                                    here n represents frequency

or n = v/2l

for first wire of 1 m length n= v/2

for second wire of 1.05 m length n=v/2.1

let frequency of tuning fork = n1

so according to the given condition v/2 = n1+ 5

and v/2.1 = n1 - 5

solve now

Physics >> Optics >> Refraction Medical Exam

if ω1 &ω2 are dispersive powers of lenses of focal length f1 & f2 respectively . then the condition of chromatic aberration for two lenses in contact is

1) ω1/ω2 = f2/f1

2) ω1/ω2 = f1/f2

3) ω1/ω2= - f1/f2

4) ω2/ω1= f1/f2

Asked By: HIMANSHU 1 year ago

3 is the true condition and can be proved

the half life of radium is 1620 year & its atomic weight is 226gm/mole. the number of atoms that will decay from its 1g sample per second is

1) 3.16 x 1010

2)3.6 x 1012

3) 3.1 x 1015

4) 31.1 x 1015

Asked By: HIMANSHU 1 year ago

for radioactivity we know that it is a first order process

so dN/dt = -λN

so dN/1 = -[0.6932/(1620*3.1*107)]*(1/226)*6.023*1023

solve now

An open knife edge of mass m is dropped from a height h on a wooden floor. if the blade penetrates a dist s into the wood , the avg. resistance offered by wood to blade.  ANS mg(1+h/s)

Asked By: SARIKA 1 year ago

velocity at the time of strike of the knife at the wood = √(2gh)

now equation for penetration on the wood is R-mg = ma            here R is reaction by the wood

so R = m(g+a)

here it is given that s is the distance penetrated by the knife on the wood so 02 = (√2gh) - 2as so a = 2gh/2s = gh/s

on taking this value of a

we get R = m(g+gh/s) = mg(1+h/s)

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A at road of 200km & B at 100km road. A with vel 20m/s & B with 7.5m/s . Then wat will b d time when B overtake A.

1)  24s

2) 40s

3) 80s

4)nothing can be predicted

Asked By: SARIKA SHARMA 1 year ago

data are irrelevent

A LIFT IS MOVING  UPWARD WITH ACC 2m/s2 .WHEN IT GAIN THE VELOCITY 4m/s THEN AT THAT MOMENT A BALL IS PROJECTED BY 300 (wrt floor to lift) WITH VEL. 4m/s RELATIVE TO LIFT . FIND HOW MUCH TIME WILL IT TAKE TO 1) TO REACH GROUND &   2) TO THE FLOOR OF LIFT AGAIN

Asked By: SARIKA SHARMA 1 year ago

since velocity of the ball is 4 m/s relative to lift so

time taken by the ball to reach the floor of lift T = 2usinθ/g = (2*4*1/2)/10 = 0.4 sec

height of the lift at the time of dropping the ball = (v2-u2)/2g = 16/20 = 8/10 = 0.8 m = h

and vertical component of the velocity of ball with respect to the ground = 6 m/s = u

so use -h = ut - gt2/2

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

A STONE WEIGHS 9N AT A PLACE ON THE SURFACE OF EARTH HAVING LATITUDE π/2 . ITS MASS AT CENTRE OF EARTH WILL BE (kg)

1) 10/ 37√2

2 ) 10√2

3) 5

4) 15

Asked By: SARIKA SHARMA 1 year ago

π/2 means it is pole so mg = 9 implies that m = 9/9.8

same will be the mass at centre of earth

A CHARGED PARTICLE IS PROJECTED PARALLEL TO A UNIFORM FIELD . THE PATH OF D PARTICLE WILL BE

1) PARABOLIC

2) ELLIPTICAL

3) CIRCULAR

4) LINEAR

Asked By: SARIKA SHARMA 1 year ago

linear and accelerated.

CHARGES ARE PLACED ON VERTICES OF A SQ. WITH a, b HAS +q & c,d has -q charge . LET E ELECTRIC FIELD & V IS POT.  AT CENTRE . IF CHARGES ON a &b R INTERCHANGED WITH THOSE OF c& d RESPTLY  THEN E  CHANGES WHY??

Asked By: SARIKA SHARMA 1 year ago

in this case magnitude will remain same. Only direction of E will change.

Physics >> Electricity >> Capacitors Medical Exam

a II plate capacitor has an electric field of 105 V/m b/w d plates . if charge on capacitor plate is 1uC d force on each capacitor is??

ans 0.05N

Asked By: SARIKA SHARMA 1 year ago

F = σq/2ε0 = Eq/2 = 105*10-6/2 = 0.05

A charge of +2.0 x 10^-8 C is placed on the positive plate and a charge of -1.0 x 10^-8 C on the negative plate of a parallel plate capacitor of capacitance 1.2 x 10^-3 uF. Calculate the potential difference developed between the plates. Please add explanation!

Asked By: VISHWAJEET MISHRA 1 year ago

due to induction the charges on the four faces will be

so V = q/C = 1.5 * 10-8/1.2 * 10-9

solve now

2 MOLES OF MONOATOMIC GAS IS MIXED WITH 1 MOLE OF A DIATOMIC  GAS. THEN γ  FOR THE MIXTURE??

ANS 1.55

Asked By: SARIKA SHARMA 1 year ago

total no of freedom for this mixture = (2*3+1*5)/(2+1) = 11/3

so γ = 1+[2/f] = 1 + 2/[11/3] = 1 + [6/11] = 17/11 = 1.55

a thin square plate with each side equal to 10cm , is heated by a blacksmith . the rate radiated energy by the heated plate is 1134W the temp of hot square plate is

( σ = 5.67 X 10-8 Wm2/k4 emissivity of plate =1)

ANS 1000K

Asked By: SARIKA SHARMA 1 year ago

according to the Stefans law P = AeσT4

so 1134 = 0.02*1*5.67*10-8*T4   (area of both the faces are considered)

so 1134*1010/11.34 = T4

so T = 1000

TWO PENDULUM HAVE TIME PERIODS T &5T/4. THEY STARTS SHM AT THE SAME TIME FROM THE MEAN POSITION . WHAT WILL BE THE PHASE DIFFERENCE B/W THEM AFTER D BIGGER PENDULUM COMPLETED ONE OSCILLATn ??

ans 900

Asked By: SARIKA SHARMA 1 year ago

When bigger pendulum will complete its one oscillation, the smaller one will complete [1+(1/4)] oscillation. so phase difference = 2π*(T/4)/T = π/2

Physics >> Mechanics part 1 >> Kinematics Medical Exam

QUES A MAN RUNS AT A SPEED OF 4M/s  TO OVERTAKE A STANDING BUS . WHEN HE IS 6m  BEHIND THE DOOR (AT t=0) , THE BUS MOVES FORWARD & CONTINUES WITH A CONSTANT ACCELERATn OF 1.2m/s2 . the MAN SHALL GAIN THE DOOR AT TIME t EQUAL TO

A) 5.2s

b) 4.3s

c)2.3s

d)  the man shell never gain the door.

ans 4.3s , Sir ,on solving I 'm getting both 4.3 & 2.3 s ( when we solve sq root) so here i want to know why not the ans is 2.3s.      AMU 2012

Asked By: SARIKA SHARMA 1 year ago

After 2.3 sec. the man overtake the door first, in this time velocity of bus will be less than that of man so it is not possible to catch the bus then after 4.3 sec. the bus door will again reach to the man, in this time velocity of bus and man are same, so relative velocity is zero and catching of bus is possible.

A RADIOACTIVE SUBSTANCE EMITS n BETA PARTICLES IN THE FIRST 2 SECONDS & 0.5 n BETA PARTICLES IN THE NEXT 2 SECONDS . THE MEAN LIFE OF THE SAMPLE IS

ANS 2/(ln2) s

Asked By: SARIKA SHARMA 1 year ago

A RADIOACTIVE SUBSTANCE EMITS n BETA PARTICLES IN THE FIRST 2 SECONDS & 0.5 n BETA PARTICLES IN THE NEXT 2 SECONDS. Definitely by definition its half life will be 2 sec.

so mean life = half life / ln2                  This is the relation between mean life and half life.

A NUCLEUS OF MASS NO. 220, INITIALLY AT REST , EMITS AN  .α PARTICLE . IF THE Q  VALUE OF THE Rxn  IS 5.5MeV THE ENERGY OF THE EMITTED α PARTICLE WILL BE ??

ANS 5.4 MeV

Asked By: SARIKA SHARMA 1 year ago

5.5*216/220 = 216/40 = 5.4 MeV                                  here 216 is the mass of nucleus after ejecting α particle.

THE  TERMINAL SPEED ATTAINED BY AN Al  SPERE OF RADIUS 1mm  FALLING THROUGH H2O AT 200C WILL BE CLOSE TO ??

ANS 4.6 m/s

(assume laminar flow , specific gravity of Al=2.7 & η H2O =8X 10-4 PL.)

Asked By: SARIKA SHARMA 1 year ago

v = 2r2g(D-d)/9η

so v = 2(.001)2*9.8(2700-1000)/9*8*10-5

solve it

One end of a 10cm long silk thread is fixed to a large vertical surface of a charged nonconducting plate having a mass 10g and a charge of 4*10^-6 c . In equlibrium the thread makes an angle of 60 deg. With he vertical.find the surface charge density on plate.
Asked By: GAURAV MAHATE 1 year ago

according to the diagram

tanθ = qE/mg = q(σ/2ε0)/mg

solve this eq. for σ.

Remember that length of the thread is not applicable in the question.

what is a short circuit?

Asked By: SWARNENDU MANNA 1 year ago

to connect - and + of the cell together

IN THE SOLUTION GIVEN BY AMIT TO MY PREVIOUS QUERY , THE FORMULA USED IS E=kq/r ,SIR I WANT TO KNOW IS IT IS CORRECT , DON'T YOU THINK IT SHOULD BE E=kq/r2 ??

