Question

In diamond,carbon atom occupy FCC lattice points as well as alternate tetrahedral voids.If edge length of the unit cell is 356pm,then radius of carbon atom is?

Joshi sir comment

for fcc lattice a√2 = 4r

Read 2 Solution.

a(edge length) = 356pm

in fcc radius = √3a / 4 now put value of a & on solving u vyl get d answer

Best SolutionSARIKA SHARMA 12 year ago is this solution helpfull: 31 52

blushpardon use r= √2a / 4 . make correction it is not √3

SARIKA SHARMA 12 year ago is this solution helpfull: 19 57

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