Chemical and Ionic Equilibrium

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What is the ph for OH ion of NaOH
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The Henry's law constant for the solubility of N2 in air is 0.8. The number of moles of N2 from air dissoloved in 10 moles of watdr at 298K and 5 atm pressure is what
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A weak acid, HA after treatment with 20 ml of 0.1 M strong base BOH has a pH of 5. At the end poin the volume of same base required is 27 ml. What is the Kof acid?

Asked By: MRUNMAYEE R GAIKWAD 8 Month ago
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specific heat of a metal is 0.031cal/degree.gram its equivalent weight is 103.6.calculate its exact atomic weight of metal

Asked By: CHANDRESH DHAR DUBEY 8 Month ago
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can pH >7 and pOH<7?

 

Asked By: NEHA VISHWAS GURAV 9 Month ago
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Degree when a small amount of HCl is added to a buffer solution of acetic acid and sodium acetate

(i) pH increases

(ii) [H+] decreases

(iii) Dissociation of acetic acid decreases

Asked By: SWATI KAPOOR 1 year agoSolved By: SARIKA
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If ionic product of water is Kw = 10-6 at 4°C, then a solution with pH = 7.5 at 4°C will

(i) turns blue litmus red 

(ii) turns red litmus blue

(ii) Be neutral to litmus

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

question is not appropriate because for given Kw , [H+] will be 10-3 and max. pH will be 6 and the question is asking about a solution of pH 7.5 which is out of limit 

but if it is considered as a correct question then answer will be (ii)

N2 + O2 = 2NO . Equilibrium constant Kc = 2 . Degree of dissociation is

(i)  1/1-√2   (ii) 1/1+√2    (iii) 2/1-√2

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

 N2   +    O2   =    2NO 

  1                       1                       0

  1-x                    1-x                  2x

so by formula Kc = (2x)2 / (1-x)(1-x)

now solve for x

In the equilibrium SO2Cl2 = SO2 + Cl2 at 2000K and 10 atm pressure , % Cl2 = % SO2 = 40 (by volume) . Then what is the value of Kp?

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

SO2Cl2 = SO2 + Cl2

100               0           0

20                  40       40

2 atm             4 atm   4 atm

now calculate Kp 

0.2 mole of N2 and 0.6 mole of H2 react to give NH3 and 40 % of reactant mixture is decreased , according to the equation,

N2 (g) + 3H2 (g) =  2NH3 (g) at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases is

 

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

N2 (g) + 3H2 (g) =  2NH3 (g)

0.2          0.6                0

0.2-x       0.6-3x         2x

according to the given condition 4x = 0.8*40/100 = 0.32

so x = 0.08

now solve

1 mole of A , 1.5 mole of B and 2 moles of C are taken in a vessel volume one litre. At equilibrium concentration of C is 0.5 mole/L. Equilibrium constant for the reaction
A (g) + B (g) = C (g)

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

A (g) + B (g) = C (g)

  1         1.5        2

1-x      1.5-x     2+x

according to the given condition 2+x = 0.5 so x = -1.5

now calculate Kc

The Ksp for a sparingly soluble Ag2CrO4 is 4 x 10-12. The molar solubility of the salt is

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

Ag2CrO-------------> 2Ag + CrO4

s                                            0                  0

                                              2s                 s

so Ksp = (2s)2 s = 4s3

now solve   

A 0.1N solution of sodium bicarbonate has a pH value of

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

Please submit complete question, Ka should be given with percentage of ionisation

pH of 0.1 M NH4Cl solution is

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

For calculating pH of a salt, only concentration is not sufficient

pH of 102 M HCl is

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

This is a strong acid so consider 100 percent ionisation 

we get [H+] = 102

it is more than 1 so pH = 0

100 c.c. of N/10 NaOH solution is mixed with 100 c.c. of N/5 HCl solution and the whole volume is made to 1 litre. The pH of the resulting solution will be

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

mili gm eq of NaOH = NV = 10

mili gm eq of HCl = 20

total mili gm eq = 20-10 = 10 of HCl

so N = 10/200 = 0.05 

so pH = log[1/0.05]

 

1 c.c of 0.1 N HCl is added to 1 litre solution of sodium chloride. The pH of the resulting solution will be