Asked By: SARIKA SHARMA 1 year ago

yes you are right

there is slight mistake in last line of previous question.it was find the work done on the system in the process of inserting the slab.
Asked By: GAURAV MAHATE 1 year ago

initial energy of capacitor = 1/2 CV2

final energy of capacitor = 1/2 KC (V/K)2

difference ?

a parallel plate capacitor of plate A and plate seperation d is charged to a potential dif. V and then the battery is disconnected .a slab of dielectric constant K is then inserted between the plates of capacitor so as tofill the space bet. The plates .find the work done in this process.
Asked By: GAURAV MAHATE 1 year ago

initial energy of capacitor = 1/2 CV2

final energy of capacitor = 1/2 KC (V/K)2

difference ?

When the charges are unequal , the neutral point is closer to the smaller charge . WHY ??

Asked By: SARIKA SHARMA 1 year agoSolved By: AMIT DAS

A point charge q is placed off centre at point c inside a thick spherical shelll of inner radius a and outer radius b. Shell is neutral and conducting. OA =ra , OB = rb & OC = rc. Then the potential at centre of shell will be ( also show the distribution of charges )

Asked By: AMIT DAS 1 year ago

Distribution:         at C q, at inner surface -q, at outer surface +q

so potential at centre = kq/rc -kq/a + kq/b

A particle P of charge q and mass m is placed at a point in gravity free space and its free to move. another particle Q , of same charge and mass , is projected from a distance r from P with an initial speed v0  towards p . Initially the distance between P and Q decreases and then increases. Then what will be the speeds of particles P and Q when their separation is minimum?

Asked By: AMIT DAS 1 year ago

by momentum conservation mv0 = 2mv1

so v1 = v0/2

E=4x^2 i the potential difference b/w A(x=0) m and b(x=4 )m, va-Vb is?

-320 or -320/3

and...if E=(2/y) if v integrate it as per the formula dv/dr=E then the ans is 2lny or -2lny  ???

Asked By: AYANSH 1 year agoSolved By: AMIT DAS
A charge q kept at the center of a semicircular thread having uniform charge per unit length lameda R is the radius of semivircular thread. Find the force req. ti keep it stationary ???
Asked By: SHUBHAM CHAUDHARY 1 year ago

first calculate the magnitude of electric field at centre of ring due to charge on the surface of ring and direction of that electric field also

this can be solved by method of integration

then F = qE

a car travels (1/4)th of a circle with radius r . Find the ratio of the distance to it's displacement ?

a ball falls on an inclined plane of inclination @ from a height h above the point of impact and makes a perfectly elastic collisiom.where will it hit the plane again?
Asked By: GAURAV MAHATE 1 year ago

velocity of impact = √2gh

so components of velocity after rebound = √2ghcosθ perpendicular to the plane and √2ghsinθ parallel to the plane for the collision is perfectly elestic

now with perpendicular component take net displacement 0 and calculate time

then find displacement along the plane by using s = ut + 1/2at2

here remember that you should divide gravity in comnents too

a gun is mounted on a railroad car .the mass of the car,the gun,the shells, and the operator is 50m where m is the mass of one shell.if velocity of the shell w.r.t. The gun(in its state before firing) is 200m/s,what is the recoil of the car after the second shot?neglect friction.
Asked By: GAURAV MAHATE 1 year ago

in first firing

m200 = 49mv so velocity of gun = 200/49

now apply momentum conservation again by taking 200/49 as the velocity of gun

The bob of mass m , charge q is circulating in a vertical circle of radius R. With the help of a string . If the maximum  speed of the bob is V then the period of revolution is T1. If an electric field of magnitude (mg/q)  is setup which makes an angle 600 with upward vertical . again the bob is circulating in same circle and its maximum speed is also v , then the period of revolution is T2. Find then  T1/T2.

Asked By: AMIT DAS 1 year ago

in first case net force of gravity = mg

in second case electric force = qE = qmg/q = mg

so resultant of gravitational mg and electric mg  will be mg again at an angle 60 degree with vertically downward direction.

in this time max velocity will not be at bottommost point as in previous case but it will make an angle 60 degree with horizontal

so T1 = T2

Consider the circuit shown with key opened. 3uf capacitor is charged to p.d. of 9 V. Capacitor 6 uF is charged to p.d. of 3V. The key is now closed . What will be the potential differnce across 3 uF capacitor in steady state?

Asked By: AMIT DAS 1 year ago

V = [3*9-6*3]/(3+6) = 9/9 = 1

here - is used for opposite poles of the capacitors are connected together

Find the magnitude of electric potential at the origrn due to following charge distribution (if q = 1 nC) sir i am unable to solve the series :

k - 3k/2 +5k/4 - 7k/4..........

= -k/2 - 3k/8 ....... plzz help

Asked By: AMIT DAS 1 year ago

k - 3k/2 +5k/4 - 7k/8..........

= k(1-3/2+5/4-7/8+...............)

now let   S = 1-3/2+5/4-7/8+.......

and -1/2 S =  -1/2+3/4-5/8+......

on substracting 2nd by 1st

we get 3/2 S = 1-1+1/2-1/4+.......

or       3/2 S = 1-(1-1/2+1/4-1/8+..........)

now solve

What is the differnce between neutral and stable in terms of equilibrium of a particle?

Asked By: AMIT DAS 1 year agoSolved By: SARIKA

my previous questn from rotational topic is still uncleared . I want to know why w= 4π is used.

Asked By: SARIKA SHARMA 1 year ago

according to rotational mechanics angular velocity = 2πn  here n is frequency  and in the problem n = 120 rotation/min = 2 rotation/sec.

the time period of oscillatn of a simple pendulum is 2π (l/g)1/2.  l is about 10cm & is known to 1mm accuracy. the time period of oscillatn is about 0.5s . time of 100 oscillatn with a wrist watch of 1s revolutn . what is the accuracy in determinatn of g?

ans 5%

Asked By: SARIKA SHARMA 1 year ago
Solution by manish sir

T = 2π (l/g)1/2

so g α  l/T2

so % error in g = % error in l + 2 % error in T

=  0.1*100/10  + 2* 1*100/50 = 1+4 = 5

here you shoult remember that if you count 100 osccilations then time will be counted for 100 osccilation.

from rest a body rotate 120rot/min for 20 sec then rotate for 5 sec with same rotation . find how many rotation it will make?

here while calculating ang. acc you use w= w0 + at , how w=4π , ( i want to know how to convert 120 rot/min)

Asked By: SARIKA SHARMA 1 year ago
Solution by manish sir

120 rotation per minute = 120/60 = 2 rotation per second

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A BODY STARTS WITH INITIAL VELOCITY 30m/s & A RETARDATION OF 4m/s2 . FIND THE DISTANCE TRAVELLED BY THE BODY IN 8th SECOND.

ANS 1m

Asked By: SARIKA SHARMA 1 year ago

by v = u - at

0 = 30 - 4t   implies t = 7.5

it means velocity will become 0 in 7.5 sec.

distance covered in 7.5 sec. = 30*7.5 - 1/2*4*(7.5)= 225 - 225/2 = 225/2

distance covered in 7 sec. = 30*7 - 1/2*4*(7)2= 210 - 98 = 112

so distance covered in first half of eighth sec. = 112.5 - 112 = 0.5 m

distance covered in last half of eighth sec. = 0*0.5 + 1/2*4(0.5)2= 0.5

so total distance covered in eighth sec. = 0.5 + 0.5 = 1 meter

IN THE PREVIOUS QUES ( THAT WAS FROM ROTATn TOPIC , SUBMITTED 5 DAYS AGO) , I AM STILL NOT GETTING THE SOLn  SUBMITTED BY YOU.

Asked By: SARIKA SHARMA 1 year ago

if this is the question based on number of rotations then read it carefully

Physics >> Mechanics part 1 >> Kinematics Medical Exam

A TOY CAR TRAVELS FROM A TO B AT A CONST. SPEED OF 20 km/h & IMMEDIATELY RETURNS TO A AT A CONST. SPEED v.  IF THE AVG. SPEED OF THE CAR IS 24 km/h . THEN v IS = ?

Asked By: SARIKA SHARMA 1 year ago

total distance = d+d = 2d km.

total time taken = d/20 + d/v hours

so avg. speed = 2d/[d/20 + d/v]

or 24 = 2/[1/20 + 1/v]

or 12 = 1/[1/20 + 1/v]

or 1/20 + 1/v = 1/12

or 1/v = 1/12 - 1/20

or 1/v = 2/60

or v = 30

A uniform electric field is established by connecting the plates of a parallel plate capacitor to a 12v battery. A charge particle of +6.24x10 to the power -6c moves from rest from the positive plate to the negative plate. when the charge reaches the negative plate,it acquires a speed of 3.4m/s.what is{a} the mass of the charge particle and{b} its final kinectic energy?

Asked By: HITESH 1 year ago

energy gained by the particle between the plates of the capacitor = qV

this will provide K.E. to the particle so qV = 1/2 mv2

solve for mass

then for K.E.

sir i have 2 questions,

1) how to integrate,  dx/(x^2 + y^2 )^1/2.

2) target 7, pg -91 derivation (end part in detail).

i will be grateful...

Asked By: APAR BANSAL 1 year agoSolved By: AMIT DAS

Calculate potential difference across a and b ,

Asked By: AMIT DAS 1 year ago

since net potential = 0, answer will be 0 for the given diagram. By interchanging the poles of any one battery this question will become meannigfull so change it and apply Kirchhoff law.

WHEN TWO SUBSTANCES OF DENSITYρ1 & ρ2 MIXED IN EQUAL VOLUME THEN RELATIVE  DENSITY OF MIXTURE IS 4    , WHEN THEY R MIXED IN EQUAL MASSES THEN RELATIVE DENSITY =3. THEN ρ1 X ρ 2  =?

ANS 12

Asked By: SARIKA 1 year ago

in first case 4 = [ρ1V + ρ2V]/2V

and 3 = [m+m]/ [m/ρ1 + m/ρ2]

solve now

A BALL FLOATS ON D SURFACE OF H2O IN A CONTAINER EXPOSED TO ATMOSPHERE . IF D CONTAINER IS COVERED & AIR IS COMPRESSED , D BALL WILL RISE . WHY?

Asked By: SARIKA 1 year ago

beacause due to compression density of air will increase and upthrust by air will make some contribution in the net upthrust so some extra part of the body will come outside water.

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

a double star consist of 2 stars of mass m & .2m. distance b/w them is r. d 2 stars revolve under their mutual gravitatn force then d 2 stars have equal periods of revolution . HOW?

Asked By: SARIKA SHARMA 1 year ago

according to newtons third law both star will give equal force to each other

so for first star of mass m,           m(2r/3)ω2  = F or ω = [3F/2mr]1/2

similarly for second                   2m(r/3)ω2 = F   or  ω = [3F/2mr]1/2

here 2r/3 and r/3 are taken according to centre of mass criteria.

a coin placed on a gramophone record rotating at 33rpm flies off d record , if it is placed at a dist. of more than 16cmfrom d axis of rotation . If d record is revolving at 66rpm , the coin will fly off if it is placed a distance not less than ?

ans=4cm

Asked By: SARIKA SHARMA 1 year ago

coin will fly off, if it will gain the required centrifugal

so apply mrω2 = mRW2

a 1 kg block is attached (& held at rest with outside support) to free end of vertically hanging spring of force const. 10Ncm-1. when block is released wat max. extensn does it cause when it comes to rest instantaneously?

Asked By: SARIKA SHARMA 1 year ago

apply mgx = 1/2 kx2

for max. extension.

a block of mass m is suspended by a light thread from an elevator . the elevator starts moving up with a uniform acc . the work done during first t sec by tensn in thread ?

although i know how to calculate this ques . i.e w.d =Fds =m(g+a)Xds  where ds=ut+1/2(at2)  because acc is const a/c to ques BUT I want to know for ds why acc is a ,why not (a+g)

Asked By: SARIKA SHARMA 1 year ago

tension in the thread depends on g an a both.

but displacement covered by elevator depends only on the acceleration of the elevator, it does not depend upon the acceleration g thats why we do not use g in that case for finding displacement.

remember that in the problem we have to calculate work done by tension in the thread

a 24.6 mev alpha particle moves towards gold nucleus[atomic no 79] calculate the distance of closest approach of alpha particle

Asked By: SHUBHAM SHARMA 1 year ago

upto closest approach total KE of α particle will become PE

so use the formula KE = 9*109 * Ze2e/r

here KE = 24.6 mev   convert it into joule first

solve equation for r

an electron in a picture tube of a tv set is accelarated from rest through a potentiol difference of 5000v .what is the speed of electron as a result of his accelaration.

Asked By: SHUBHAM SHARMA 1 year agoSolved By: SARIKA

FROM REST A BODY ROTATE  120 rotation/min  FOR 20 sec THEN IT ROTATE FOR 5sec  WITH SAME  ROTATION . FIND  HOW MANY ROTATn IT WILL MAKE?

Asked By: SARIKA SHARMA 1 year ago

ω = ω0+ αt

so 4π = 0 + α20       so α = π/5

so total angular displacement = 1/2 π/5 202 = 40 π  = 20 rotation

and with angular velocity 2 rotation/sec total rotations in 5 sec. = 10

so answer will be 20+10 = 30

A hunter aims his gun at a monkey sitting on a tree at the instant bullet leaves the gun the monkey drops down . WILL  THE  BULLET  HIT  THE  MONKEY  ?

Asked By: PRIYANKA DAHIYA 1 year ago

yes because monkey and bullet both are falling with the same gravity

a capacitor consists of two metal plates each 10cm by 20cm ,they are seperated by a 2 mm thick insulator with dielectric constant 4.1and dielectric strength 6*10to power7 v/m.what minimum voltage will cause spark in capacitor.
Asked By: GAURAV MAHATE 1 year ago

V = Ed = 6* 107*0.002

Find the potential difference Va - Vb between a and b ?

Asked By: AMIT DAS 1 year ago

let charge in the line of 24 volt is Q in the direction of battery and at point b, let the charges in the two lines are q and Q-q (q in the middle line)

now accoring to the Kirchhoff law

24-12 = Q/1 + q/2

and 24-6 = Q/1 + (Q-q)/4

solve these 2 for q and Q

then by point potential rules get the answer.

a chain of length L and mass m lies on the surface of a smooth sphere of rad. R>L with one end tied to the top of sphere . A.find the grav.potential energy of the chain w.r.t. Centre of sphere . B.suppose the chain is released and slides down the sphere .find k.e. Of the chain when it slid through an angle @ . C.find the tangential acc. dv/dt of the chain when chain starts sliding down.
Asked By: GAURAV MAHATE 1 year ago

consider a small segment of chain at angle β from top, its length = Rdβ and mass = mRdβ/L

its potential energy = [mRdβ/L]gRcosβ  now integrate it within the limits 0 to L/R

for getting the answer of the second part calculate potential energy twice once between the limits 0 to L/R and then between the limits θ to θ+(L/R)

then difference of potential energy = KE of the chain. solve it ?

for getting third part differentiate v obtained in the second part with respect to t, dθ/dt will be ω and it will be v/R

finally put θ and t = 0 for getting the answer.

my previous ques from fluid topic is not solved yet so pls reply that ques & that of chem of some other one

Asked By: SARIKA SHARMA 1 year ago

very soon you will get the answers

what is the formula for hole mobility in a semiconductor. ( not dimensional formula ,that i will find myself)

Asked By: SARIKA SHARMA 1 year ago

hole mobility  = velocity of hole/electric field applied

the force acting on a particle varies with displacement a/c to relatn F=ax1/2 +bsin (kx+o)

then which of the following expressn is meaningful?

1) F+b

2) (a2/kb) +o

3) a+b

4)(  a/b) +o

Asked By: SARIKA SHARMA 1 year agoSolved By: NIKHIL VARSHNEY

two point charge are placed on x axis a 2mc charge at x=10 and -1 mc at x =40cm calculate the potential at pt x =100cm

Asked By: SHUBHAM SHARMA 1 year ago

potential at 100 cm = k 2 * 10-3 / 0.9 - k 1* 10-3 / 0.6

now solve

IN THE PREVIOUS QUES P2V3 =K BUT SORRY I AM NOT GETTING HOW PV3/2 =K

Asked By: SARIKA SHARMA 1 year ago

take square root on both the sides

DURING AN ADIABATIC PROCESS IF THE PRESSURE OF AN IDEAL GAS IS PROPTIONAL TO THE CUBE OF ITS ABSOLUTE TEMP. THEN RATIO OF SPECIFIC HEATS AT CONSTANT PRESSURE & AT CONST. VOL IS?

ANS 3/2

Asked By: SARIKA SHARMA 1 year ago

P  α   T3

so P α  (PV)3

so P2V3 = K

or PV3/2 = K

so on the basis of PVγ  =  K  calculate  γ

A SUBMERGED BLOCK RISES BY 2cm WHEN MASS OF 10kg IS REMOVED ( BE4 THAT 10kg MASS WAS KEPT ON IT)

WHAT WILL BE THE VOLUME OF THE BLOCK

Asked By: SARIKA SHARMA 1 year ago

According to the given conditions

in first case block is completely inside water by putting 10 kg in it means density of block will be less than that of water

according to the law of floatation we know that

wt. of solid = upthrust

so 10g + AL(0.01)Dg = AL(0.01)dg

in second case

AL(0.01)Dg = A[L-2](0.01)dg

substracting 2nd eq. by 1st eq. we will get A = 1/2

now initial lenght in start is not provided by you, if it is given then calculate V = AL(0.01)

In thid question d and D are densities of liquid and solid, A and L are area of bottom of block and its length in cm.   0.01 is for converting cm. into m.

the density of two substances are in ratio 5:6 & specific heat are in ratio 3:5. their thermal capacity per unit volume will be in ratio?

ans 1:2

Asked By: SARIKA SHARMA 1 year ago

thermal capacity = ms = Vds

so thermal capacity per unit volume = ds

it takes 6 hours for ice layer thickness to grow from 1cm to 2cm on a lake in Siberia, ideally the time taken for thickness to grow from 3cm to 4cm?

ans 14 hrs

Asked By: SARIKA SHARMA 1 year ago

for this type of question relation between time and thickness will be

[x2] α t

so 22 - 12 = k6

and 42 - 3= kt

on dividing we will get 3/7 = 6/t

or t = 14

a cylinderical tube open at both ends has a fundamental frequency f in air the tube is dipped vertically in H2O so that half of it is in H2O the fundamental frequency of the air column is

1)f/2

2)3f/4

3)2f

4) f

aieee 2012

Asked By: SARIKA SHARMA 1 year ago

for first case       l = λ/2      so l = v/2f

for second case l/2 = λ/4  so  l/2 = v/4f

so f in both case are same.

two cars of masses m &M are moving in circles of radii r & R their speeds are such that they make complete circle in same time t. ratio of centripetal acceleration

1) m:M

2)R:r

3)1:1

4) MR:mr

aieee 2012 is the ans is (4)

Asked By: SARIKA SHARMA 1 year ago

since both make complete circle in same time t so angular velocities of the two will be same

now use F = mrω2

a cyclist  is moving in a circle of radius 20m with velocity 5ms-1mass =60kg of both boy & cycle find static friction on tyre

Asked By: SARIKA SHARMA 1 year ago

v2/rg = µ

so µ = 5*5/20*10 = 1/8

F= µ * N = 1/8 * 60*10 = 600/8 = 75 N

µ is the coefficent of static friction, Fs is static friction and N is normal reaction

A POINT CHARGE q IS ROTATED ALONG A CIRCLE IN D ELECTRIC FIELD GENERATED BY ANOTHER POINT CHARGE Q D WORK DONE BY ELECTRIC FIELD ON ROTATING CHARGE IN ONE COMPLETE REVOLUTn IS ZERO

WHY???