Asked By: SWATI KAPOOR 1 year agoSolved By: SWATI KAPOOR
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When 0.1 mole of ammonia is dissolved in sufficient water to make 1 litre of solution. The solution is found to have a hydroxide ion concentration of 1.34 x 10-3 . The dissociation constant of ammonia is

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

NH3 + H2O---------------------> NH4+ + OH-

0.1                                      0           0

0.1(approx)                      1.34*10-3  1.34*10-3‚Äč

now calculate dissociation constant

Calculate the percentage ionization of 0.01 M acetic acid in 0.1 M HCl. Ka of acetic acid is 1.8 x 10-5

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

CH3COOH ----------------> CH3COO- + H+

0.01                                        0                0.1

0.01-x                                      x               0.1+x

0.1+x =0.1 for x is negligibly small

so K= x*0.1/(0.01-x)

now solve

The dissociation constant of a weak acid  HA and weak base BOH are 2 x 10-5 and 5 x 10-6 respectively. The equilibrium constant for the neutralization reaction of the two is (ignore hydrolysis of resuting salt)

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

HA + BOH ------------------>  B+ + A- + H2O

K = [B+][A-][H2O]/[HA][BOH]

  = [B+][OH-]/[BOH] *  [H+][A-]/[HA] *  [H2O]/[H+][OH-] = Kb *  Ka  /  Kw

now solve 

Which of the following increasing order of pH of 0.1 M solution of the component    (a) HCOONH4  (b) CH3COOHNH4  (c) CH3COONa (d) NH4Cl  is correct

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

(d) NH4Cl   <     (a) HCOONH4    <    (b) CH3COONH4     <      (c) CH3COONa

Which of the following molar ratio of NH3 and HCl in aqueous solution will constitute a buffer ? (a) 1 : 2 (c) 1 : 1 (b) 1 : 3 (d) 2 : 1 

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

in (d) after reaction no. of moles of NHwill be 1 and 1 mole NH4Cl will be formed so it will be a basic buffer.

In order to prepare a buffer of pH 8.26, the amount of (NH4 )2SO4 required to be mixed with 1L of 0.1M NH3 (pKb of NH= 4.74) is

Asked By: SWATI KAPOOR 1 year ago
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Solution by manish sir

NH3 + H2 ------------>  NH4+ + OH-

so Kb = [NH4+] [OH-]/[NH3][H2O]

so Kb = [NH4+]/[NH3][H+] * [H+][OH-]/[H2O]

so Kb = [NH4+]/[NH3][H+] * Kw

now take log and solve. concentration of  (NH4 )2SO4 will be double of [NH4+] 

 

if you find any problem on solving this then reply

1.0 ml of dilute solution of NaOH is added to 100 ml of a buffer of pH 4. The pH of the resulting solution 

(a) becomes 7.0          

(b) becomes 9.0

(c) becomes 3.0

(d) Remains practically unchanged

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

it is strong acidic buffer so answer is (d)

10 ml of M/200 H2SO4 is mixed with 40 ml of M/200 H2SO4. The ph of the resulting solution is

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

M of H2SO4 = 1/200

so [H+] = 2*1/200 = 1/100 = 10-2

now calculate pH

 

 

 

The pH of solution at 25°C which has twice as many hydroxide ion as in pure water at 25°C , will be

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

no of hydroxide ion in pure water = 10-7

so according to the given condition no. of hydroxide ions in solution = 2*10-7

so pOH = -log2*10-7

so pH = 14 - pOH 

The ph of 0.1 M HCN is 5.2. What is the Ka?

Asked By: SWATI KAPOOR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

HCN ------------------->  H+ + CN-

0.1                                 0          0

0.1-x                              x           x

pH = 5.2

so -log[H+] = 5.2 

solve for [H+], it will give x

then calculate Ka

 

what is the ph of the solution formed by mixing 20 ml of 0.05 M H2SO4 with 5 ml of 0.45 M NaOH at 298 k ?