Asked By: SARIKA 1 year ago

Because this particle is revolving in an equipotential surface generated by other and work done = potential diff * q = 0

TWO EQ. +VE CHARGES R KEPT AT PT A & B D ELECTRIC POTENTIAL AT D PT B/W A & B (EXCLUDING THESE POINTS ) IS STUDIED WHILE ,MOVING FROM A TO B D POTENTIAL DECREASE THEN INCREASE WHY???

Asked By: SARIKA 1 year ago

at start when the point will be nearer to first charge, potential due to the nearer charge will be very high, at the middle point of the two charges it will be minimum and after that it will increase again due to its approach towards another charge.

There are two fixed spheres of charges Q and 4Q and the distance between their centres is 6R. The Radius of first sphere is R and radius of the secind one is 2R. A charge -q is to be projected from the along the line joining their centres ( it is on the surface of the sphere with radius R), so that  it can reach the surface of other solid sphere of charge 4Q. What will be the minimum velocity to be given so that it reaches there?

sir i have used energy conservation in this problem :

-kqQ/R - kQ4q/5R +.5 mv^2 = -kQq/4r - kqQ4/2R

but im not getting the answer .....is anything left in ths  ..please telll

Asked By: AMIT DAS 1 year ago

first find a point midway between the two spheres where net E will be 0

Then consider v = 0 at that point and compare the potential energy + kinetic energy of the starting point and that obtained point.

Define Potential Energy?

Asked By: SIDDHANT KAPOOR 1 year ago

Potential energy is the energy of a particle due to its position relative to the reference point taken.

CENTRIPETAL & CENTRIFUGAL FORCES ALWAYS ACT IN PAIR. IS D STATEMENT IS CORRECT IF YES THEN Y &IF NOT  THEN ALSO GIVE REASON

Asked By: SARIKA 1 year ago

if you are observer in the ground then centripetal will work but if observer is in the rotating frame then centrifugal force will work. These two force does not form a pair

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

WEIGHT OF A BODY ON SURFACE OF EARTH DEPENDS UPON D ANGULAR SPEED OF ROTATn OF EARTH ABOUT ITS OWN AXIS. IS THIS STATMENT IS CORRECT? PLS. GIVE REASON ALSO

Asked By: SARIKA 1 year ago

since a cetrifugal force works on the body and this force depends on angular speed so statement is correct.

Physics >> Optics >> Photometry Medical Exam

IN D QUES OF RED ROSE IN WHICH  WE HAVE TO FIND COLOR WHY THE COMPLEMENT COLOR OF BLUE i.e ORANGE &RED WILL B SEEN

Asked By: SARIKA 1 year ago

since only blue light is present so any other colour can not be the answer

formatn of rain drop is/r involved

1)saturatn of vapour pressure

2) temp.

3)viscosity

4) surface tension

MORE THAN ONE OPTn IS/R CORRECT

Asked By: SARIKA 1 year ago

saturation of V P, because due to this drops will be created.

and surface tension cause for the shape of drop

QUES  TWO IDENTICAL SOUNDS s1 &s2  reach at a point P in phase. resultant loudness at a point P is ndB higher than loudness of s1 the value of n =?

ANS) 6

Asked By: SARIKA 1 year ago

Let intensity of one source = I

then intensity at a point where two waves meet in phase = I+I+2√I√Icos0 = 4I

now loudness = 10logI/I0 due to a single source

and loudness at the point where 2 waves meet in phase = 10log4I/I= 10logI/I0+ 10log4

since 10log4 = 6 so increment = 6

IN THAT QUES OF CENTRE OF MASS BOTH THE OPTION ARE GIVEN THEN  IN EXAM HOW WE KNOW THAT WHICH ONE IS CORRECT. AS WE USE Vm  /M+m =V OF PLANK & m= mass of man

Asked By: SARIKA 1 year ago

I could not understand, what the question is,

THE PRESSURE P &VOL V OF AN IDEAL GAS BOTH INCREASE IN A PROCESS

A)SUCH CASE NOT POSSSIBLE

B)WORK DONE BY SYSTEM IS +ve

C)TEMP. OF SYS. MUST INCREASES

D)HEAT SUPPLIED TO GAS IS EQUAL TO THE CHANGE IN INTERNAL ENERGY

MORE THAN OPTn R CORRECT

Asked By: SARIKA 1 year agoSolved By: NIKHIL VARSHNEY

THE MAXm TENn IN STRING OF A SIMPLE PENDULUM IS 1.2TIMES THE MINm TENSION. IF a IS ANGULAR AMPLITUDE THEN a WILL BE

A)cos-1(4/5)

B)COS-1(3/4)

C)cos-1(15/16)

d) cos-1(7/8)

Asked By: SARIKA 1 year ago

max tension at bottom point = mg+mv2/r

min tension at extreme point = mgcosθ

according to the given condition mg+mv2/r = 1.2mgcosθ       (1)

and by energy conservation 1/2mv2 = mg(r-rcosθ)                   (2)

solve now answer will be C

Physics >> Optics >> Photometry Medical Exam

A RED ROSE IS KEPT IN BLUE LIGHT. WHAT COLOUR OF ROSE WILL BE SEEN?

Asked By: SARIKA 1 year ago

Since it is red rose it means it will absorb all colours other than red so in blue light it will be seen as black.

A PARTICLE OF MASS m IS MADE TO MOVE WITH UNIFORM SPEEDv ALONG PERIMETER OF A REGULAR HEXAGON

. MAGNITUDE OF IMPULSE APPLIED AT EACH CORNER OF HEXAGON IS

A)mv

b)mv31/2

c)mv/2

d)zero

Asked By: SARIKA 1 year agoSolved By: NIKHIL VARSHNEY

if more air is pushed in soap bubble the pressure in it decreases WHY?

Asked By: SARIKA 1 year ago

since inside soap bubble pressure is given by the formula P0 + 4T/R and on pushing air  R will increase so pressure will decrease.

HOW WE WILL CALCULATE 10e-2 in the ques of NUCLEAR PHY.

Asked By: SARIKA 1 year agoSolved By: NIKHIL VARSHNEY

IN THE  PREVIOUS QUESn THAT WAS   BALL IS DROPPED  FROM HEIGHT 5M ACC. DUE TO GRAVITY IS NOT KNOWN & WE HAVE TO FIND = IT LOSES ITS VEL. BY WHICH FACTOR WHEN IT RISES TO 1.8M

IN THE SOLn SUBMITTED BY SOMEONE HE HAS TAKEN ACC.  WHILE FINDING VEL EQN= =V2-U2=2AS    AS CONST. SO I WANT TO KNOW WHY IN THIS QUES ACC. IS TAKEN CONST. WHILE THERE IS NO MENTn IN QUES

Asked By: SARIKA 1 year ago

consider once agian

a sample of radioactive element has mass 10g at a instant t=0 the approximate mass of this elementcin the sample after 2

mean lives is ?

ans 1.3g

Asked By: SARIKA 1 year agoSolved By: NIKHIL VARSHNEY

a small block of mass m is kept on a rough inclined surface of inclination o * fixed in an elevator the elevator goes up with a uniform velocity v &block doesn't slide on the wedge the w.d by the force of fricition on block in t time is?

ANS) mgtsin2o*

Asked By: SARIKA 1 year ago

work done by the force of fricition on block in t time = fvtcos(90-θ) = mgsinθvtsinθ

TWO EQUAL MASSES ARE ATTACHED TO TWO ENDS OF A SPRING CONST. k THE MASSES ARE PULLED OUT SYMMETRICALLY TO STRECH SPRING BY A LENTH x OVER ITS NATURAL LENTH. WORK DONE BY THE SPRING ON EACH MASS IS -1/4kx2.  HOW

Asked By: SARIKA 1 year ago

total work done on the spring = 1/2kx2

so work done by the spring = -1/2kx2

this work is done on 2 masses so work done by the spring on 1 mass = -1/4kx2

Q WHICH SET CAN'T ENTER INTO THE LIST OF FUNDAMENTAL QUANTITIES IN ANY SYSTEM

a) lenth, mass, velocity

b)lenth, time,velocity

c) mass, time, velocity

d)lenth, time,mass

OPTn B IS CORRECT BUT I WANT TO KNOW THE REASON

Asked By: SARIKA 1 year agoSolved By: NIKHIL VARSHNEY

A SYSTEM OF m1 &m2 THE PARTICLE m1 IS PUSHED TOWARDS THE CM OF PARTICLES THRU DIST. d BY WHAT DIST. WOULD m2 MOVE SO AS TO KEEP MASS CENTRE OF PARTICLES AT THE ORIGINAL POSITION

SIR, I WANT TO KNOW Y ans is m1d/m2  WHY NOT m1d/ m1+m2?

Asked By: SARIKA 1 year ago

with centre of mass as reference point m1d = m2x so x can be calculated.

IF MORE AIR IS PUSHED IN A SOAP BUBBLE THE PRESSURE IN IT WILL INCREASE OR DECREASE . PLS GIVE REASON ALSO

Asked By: SARIKA 1 year ago

since inside soap bubble pressure is given by the formula P0 + 4T/R and on pushing air  R will increase so pressure will decrease.

Physics >> Electricity >> Capacitors Medical Exam

Q      Q1=1.5C ,  R1=2M, Q2 =3C&R2=1M WHEN THESE SPHERICAL CAPACITER TOUCHED EACH OTHER THEN CHARGE  WILL MOVE OR NOT . IF MOVE THEN HOW MUCH

(MANIPAL 2012)

Asked By: SARIKA 1 year ago

on touching, the new ratio of charges = x/y = 2/1                 this is by the formula q1/q2 = C1/C2 = R1/R2

and x+y = 1.5+3 = 4.5

or 2y+y = 4.5

or y = 1.5

so 1.5 C will move from second to first.

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

Q IF A BODY IS PROJECTED UPWARD WITH SPEED 1/2 OF ESCAPE SPEED OF EARTH THEN MAXn HEIGHT ATTAINED BY IT IS=?

Asked By: SARIKA 1 year agoSolved By: NIKHIL VARSHNEY

escape velocity = √(2GM/R)   so 1/2 of escape = 1/2√(2GM/R)

so according to given condition on applying energy conservation we will get

energy at start = energy at the heighest point

or    -GMm/R +  mv2/2 =  -GMm/R1 +  0

or     - GMm/R   +  2GMm/8R =  -GMm/R1 + 0

solve now for finding R1  then find R1-R

Q A BALL IS DROPPED FROM HEIGHT 5 M ON A PLANE WHERE ACC. DUE TO GRAVITY IS NOT KNOWN. ON BOUNCING IT RISES TO 1.8M . IT LOSES ITS VELOCITY ON BOUNCING BY A FACTOR OF =?

By using formula h'=h e2n    ans comes 3/5 but given is 2/5. in two reference book.

Asked By: SARIKA 1 year agoSolved By: NIKHIL VARSHNEY
Physics >> Mechanics part 1 >> Kinematics Medical Exam

IN QUESTn < B/W 2 NON ZERO VECTOR A &B 120* RESULTANT GIVEN IS GREATER WHILE ACC. TO IT SHD BE LESS SO I REQUEST  YOU SIR TO AGAIN CHECK . QUES FROM HC  VERMA

Asked By: SARIKA 1 year ago

i am confirmed, option B will be correct answer

Physics >> Mechanics Part 2 >> Gravitation Medical Exam

Q A UNIFORM SPHERICAL SHELL GRADUALLY SHRINKS MAINTAING ITS SHAPE. THE GRAVITATn POTENTIAL AT THE CENTRE WILL DECREASE. Y DOESN'T IT SHD REMAIN CONST. =?

Asked By: SARIKA 1 year ago

Formula for gravitational potential at centre is -3/2 GM/R so if R will decrease V will increse numerically but - is present so decreases

Q IF IN THE SAME QUESTn OF BAROMETER THE ELEVATOR IS ACCELERATING UPWARD READS 76cm. THEN AIR PRESSURE IN ELEVATOR IS >76cm PLS EXPLAIN THE CONCEPT BEHIND SUCH CASES.

Asked By: SARIKA 1 year ago

when elevator will move in upward direction the extra Hg level will feel a down force and given that in movable condition it is 76 cm. Hg so really it will be more than 76 cm.

Physics >> Mechanics part 1 >> Kinematics Medical Exam

Q A CURVE IS REPRESENTED BY y=sinx IFx IS CHANGED FROM PIE/3 TO PIE/3+PIE/100, FIND APPROX. CHANGE IN x?

Q  A CAR IS GOING DUE NORTH AT A SPEED =50km/h IT MAKES A 90* LEFT TURN WITHOUT CHANGING SPEED THE CHANGE IN VEL. OF CAR IS=?                                                                                                  (ANS 70km/h towards south west )  i want to know that here we are  just changing the directn so only directn. shd. b change but here magnitude is also changing HOW?

FLUIDS

Q A BAROMETER KEPT IN N ELEVATOR READS 76cm WHEN IT IS AT REST . IF ELEVATOR GOES UP WITH INCREASING SPEED READING WILL BE <76 cm . IS REASON IS THAT PRESSURE IS DIRECTLY PROPTn TO HEIGHT ?

Asked By: SARIKA 1 year ago

I think we have to caculate change in y

since y = sin x

so dy = cosx dx = cosπ/3* π/100 = π/200

the initial velocity of car = 50j      and after turn velocity = -50i                              here i and j are the unit vectors along east and north direction

so change in velocity = -50i - 50j

its mod = 50 √2 = 70

Because in barometer the extra Hg level will experience a downward force so Hg level will decrease.

Physics >> Mechanics part 1 >> Kinematics Medical Exam

Q A VECTOR A POINTS VERTICALLY UPWARD & B PTS. TOWARDS NORTH. VEC. PRODUCT ACROSS B IS ALONG WHICH DIRECTION?

Q LET < B/W TWO NON ZERO VECTORS A &  B BE 120* &  ITS RESULTANT BE C THEN

1) C MUST BE EQUAL TO MOD. OF A-B

2) C MUST BE LESS THAN MOD. OF A-B

3)C MUST BE GREATER THAN MOD. OF A-B

4)C  MAY BE EQUAL TO MOD. OF A-B

Asked By: SARIKA 1 year ago

Take your right hand fingers along A and curl these fingers along B, thumb will give you an idea for A × B. for the given problem answer will be west.

|A+B|2 = |A|2 + |B|2+ 2A.B            (1)

|A-B|2 = |A|2 + |B|2 - 2A.B             (2)

on subtracting (2) by (1)

|A+B|2 - |A-B|= 4A.B

so C2 = |A-B|+ 4A.B

or C2 = |A-B|2 +4|A||B|cos120

since cos120 is negative so C will be less than |A-B|

Q E=ELECTROMAG F, G=GRAVT.F, N = NUCLEAR F B/W 2 e- AT A GIVEN PTN. THEN E>G>N HOW=?  BECAUSE G< THEN OTHER FORCES.

Asked By: SARIKA 1 year ago

for the distance upto fermi level order will be N>E>G

but  the distance between electrons is greater than fermi level so the given order is justified because now nuclear forces will be very weak.

Physics >> Mechanics part 1 >> Kinematics Medical Exam

Q A PARTICLE START MOVING FROM REST STATEVALONG A STRAIGHT LINE UNDER ACTION OF A CONST. F & TRAVEL DIST. X IN FIRST 5 sec THE DIST. TRAVELLED IN NEXT 5 sec WILL BE=?

QA CUBE OF A SIDE a IS HEATED TO RAISE ITS TEMP. BY 3*C IF Y IS COEFF. OF VOL. EXPANSION THEN TOTAL INCREASE IN AREA=? (ANS 12Yasqure. )

WAVES & OCILL.                 Q OBSV. IS MOVING TOWARDS A SOURCE AT REST WITH 30m/s if sound is sounding a sound of freq 500Hz & speed of sound is 300m/s then wavelenth by obsv. =?

Q TEMP. OF GAS INCREASED BY 2K KEEPING PRESS. CONST. SPEED OF SOUND IN GAS=?    ans=1.22m/s

Q THE MASS OF ELEVATOR = 4000kg .STARTING FROM REST HOW MUCH DIST. WILL IT RISE IN 2s IF TENSION =56 kN .  I want to know why we use ,' a ' for cal. dist. why 'a+g' is NOT use.

Asked By: SARIKA 1 year ago

by formula s = ut + 1/2 a t2

u = 0 [given]

so       s = 1/2 a (5)2= 25a/2       for first 5 sec.

and    s = 1/2 a (10)2 = 50a        for total 10 sec. from start

so for next 5 sec. distance = 50a - 25a/2 = 75a/2

answer :  a'3 = a3 (1+ γ3)     here a' is the side of the cube after heating it

so a' = a (1+3γ)1/3

so area increment = 6a'2 -  6a2 = 6a2 [(1+3γ)2/3 - 1] = 6a2 [ 2γ] = 12γa2

Please submit all the questions seperately.

λ = v/n = 300/500

so according to formula v'/v  = [(T+2)/T]1/2

or v'/v = 1 + (1/T)

so v' - v = v(1/T) = 332*1/273 =  1.22       here 332 is the speed of sound at 273K

when a machine works , you should not count gravity, for example if we raise our hand upword with uniform velocity then gravity makes no problem in it because our hand is working by our internal capabilitites

Physics >> Mechanics part 1 >> Kinematics Medical Exam

Q A PARTICLE STARTS MOVING WITH ACC.=2m/s 2  DISTANCE TRAVELLED BY IT IN 5th HALF SECOND IS=?

Q A PARTICLE  MOVES IN A STRAIGHT LINE & ITS POSITION X  AT TIME t IS GIVEN BY X RAISED TO P. 2=2+t . ACC.   IS GIVEN BY=?                                                                                                                                                (ans . -2/4t cube)

Asked By: SARIKA 1 year ago

first calculate distance of 4 seconds by using s = ut + 1/2 a t2

then distance of 4.5 sec. by same formula

difference of these 2 is the distance of 5th half sec.

but some writter consider 5th half as 1/2 +1/2+1/2+1/2+1/2 means 2.5

so they use the same formula first for 2 sec then for 2.5 sec, then their difference.

according to my opinion first is more true way to solve.

Dear Sarika please submit only one question in a box, for a new question use another box so that i could give answers more quickly.