Asked By: SAMREEN KOUR 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

mili eq of acid = VN = 20*0.1 = 2

mili eq of base = VN = 5*0.45 = 2.25

total milieq = 2.25-2 = 0.25 of base in 25 ml

so N = 0.25/25 = 10-2

so pOH = 2 so pH = 12

1-In the following hypothetical reaction A + 3B --------------

 2C + D, initial moles of A is twice that of B. If
at equilibrium moles of B and C are equal, % of B reacted is?
Asked By: SHWETA BHARDWAJ 1 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

     A + 3B ---------> 2C + D

     1    1/2                0     0

    1-x   1/2-3x          2x    x

according to the given condition 1/2 - 3x = 2x

                                        so 1/10 = x

so 3x = 3/10

so % = 0.3*100/0.5 = 60

when 20 g of caco3 were put into 10 litre flask and heated to 800 degree cesius, 30% of caco3 remained unreacted at equilibrium. kp for decomposition of caco3 will be 1.231 ATM    HOWWWW............PLS SOLVE THIS ....PLS PLS..........

Asked By: PRATIBHA 2 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

CaCO3     ---------->   CaO   +   CO(g)

0.2 mole                   0            0

0.06                       0.14       0.14

so Kp= p                       only CO2 is gas so its pressure is considered 

now p = 0.14*0.0821*1073/10 

now solve

Hello,

sir can someone explain to me what is ionic equilibria. And how to calculate the ph and -log c. And so on. I am really confused. Thank you.

Asked By: MARWA 2 year agoSolved By: SARIKA SHARMA
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QUES)  AMMONIA UNDERGOES SELF DISSOCIATION ACCORDING TO D Rxn

2NH3 (l) ------> NH4+ (am) + NH2-  (am)

WHERE am , STANDS FOR AMMONIATED . WHEN 1 MOL OF NH4Cl IS DISSOLVED IN 1 kg OF LIQUID AMMONIA , THE B.P. AT 760 TORR IS OBSV. AT -32.70 C ( NORMAL BOILING B.P OF NH3 (l) IS -33.40 C )

WHAT CONCLUSn  ARE REACHED ABOUT THE NATURE OF SOLn??

ANS NH4Cl IS COMPLETELY DISSOCIATED IN NH3)

Asked By: SARIKA SHARMA 2 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

boiling point elevation = (-32.7) - (-33.4) = 0.7

now according to the given data 

boiling point elevation = 1000*K(ammonia)*1/1 = 1000*0.00035 = 0.35

so i = 0.7/0.35 = 2

so 100 % dissociation

SIR , I WANT TO KNOW THAT IN THE EQUILM QUES WHY YOU TAKE MOL FRACT FOR CH3COCH3=1-1/6-1/6.WHY YOU SUB FROM 1.

Asked By: SARIKA 2 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

If we multiply mole fraction to pressure, we get the pressure exerted by the component so it is a good way to get answer. and 1 represents net sum of mole fractions of all the components. here first and second 1/6 stands for mole fraction of ethane and carbon monooxide. 

Q CH3COCH3 (g) eqm CH3CH3 +CO

  initial pressure of CH3COCH is 300 mm when eqm is setup mole fraction of CO(g) = 1/6 hence total pressure will be =?

ANS 360mm of hg .SOL =?

Asked By: SARIKA 2 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

At equilibrium mole fraction of CO = 1/6, that of CH3CH= 1/6

so mole fraction of CH3COCH3  = 1- 1/6 - 1/6 = 2/3

let the total pressure at equilibrium = p

so pressure of CH3CH3 and CO will be p/6 and p/6

and that of CH3COCH= 2p/3 

now consider the following dissociation data

CH3COCH3 ----> CH3CH3 + CO

300 mm                        0                      0                            at starting

300-x  mm                    x                       x                            at  equilibrium 

here x = p/6  (1)  and 300-x = 2p/3   (2)                                         add these equations and get the value of p

Sir can you please post a topic on ionic equilibrium ( especially for numerical solving).

Asked By: AMIT DAS 2 year ago
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Solution by manish sir

YES

very soon

what is difference between dissociatio and ionisation?

Asked By: ANUJ KUMAR YADAV 2 year ago
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Answer Strategies and trick (it will help you to solve it by yourself)

Dissociation is the reaction in which two or more than two product molecules are formed.

ex.                  PCl5   --->     PCl3  +  Cl2

whereas ionisation is the reaction in which ions are formed 

ex.               MgCl2  ---->    Mg++   +  2 Cl-

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