According to the given condition

x2 = 2+t

on differentiaing we get 2x dx/dt = 1

or v = 1/2x

now differentiate it again we get dv/dt = -(1/2x2 )(dx/dt) = -(1/2x2 )(-1/2x) = 1/4x3

Q  HEAT & WORK ARE EQUIVALENT. THIS MEANS

TEMP OF BODY CAN BE INCREASED BY DOING WORK ON IT. PLS TELL HOW THIS STAT. IS CORRECT.Q

Q IF H IS SUPPLIED TO IDEAL GAS IN ISO PROCESS. THEN W= +ve HOW? BECAUSE IF ISO THEN U= 0 & EQN IS Q=W+0 & H IS SUPPLIED SO Q=-veSO W =-ve.so ans shd be -veBUT ANS GIVEN IS +ve PLS TELL ANS WITH EXPL. THANKS FOR PRE SOLUTIONS .

Asked By: SARIKA 1 year ago

This means heat can be used to make work and work done produces heat

By doing 4.2 joule work 1 cal. heat will be produced in a body so due to this 1 cal, temp. will increase

In physics heat is supplied means Q will be +ve so W will also be positive hence is correct. A system is placed in refrigrator for absorbing heat from the body, this process will have Q -ve.

Q  IF Al DIPPED IN H2O AT 10*C THEN FORCE OF BUOYANCY WILL INCREASE OR DECREASE?

Q TEMP. OF A SOLID OBJECT IS OBSV.  CONST .DURING A PERIOD . IN THIS PERIOD

a)HEAT MAY HAVE BEEN SUPPLIED TO IT

b) H MAY HAVE BEEN EXTRACTED FROM IT

c) no H SUPPLIED TO IT

d)NO H EXTRACTED FROM IT

more than one opt is correct . pls explain your each opt with expln.

Asked By: SARIKA 1 year ago

It depends that either Al or water will change its density more rapidly, because Bouyancy is based on densities of solid and liquid

Answer : a, because it may be an isothermal process

b, because in isothermal process, surrounding can also give heat to the system.

c, may be the process is adiabatic

Q gas of certain mass at 273K is expanded to 81 times its vol. under adia. condition. if gamma = 1.25 for gas then its final temp. = ?

Q for a const. vol. gas thermometer one should fill gas at high temp & low pressure WHY ?

Q  iF TEMP of uniform rod is slightly increase by del T its moment of inertia about 90* bisector increase BY = ? (ANS 2alpha I del T ).

Q Al sphere is dipped into H2O at 100*C if temp is increased forse of buoyancy will inc. OR decreased WHY =?

DENSITY OF A SUB. IS 10g/cc at 0*C &at 100*C d= 9.7 g/cc . coeff. of linear expantion is =?

Asked By: SARIKA 1 year ago

so 273*V0.25 = T*(81V)0.25

so 273/3 = T

Answer :   Because real gases perform ideal behaviour in this range.

on increasing temperature by dT new inertia = 1/12 M[L(1+αdT)]2

so increment in inertia = 1/12 ML2 [(1+αdT)2-1-] = 1/12 ML2 [ (αdT)2 + 2αdT ]                 now neglect (αdT)because it is small term

Answer :   Since temperature is already 100 degree centigrade so on increasing it further density of Al will increase rapidly in comparision to density of water so Buoyancy force will be increased.

Answer :   use the formula d100 = d/ (1+γ100)   here γ=3α                    calculate α

Q Agraph having temp *C along xaxis& *F along y axis. if graph is straight then it intercept +ve y axis. WHY ?

Asked By: SARIKA 1 year ago

(F-32)/9 = t/5

so F = 9t/5 + 32

on taking t = 0 we will get F = 32

thats why it makes an intercept of 32 in y axis

sir,  can u please post a topic on rigid body rotation ? mainly heip to solve question please.  with some examples.

Asked By: SHUBHAM VED 1 year ago

Yes, I will do very soon.

Q 1-when current passes through a solenoid .then what happens to the length of solenoid?

Q2-a current carrying wire carrying current i normally into the paper at the centreof current carring circular ring.the magnetic force acting on the circular ring is ?

Q3- To increase the current through the solenoid from 1A TO 2A ,30J work is done by thr battery.work done  by the same battery in increasing the current from 3A TO 4A IS?

Q4- When a closed looop is held stationary in  magnetic field b/w north & south pole of 2 permanent magnets of different dipole moments , then current will be induced in the loop or not?

Asked By: TANVI GROVER 1 year ago

1. the length will decrease as the current in the two consecutive turns of the solenoid are in same direction. which will create an atrraction.

2. since B produced by the wire is parllel to the direction of dl so net force will be 0

3.dw = Lidi first take limit 1 to2 and w=30 to find the L (INTEGERATE)

After than again use the above formula  taking limit 3 to 4 .put L here ,L= 20

4. I think no emf will be induced as the flux is not changing.

These answers by NIKHIL VARSHNEY are correct

a uniformrope of lenth 10 m and mass 12 kg hangs verticaly from a rigid support .  a block of mass 4 kg is attached to the free end  of  the rope . atrans verse wave of wavelenth 00.03 m is prodused at the lower end .  wavelenth of pulse when it reaches upper end  will be?

Asked By: SHUBHAM VED 1 year ago

at top point tension in the string = 16g

and at bottom point T = 4g

and v = √(T/m)   here m is mass per unit length which is same throughout the rope.

first calculate v at both the points

frequency will be same throughout

so use the formula v = nλ twice

once at bottom and once at top point

then by diving these 2 formulae we will get the result

try it.

why is electric field of earth is in order of 100v/m any reason by formulae

Asked By: ABHISHEK JAIN 1 year ago

emf generated between the extremes of equator line = vBl = RωBl

so E = RωBl/l = RωB = 2πRB/T

now calculate

the speed of sound in hydrogen at stp is v. the speed of sound in a mixture containing 3parts of hydrogen and 2 parts of oxygen at stp will be

Asked By: KESHAV 1 year agoSolved By: NIKHIL VARSHNEY

please,  write tibs about tidal effect  and it's fourmula ?   Is it depend inversly on the cube of the distance? and is  tidal effect of the moon's pull grater than the tidal effect of Sun?

Asked By: SHUBHAM VED 1 year ago

The tidal force is a secondary effect of the force of gravity and is responsible for the tides. It arises because the gravitational force per unit mass exerted on one body by a second body is not constant across its diameter, the side nearest to the second being more attracted by it than the side farther away. Stated differently, the tidal force is a differential force. Consider three things being pulled by the moon: the oceans nearest the moon, the solid earth, and the oceans farthest from the moon. The moon pulls on the solid earth, but it pulls harder on the near oceans, so they approach the moon more causing a high tide; and the moon pulls least of all on the far oceans (on the other side of the planet), so they stay behind more, causing another high tide at the same time. If we imagine looking at the Earth from space, we see that the whole Earth was pulled, but the near oceans more and the far oceans less; the far oceans stayed behind since they are pulled less (since they are farther away).

Tidal effects become particularly pronounced near small bodies of high mass, such as neutron stars or black holes, where they are responsible for the "spaghettification" of infalling matter. Tidal forces create the oceanic tide of Earth's oceans, where the attracting bodies are the Moon and, to a lesser extent, the Sun.

Formula

$\vec a_t$(axial) $~ \approx ~ \pm ~ \hat r ~ 2 \Delta r ~ G ~ \frac{M}{R^3}$

why the direction of electric dipole moment is from -ve to +ve

Asked By: HIMANSHU MITTAL 1 year ago

It is the direction of electric field due to a dipole at axial point.

a hollow sphere of mass M (in K.G.) radius R (in m.)  is rotating with angular  frequency  omega(in radsec)  . it suddenly stops rotating and 75% of  the K.E. converted  into heat energy .   if S joulekg-kelvin is the spesific heat of material of the sphere, the rise of temperature of the sphere is ?

Asked By: SHUBHAM VED 1 year ago

Rotational K. E. = 1/2 I ω2

so 0.75 [1/2 I ω2] = M S dT

and I = 2/3 M R2

now solve

2 comparable masses m1 and m2  r orbiting about their bodycenter o at distance r1 and r2 from  their  body center respectively  with a common period T. the squar of time period  ?

Asked By: SHUBHAM VED 1 year ago

According to the diagram

Gm1m2/(r1+r2)2 = m1r1ω2 = m2r2ω2

compare first part with either second or third part of the given equation for getting ω2 then find T2

how can we calculate ratio of intensities of two sound waves  having unequal amplitudes (one having double the amplitude of the other - both are sinusodial waves) and the graph is displacement vs time .

Asked By: AMIT DAS 1 year ago

Intensity of a wave depends on two power of amplitude and two power of frequency. Check the graph carefully for getting idea about frequency and details of amplitude are given in the question.

A point mass 'm' is placed on the axis of a uniform ring of same mass 'm' & radius 'r' the maximum force of attraction b/w them is

Asked By: AMIT DAS 1 year agoSolved By: NIKHIL VARSHNEY

The activity of a freshly prepared  radioactive sample is 10^10 disintegrations per second, whose mean life is 10^9 sec.

The mass of an atom of this radioisotope is 10 ^ -25 kg.  The mass (in mg) of the radioactive sample is

Asked By: NITIN RAO 1 year ago

dN/dt = -λN

1010 = -[1/109] N                                               λ = 1/mean life

so N = 1019 disintegration

so mass of radioisotope = 1019 *10-25 = 10-6 Kg = 1 mg

A transparent sheet of paper of refractive index 'n' and thickness 't' is pasted on one of the slits in YDSE  which uses monochromatic light of wavelength  'x'  . How many fringes will cross through the centre if the paper is removed ?

Asked By: NITIN RAO 1 year ago

total path difference created by the paper = (n-1)t

geometrical path difference = yd/D

so position of central maxima will be obtained by eq. (n-1)t  = yd/D

here y is position of central bright, d is slit appeture and D is distance between slits and screen.

so y = (n-1)tD/d

width of maxima = xD/d ,                 x is wavelength of light

so no. of fringes shifted = [(n-1)tD/d]/[xD/d] = (n-1)t/x

we taken a equal length of wire like copper and  maganim which one is more thicker ?

Asked By: VIKRANT KUMAR 1 year ago

length are equal and metals are different

but none of the two is a deciding factor for the thickness of wire, so question is irrelevent

why current is not flow in insultor  give me proper reasion and its funtions ?

Asked By: VIKRANT KUMAR 1 year ago

This can be explain by using band theory.

According to this theory movable electrons are present in valence band but for conduction their transfer to conduction band (far from the nucleus in comparison to valence band) is compulsory. In insulators the gap between valence and conduction band is large thats why tranfer is not possible so no conduction

two trains each 100m long ,oving in opposite directions ,cross each other in 8sec .if one is moving twice as fast than other ,then the speed of the faster train is?

Asked By: YOMOL RAJU 1 year ago

Crossing means to cover the length of both the trains

so according to the given conditions 2v+v = (100+100)/8

or 3v = 25 or v = 25/3

so speed of faster train = 50/3 m/s

there is a small block of mass m kept at the left end of a larger block of mass M and length l.The system can slide on a horizontal road.The sysytem is started towards right with an initial velocity v. The friction coefficeient between the road and the bigger block is μ and that between the block is μ/2. Find the time elapsed before the smaller block separates from the bigger block?

Asked By: AMIT DAS 1 year ago

Since there is no force for accelerating the larger block so larger block will be retarded due to this smaller block will move in forward direction

for the process equations are

0 + (µ/2)mg - µ(M+m)g = Ma   (1)

(µ/2)mg - ma = ma1                 (2)

take the value of a from eq (1) to eq (2) and get a1

then l = 0t + (1/2)a1 t2

a wedge of mass M' is connected with a hanging block of mass M with a light string and a massless pulley. and a small block of mass m is placed on the top of te wedge. find the mass M of the hanging block which will prevent the smaller block from slipping over the wedge . All the surfaces are smooth .

Asked By: AMIT DAS 1 year ago

According to the given diagram       Mg - T = Ma,             T = (M'+m)a       and           macosθ = mgsinθ

solve these equations.

please solve  q. no. 33 on page no. 82 of hc verma  (part -1 newtons laws of motion)......

Asked By: AMIT DAS 1 year ago

Dear Amit

this book is not available here so please send the question.

There is some amount of water in the beaker, and a vertical  rod is passing through the centre of the circular base of the cylindrical beaker which is rotated with angular velocity ω  , then water takes a particular shape(miniscus is formed). Find the equation of the miniscus of water when the mid point of  the miniscus just touches the bottom surface of the beaker?

Asked By: AMIT DAS 1 year ago

after making the diagram, complete the miniscus as a sphere, then following conditions will be obtained

1) h = R(1-cosθ)  here h, R and θ are height of miniscus, radius of the sphere and  contact angle.

2) R = r/cosθ, r is the radius of beaker

3) tanθ = g/rw2

4) πr2hρ - πR3ρcos2θ = 2πrTcosθ

There are 4 equations, remove R, θ and T and get a relation between h and r in terms of g, w, ρ and π

Physics >> Optics >> Refraction IIT JEE

what is meant by rate of change of transverse magnification

Asked By: NIKHIL VARSHNEY 1 year ago

transverse magnification m = v/u so rate of change of trasverse magnification is dm/dt. calculate by differentiation

what is the main use of capacitors

Asked By: ASHOK UPPUTURI 1 year ago

Capacitor :- A capacitor is a device to store energy

Focsl length of lens depends on colour of light?

Asked By: NIKHIL VARSHNEY 1 year ago

Yes, f depends on µ and µ depends on colour of light

the ratio of intensities between two coherent sound sources is 4:1. the difference of loudness in decibel between maximum and minimum intensities, when they interfere in space is

(1) 10 log2

(2) 20 log3

(3) 10 log3

(4) 20 log2

Asked By: HIMANSHU MITTAL 1 year ago

I1/I= 4/1 so a1/a2 = 2/1 so amax/ amin = 2+1/2-1 = 3/1 so Imax/ Imin= 9/1

now loudness L = 10 log(I/I0)

so difference of loudness = L1-L2 = 10 log (9I/I) = 10 log9 = 20 log3

two coherent light sources A and B with seperation 2λ are placed the x-axis symmetrically about the origin. they emit light of wavelength λ. obtain the position of maximas on a circle of large radius R lying in the xy plane and with the center at origin

Asked By: HIMANSHU MITTAL 1 year ago

for maxima path diffrence should be integral multiple of λ.

It is given that two coherent light sources A and B with seperation 2λ are placed on the x-axis symmetrically about the origin, and we have to get the points of maxima in the circle so at the point where circle cuts the X axis (path diffrence = 2λ) and where circle cuts the Y axis (path difference = 0) will be the point of maxima. Besides it one point will also be present in the circle in first quadrant where path difference will be λ so it will be a maxima also. it means total 8 points are there

two sound waves having intensities 4 unit and 9 unit coming from two coherent sources arrive at a point along the same line simultaneously  in same phase. resultant intensity at the point will be

Asked By: HIMANSHU MITTAL 1 year ago

Use the formule I = I1 + I2 + 2 √I1 √I2 cosθ

here θ = 0

two sound sources of intensity I and 4I are used in an interference experiment. find the intensity at points where the waves from the two sources are superimposed with a phase difference of

(1) zero

(2) π/2

93)π

Asked By: HIMANSHU MITTAL 1 year ago

Use the formule I = I1 + I2 + 2 √I1 √I2 cosθ

here θ = 0

in a large room, a person receives direct sound wave from a source 120m away from him. he also receives wave from the same source which reaches him after being reflected from 25m high ceiling at apoint midway between them. the two waves interfere constructively for wavelength of

(1) 20, 20/3, 4

(2) 10, 5, 3.33

(3) 10, 20, 30

(4) 15, 25, 35

Asked By: HIMANSHU MITTAL 1 year ago

path difference between two waves one coming directly (path length = 120 m) and other coming after reflection (path length = 130), you can get this by geometry

so path difference = 10 m

for constructive interference path difference should be a multiple of wavelength so (2) is answer

a source of sound and an observer are moving with velocities v = (2i + 4j)m/s and v = (6i - 3j)m/s. if frequency of source is 400 Hz, then frequency observed by observer will be

Asked By: HIMANSHU MITTAL 1 year ago

dot product of the two velocities given = 0, means observer and source are moving perpendicularly, so observer will observe the original frequency.

two waves are represented by y = Acosωt and y = Asin(ωt - π/6), superimpose on each other. the amplitude of the rsultant wave is

Asked By: HIMANSHU MITTAL 1 year ago

first convert cos into sin then calculate phase difference, its value will be π/2 + π/6 = 2π/3

now use the formula for resultant amplitude

which of the following phenomenon cannot be observed with sound waves?

(1) diffraction

(2) polarisation

(3) reflection

(4) interference

Asked By: HIMANSHU MITTAL 1 year ago

polarisation

a source of sound of frequency f emits sound wave with speed v is at rest. if an observer is moving towards source with speed Vo(V not), then wavelength of sound waves observed by the observer will be

(1) v/f

(2) (v - Vo)/f

(3) [v(v - Vo)]/[f(v + Vo)]

(4) [v(v + Vo)]/[f(v - Vo)]

Asked By: HIMANSHU MITTAL 1 year ago

since velocity and frequency are changing proportionally so wavelength will be constant = v/f

a sonometer wire supports a 4kg load and vibrates in fundamental mode with a tuning fork of frequency 416 Hz. the length of the wire between the bridges is now doubled. in order to maintain fundamental mode the load should be changed to

Asked By: HIMANSHU MITTAL 1 year ago

for sonometer wire

in fundamental mode l = λ/2 = v/2f       here l, λ and f are length , wavelength and frequency respectively

now v = √(T/µ)      here T and µ are tension and mass per unit length

so finally we will get l = √(T/µ)/2f

make two equations by using this formula and given conditions

in the two equations f and µ will be same

in a stationery wave, there is no energy current, but there is energy density. (TRUE/FALSE)

Asked By: HIMANSHU MITTAL 1 year ago

TRUE

at STP, the speed of sound in hydrogen is 1324ms‾¹ then the spped of sound in air (at STP) is

Asked By: HIMANSHU MITTAL 1 year ago

formula for speed of sound is v = √(γRT/M)

you have to form two equations for the two mediums, for both the mediums γ will be same because Hydrogen and Air both are diatomic gases, T will also be same for both the cases are taken in STP, only M will be different

a person is standing between two vertical walls. he heard the echo of his sound after t = 1s and t = 1.5s. distance between walls is (speed of sound in air = 340ms‾¹

Asked By: HIMANSHU MITTAL 1 year ago

time taken by the sound to reach upto the first wall = 0.5 sec

similarly time taken by the sound to reach upto the second wall = 0.75

so total time = 1.25 sec. so distance between the walls = 340 * 1.25 = 425

which of the following is minimum audible wavelength at room temperature?

(1) 20mm

(2) 20cm

(3)20m

(4) 20km

Asked By: HIMANSHU MITTAL 1 year ago

maximum audible frequency = 20000 Hz

Velocity of sound = 340 m/s

so minimum audible wavelength = 340/20000 m = 34000/20000 cm = 340/20 mm = 17 mm approx 20 mm

two identical conducting rods are first connected independently to  two vessels, one containing water at 100°C and the other containing ice at 0°C. In the second case, the rods are joined end to end connected to the same vessels. Let M1 and M2 g/s be the rate of melting of ice in the two cases respectively, the ratio M1/M2 is

(1) 1:2

(2) 2:1

(3) 4:1

(4) 1:4

Asked By: HIMANSHU MITTAL 1 year ago

in first case rods are taken in parellel so net length and area will be l and 2A with conductivity coefficient K

similarly in second case rods are taken in series so net length and area will be 2l and A with conductivity coefficient K

now use H = KA(θ1- θ2)/L and  H = dQ/dt = mL/t     L is latent heat which is fixed in both the cases

Three discs A,B and C having radii 2m, 4m and 6m respectively are coated with carbon black on their outer surfaces. the wavelenghts corresponding to maximum intensity are 300 nm, 400nm and 500 nm respectively. if the power radiated by them are Qa, Qb and Qc respectively then

(1) Qa is maximum

(2) Qb is maximum

(3) Qc is maximum

(4) Qa= Qb = Qc

Asked By: HIMANSHU MITTAL 1 year ago

according to Wein's displacement law λT = constant

so ratio of temperatures of the three discs will be 1/3:1/4:1/5 = 20:15:12

and ratio of area of the discs = 1:4:9

now according to Stephan's law Q α  A * T4

so ratio Qa:Qb:Qc = 1*(20)4 : 4*(15)4 : 9*(12)4

on solving we will get that Qis maximum

A bullet of mass 1 gm moving with a speed of 20m/s hits an ice block of mass 990 gm kept on a frictionless floor and gets tuck in it. the amount of ice that melts, if 50% of the lost kinetic energy goes to ice will be

(1) 0.030 g

(2) 0.30 g

(3) 0.0003 g

(4) 3.0 g

Asked By: HIMANSHU MITTAL 1 year ago

amount of energy given by bullet = 0.5 (1/2) m v2 / 4.2 cal.

and amount of energy received by the ice block = ML   here L is latent heat and M is mass of ice melted

on comparing we will get  m v2/(4*4.2) = M*80 or M = 1*400/16.8*80 = 5/16.8 = 0.30 gm

a metallic sphere having inner radius a and outer radius b has thermal conductivity k = ko(k not)/r² (a ≤ r ≤ b). the thermal resistance between inner and outer surface for radiant heat flow is

Asked By: HIMANSHU MITTAL 1 year ago

consider a sphere of radius r and thickness dr

formula used is H = KAdT/L so dT/H = L/KA or R = L/KA,  dT/H is thermal resistance

thermal resistance of layer of thickness dr is dr/K4πr2, on putting the value of K we get

dR = r2dr/4πr2k0

or dR = dr/4πk0

now integrate within the proper limits

Assuming the sun to be aspherical body of radius R at a temperature of T K, evaluate the total radiant power incident on earth, at a distance r from the sun. Take radius of earth as Ro(R not)

Asked By: HIMANSHU MITTAL 1 year ago

Total radiant power given by the sun = σAT4 = 4πR2σT4

amount received on the surface of earth = (πR02/4πr2)*4πR2σT4

A body emits radiant energy 1600Js‾¹ when it is at temperature 273 °C. if its temperature decreases to 273 K them it emits radiant energy at the rate of

(1) 0

(2) 800 Js‾¹

(3) 400 Js‾¹

(4) 100 Js‾¹

Asked By: HIMANSHU MITTAL 1 year ago

Temprature of second case is half of the temprature of first case so according to stefan's law radiant power will become 1/16 part = 100

The density of a substance decreass from 10 * 10³ kg m‾³ to 7 * 10³ kg m‾³ on heating it from 0° C to 100° C. the coefficient of linear expansion of the substance is

(1) 3 * 10‾³ °C‾¹

(2) 10‾³ °C‾¹

(3) 2 * 10‾³ °C‾¹

Asked By: HIMANSHU MITTAL 1 year agoSolved By: NIKHIL VARSHNEY

A copper cube of each side 40 cm floats on mercury. the density of copper cube is 3.2g/cc and of mercury is 13.6g/cc at 27° C. the coefficient of volume expansion of Hg and linear expansion of copper are 1.8 * 10^(-4) /°C and 3 * 10^(-6) /°C respectively. Calculate the increase in height i.e. how much block sink further when the temperature rises from 27°C to 100°C?

Asked By: HIMANSHU MITTAL 1 year ago

dipped length of the cube in first case = m/Ad  here m, A, d are mass of cube, area of the cube and density of mercury respectively

after increasing temperature dipped length in the second case = m/A(1+2αt)[d/(1+γt)]

values are m = VD = 403 3.2, A = 402, α = 3 * 10-6, d = 13.6, γ = 1.8 * 10-4, t = 73

all values are in CGS

now solve then substract 1st length from 2nd length

A thermally insulated piece of metal is heated by supplying a constant power P. Due to this, the temperature of the metal starts varying with time as T= at^1/4 + To(T not)

The heat capacity of the metal as a function of temperature is

(1) 4PT³/a^4

(2) 4P(T-To)³/a^4

(3) 4PT²/a³

(4) 4P(T - To)²/a³

Asked By: HIMANSHU MITTAL 1 year ago

P = dQ/dt = mcdT/dt

or mcdT = Pdt

or mc = Pdt/dT

or mc = Pd/dT[(T-T0)4/a4]

here mc is heat capacity

now solve

The specific heat of a substance at temperature T° C is S = at² + bt + c. the amount of heat required to raise the temperature of 'm' grams of a substance from 0° C to t° C is

(1) m( at³/3 + bt²/2 + ct )

(2) m( at³ + bt² + ct )

(3) m( at³ + bt² + ct)/2

(4)m(at³/2 + bt²/3 + ct/2)

Asked By: HIMANSHU MITTAL 1 year agoSolved By: NIKHIL VARSHNEY

Two absolute scales A and B have triple points of water defined to be 200 A and 350 B. What is the relation between Ta and Tb?

(1) Ta = Tb/2

(2) Ta = 7Tb/4

(3) Ta = 2Tb

(4) Ta = 4Tb/7

Asked By: HIMANSHU MITTAL 1 year ago

273.15 K = 200 A

and 273.15 K = 350 B

so A = 273.15 K/200 and B = 273.15 K/350

so Ta A = TbB

or Ta/T= B/A = 200/350 = 4/7

so 4th option

The absolute zero temperature is

(1) -273° C

(2) -273.15 K

(3) -273.15° F

(4) -273.15° C

Asked By: HIMANSHU MITTAL 1 year ago

it is -273.15 0

2 moles of a diatomic gas are enclosed in a vessel. when a certain amount of heat is supplied, 50% of the gas molecules get dissociated, bit there is no rise in temperature. What is the heat supplied if the temperature is T?

(1) RT

(2) RT/2

(3) 11RT/2

(4) 5RT

Asked By: HIMANSHU MITTAL 1 year ago

internal energy of 2 mole diatomic gas = 2*5/2 RT = 5RT

now after 50% disociation in monoatomic form total internal energy

of 1 mole diatomic gas = 1*5/2 RT = 2.5 RT

and that of 2 mole monoatomic = 2*3/2 RT = 3RT  ( 2 mole monoatomic gas will be formed by the dissociation of 1 mole diatomic gas)

so internal energy change = 1/2 RT

This internal energy increment will be equal to the heat provided

A gaseous mixture consists of 16g of helium  and 16g of oxygen. the ratio Cp/Cv of the mixture is

(1) 1.59

(2) 1.62

(3) 1.4

(4) 1.54

Asked By: HIMANSHU MITTAL 1 year ago

16 gms He = 4 mole,   16 gms O2= 1/2 mole

so total freedom n = [4(3) + 1/2(5)] / [4 + 1/2]  = 3.22222   here 3 and 5 are freedoms for mono and di atomic gases

so γ = 1 +  2/3.2222222 = 1.621

A vessel of volume 0.3 m³ contains helium at 20.0°C. the average kinetic energy per molecule for the gas is

(1) 6.07 * 10^(-21) J

(2) 7.3 * 10³ J

(3) 14.6 * 10³ J

(4) 12.14 * 10^(-21) J

Asked By: HIMANSHU MITTAL 1 year ago

Use the formula 3/2 kT

k is boltzmann constant = 1.38* 10-23

4 moles of an ideal monoatomic gas is mixed with 6 moles of a  non reactive diatomic ideal gas. the molar heat capacity of the  mixture at constant volume is (assume no vibration) nearly

(1) 27 J mol‾¹K‾¹

(2) 17 J mol‾¹K‾¹

(3) 7 J mol‾¹K‾¹

(4) 37 J mol‾¹K‾¹

Asked By: HIMANSHU MITTAL 1 year ago

at constant volume work done = 0

degree of freedom = 4(3) + 6(5) / 4 + 6 = 12+30/10 = 4.2   so γ = 1 + (2/4.2)

so molar heat capacity = R/(γ-1)

consider an ideal gas contained in a vessel. if the intermolecular interaction suddenly beings to act, which of the following will happen?

(1) the pressure decreases

(2) the pressure increases

(3) the pressure remain unchanged

(4) the gas collapses

Asked By: HIMANSHU MITTAL 1 year ago

if the intermolecular interaction suddenly beings to act, then the pressure increases because due to intermolecular interaction gase will work as real gas

in the previous case if north pole is brought near the mettalic ring  why the direction is reversed. we have to consider the  drn of magnetic field of magnet or not. if yes then which drn N-S or S-N.

Asked By: NIKHIL VARSHNEY 1 year ago

If observer is in the side of magnet, then in the given case form N in the ring, it will give you anticlockwise direction.

Due to this current produced magnetic field will be towards the coming magnet, and since north pole of magnet is coming towards ring so this field will oppose the motion of magnet

The south pole of a magnet is bought near a metallic ring ,the direction induced current in the ring will be?  Explain it clearly.

Asked By: NIKHIL VARSHNEY 1 year ago